Principles of Engineering - Simple Machines: Screw Calculations

System Overview and Specifications

  • System Description:

    • A 7/16 in7/16\,\text{in} nut driver with a 1 1/2 in1\,1/2\,\text{in} (1.5 in1.5\,\text{in}) diameter handle is used to turn and install a 1/4”−20 UNC1/4\text{''}-20\,\text{UNC} bolt into a robotic arm assembly.

  • Key Hardware Components and Dimensions:

    • Tool: Nut driver (7/16 in7/16\,\text{in} size).

    • Handle Diameter (dd): 1.5 in1.5\,\text{in} (1 1/2 in1\,1/2\,\text{in}).

    • Handle Radius (rr): r=d2=1.5 in2=0.75 inr = \frac{d}{2} = \frac{1.5\,\text{in}}{2} = 0.75\,\text{in}.

    • Fastener Specification: 1/4”−20 UNC1/4\text{''}-20\,\text{UNC}.

    • Major Diameter: 1/4 in1/4\,\text{in} (0.25 in0.25\,\text{in}).

    • Threads Per Inch (TPI): 20 threads/in20\,\text{threads/in}.

    • Thread Series: Unified National Coarse (UNC).

Circumference of Effort Application

  • Concept:

    • The effort distance for a simple machine screw system driven by a handle is equal to the circular distance traveled by the outer effort boundary (handle radius) during one complete revolution (360∘360^{\circ}).

  • Formula:

    • C=2πrC = 2\pi r

    • Where:

    • CC = Circumference of effort circle

    • rr = Radius of handle (0.75 in0.75\,\text{in})

  • Calculation and Substitution:

    • C=2×π×0.75 inC = 2 \times \pi \times 0.75\,\text{in}

    • C=4.71239 inC = 4.71239\,\text{in}

  • Final Answer:

    • C=4.71 inC = 4.71\,\text{in}

Pitch Determination

  • Concept:

    • Pitch (PP) is defined as the distance measured parallel to the axis of a screw between corresponding points on adjacent thread forms. It represents the linear distance advanced by the screw in a single full turn.

  • Formula:

    • P=1TPIP = \frac{1}{\text{TPI}}

    • Where:

    • PP = Thread pitch

    • TPI\text{TPI} = Threads per inch (20 threads/in20\,\text{threads/in})

  • Calculation and Substitution:

    • P=120 threads/inP = \frac{1}{20\,\text{threads/in}}

    • P=0.05 inP = 0.05\,\text{in}

  • Final Answer:

    • P=0.05 inP = 0.05\,\text{in}

Ideal Mechanical Advantage (IMA)

  • Concept:

    • The Ideal Mechanical Advantage (IMA) of a screw system is the theoretical force multiplication factor calculated as the ratio of effort distance (circumference per turn, CC) to resistance distance (pitch per turn, PP).

  • Formula:

    • IMA=CP\text{IMA} = \frac{C}{P}

    • Where:

    • CC = Effort distance per revolution (4.71 in4.71\,\text{in})

    • PP = Resistance distance per revolution (0.05 in0.05\,\text{in})

  • Calculation and Substitution:

    • IMA=4.71 in0.05 in\text{IMA} = \frac{4.71\,\text{in}}{0.05\,\text{in}}

    • IMA=94.2\text{IMA} = 94.2

  • Final Answer:

    • IMA=94.2\text{IMA} = 94.2

Theoretical Resistance Force Output

  • Concept:

    • In an ideal system operating without frictional losses, IMA=FRFE\text{IMA} = \frac{F_R}{F_E}. The theoretical load or resistance force (FRF_R) that can be overcome is equal to the applied effort force (FEF_E) multiplied by the ideal mechanical advantage.

  • Formula:

    • IMA=FRFE  ⟹  FR=FE×IMA\text{IMA} = \frac{F_R}{F_E} \implies F_R = F_E \times \text{IMA}

    • Where:

    • FEF_E = Applied effort force (5 lb5\,\text{lb})

    • FRF_R = Output resistance force overcome

    • IMA\text{IMA} = Ideal mechanical advantage (94.294.2)

  • Calculation and Substitution:

    • FR=5 lb×94.2F_R = 5\,\text{lb} \times 94.2

    • FR=471 lbF_R = 471\,\text{lb}

  • Final Answer:

    • FR=471 lbF_R = 471\,\text{lb}