Concentration of Hypobromite Solution Calculation

Chemical Reaction of Ammonia and Hypobromite

• Chemical Reaction: The reaction between ammonia (NH₃) and hypobromite (OBR) can be represented as follows:

  • 2 NH3 + 3 OBr^- \rightarrow N2 + 3 Br^- + 3 H_2O

• Molar Masses:

  • Ammonia (NH₃): 17.031 g/mol
  • Hypobromite (OBR): Not provided, but relevant data can be inferred from the reaction.

Practical Example of Calculation

• Given data:

  • Mass of ammonia (NH₃): 0.547 g
  • Volume of hypobromite solution: 26.4 mL

• Objective: Calculate the concentration of hypobromite solution in molarity (M).

Step 1: Convert mass of ammonia to moles

• Use the molar mass of ammonia to find the number of moles:
  • Formula:
    ext{Moles of NH}_3 = \frac{\text{mass (g)}}{\text{molar mass (g/mol)}}
  • Calculation:
    \text{Moles of NH}_3 = \frac{0.547 \text{ g}}{17.031 \text{ g/mol}} \approx 0.0322 ext{ moles}

Step 2: Determine moles of hypobromite reacted

• According to the balanced chemical reaction:
  • For every 2 moles of NH₃, 3 moles of hypobromite (OBR) are required:
  • Thus, molar ratio:
    \text{Moles of OBr} = \frac{3}{2} \times \text{Moles of NH}_3
  • Calculation:
    \text{Moles of OBr} = \frac{3}{2} \times 0.0322 ext{ moles} \approx 0.0483 ext{ moles}

Step 3: Find concentration of hypobromite solution

• Concentration is defined as:
  • Formula:
    ext{Concentration (M)} = \frac{\text{moles of solute}}{\text{volume of solution (L)}}
  • Convert volume from mL to L:
  • Volume = 26.4 mL = 0.0264 L
  • Calculation:
    ext{Concentration (M)} = \frac{0.0483 \text{ moles}}{0.0264 \text{ L}} \approx 1.83 ext{ M}

Results

• Concentration of hypobromite solution: 1.83 M

Conclusion

• This calculation demonstrates the stoichiometric relationship in the chemical reaction between ammonia and hypobromite, and how to determine the concentration of a reactant based on the mass of one component and the volume of another.