Cambridge IGCSE Mathematics Practice Paper Notes

Cambridge IGCSE Mathematics Practice Paper

General Information

  • Duration: 1 hour 30 minutes

  • Total Marks: 100

  • Instructions:

    • Answer all questions.

    • Show workings in the space provided.

    • Write the final answer on the line labeled "Answer:"

    • Calculators are permitted only on questions marked "Calculator Allowed."

    • Marks are awarded for the method as well as the final answer.

  • Topics Covered: Number, Algebra, Functions, Coordinate Geometry, Geometry.

Section 1: Number (20 marks)

Q1 (3 marks)

Express 72 as a product of its prime factors.

Q2 (3 marks)

Express 0.00045 in standard form.

Standard form is expressed as a×10ba \times 10^b, where 1 \leq a < 10 and b is an integer.

Q3 (3 marks)

Calculate the value of 53×515^3 \times 5^{-1}.

Use the rule am×an=am+na^m \times a^n = a^{m+n}.

Q4 (3 marks)

Find the highest common factor (HCF) and the least common multiple (LCM) of 12 and 18.

  • HCF: The largest number that divides both 12 and 18.

  • LCM: The smallest number that is a multiple of both 12 and 18.

Q5 (4 marks)

A number is increased by 25% and then decreased by 20%. Determine the net percentage change.

Let the number be xx. Increasing by 25% gives x+0.25x=1.25xx + 0.25x = 1.25x. Decreasing the result by 20% gives 1.25x0.20(1.25x)=1.25x0.25x=x1.25x - 0.20(1.25x) = 1.25x - 0.25x = x.

Q6 (4 marks)

If 60 is 75% of a number, find the number.

Let the number be xx. Then 0.75x=600.75x = 60.

Section 2: Algebra (20 marks)

Q7 (3 marks)

Solve for xx: 3x7=2x+53x - 7 = 2x + 5.

Q8 (3 marks)

Factorise x29x^2 - 9.

This is a difference of squares: a2b2=(ab)(a+b)a^2 - b^2 = (a - b)(a + b).

Q9 (3 marks)

Expand and simplify (2x+3)(x4)(2x + 3)(x - 4).

Use the distributive property (FOIL method).

Q10 (3 marks)

Solve the quadratic equation x25x+6=0x^2 - 5x + 6 = 0.

Factorise the quadratic equation or use the quadratic formula: x=b±b24ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} for ax2+bx+c=0ax^2 + bx + c = 0.

Q11 (4 marks)

Solve the simultaneous equations:

x+y=10x + y = 10
xy=2x - y = 2

Solve for xx and yy.

Q12 (4 marks)

If a=b+3a = b + 3 and 2a4b=62a - 4b = 6, find aa and bb.

Substitute the first equation into the second equation to solve for bb.

Section 3: Functions (20 marks)

Q13 (3 marks)

Given f(x)=2x+1f(x) = 2x + 1, evaluate f(5)f(5).

Substitute x=5x = 5 into the function.

Q14 (3 marks)

For g(x)=x24g(x) = x^2 - 4, compute g(3)g(3).

Substitute x=3x = 3 into the function.

Q15 (3 marks)

Find xx for which f(x)=0f(x) = 0, where f(x)=2x+1f(x) = 2x + 1.

Solve 2x+1=02x + 1 = 0 for xx.

Q16 (3 marks)

Write the function h(x)=3x2h(x) = 3x - 2 in function notation and state its slope and y-intercept.

  • Slope: The coefficient of xx.

  • y-intercept: The value of h(x)h(x) when x=0x = 0.

Q17 (4 marks)

If f(x)=x2f(x) = x^2 and g(x)=x+3g(x) = x + 3, find (fg)(2)(f \circ g)(2).

(fg)(x)=f(g(x))(f \circ g)(x) = f(g(x)). First, find g(2)g(2), and then find f(g(2))f(g(2)).

Section 4: Coordinate Geometry (20 marks)

Q19 (3 marks, Calculator Allowed)

Find the gradient of the line through (1,2)(1, 2) and (4,8)(4, 8).

Gradient m=y<em>2y</em>1x<em>2x</em>1m = \frac{y<em>2 - y</em>1}{x<em>2 - x</em>1}.

Q20 (3 marks, Calculator Allowed)

Find the equation of the line through (1,2)(1, 2) with a gradient of 3.

Use the point-slope form: yy<em>1=m(xx</em>1)y - y<em>1 = m(x - x</em>1), where mm is the gradient and (x<em>1,y</em>1)(x<em>1, y</em>1) is the point.

Q21 (3 marks)

Find the midpoint of the segment joining (3,4)(3, 4) and (7,10)(7, 10).

Midpoint =(x<em>1+x</em>22,y<em>1+y</em>22)= (\frac{x<em>1 + x</em>2}{2}, \frac{y<em>1 + y</em>2}{2}).

Q22 (3 marks)

Calculate the distance between (2, -1) and (-3, 4).

Distance d=(x<em>2x</em>1)2+(y<em>2y</em>1)2d = \sqrt{(x<em>2 - x</em>1)^2 + (y<em>2 - y</em>1)^2}.

Q23 (4 marks)

The line y=2x1y = 2x - 1 intersects the x-axis at A. Find the coordinates of A.

The x-axis is where y=0y = 0. Set y=0y = 0 and solve for xx.

Q24 (4 marks)

Given that the line y=mx+cy = mx + c passes through (2,3)(2, 3) and (4,7)(4, 7), determine mm and cc.

Substitute the points into the equation to form two simultaneous equations and solve for mm and cc. Solve using substitution or elimination. mm is the gradient and cc is the y-intercept.