Quadratic Functions and Equations

Quadratic Equations

A quadratic equation is expressed in the form ax2+bx+c=0ax^2 + bx + c = 0, where:

  • aa is the quadratic coefficient.

  • bb is the linear coefficient.

  • cc is the constant term.

Sum and Product of Roots

For a quadratic equation ax2+bx+c=0ax^2 + bx + c = 0, the sum and product of the roots can be determined using the following formulas:

  • Sum of roots: ba-\frac{b}{a}

  • Product of roots: ca\frac{c}{a}

Example Problems

  1. Problem: What is the sum of all values of mm that satisfy 2m216m+8=02m^2 - 16m + 8 = 0?

    • Solution:

      • Here, a=2a = 2 and b=16b = -16.

      • Sum of roots = 162=162=8-\frac{-16}{2} = \frac{16}{2} = 8

  2. Problem: What is the sum of the solutions to the equation x214x+40=2x+1x^2 - 14x + 40 = 2x + 1?

    • Solution:

      • First, rewrite the equation in standard quadratic form: x214x+402x1=0x216x+39=0x^2 - 14x + 40 - 2x - 1 = 0 \Rightarrow x^2 - 16x + 39 = 0

      • Here, a=1a = 1 and b=16b = -16.

      • Sum of roots = 161=16-\frac{-16}{1} = 16

  3. Problem: What is the sum of the roots of the equation x33x+52=0x^3 - 3x + 52 = 0?

    • Solution:

      • rewrite the equation as x3+0x23x+52=0x^3 + 0x^2 - 3x + 52 = 0

      • Here the coefficient of x2x^2 is 0, so the sum of the roots is: 01=0-\frac{0}{1} = 0

  4. Problem: What is the product of the solutions to the equation x(x2)=35x(x - 2) = 35?

    • Solution:

      • First, rewrite the equation in standard quadratic form: x22x35=0x^2 - 2x - 35 = 0

      • Here, a=1a = 1 and c=35c = -35.

      • Product of roots = 351=35\frac{-35}{1} = -35

  5. Problem: What is the product of the two solutions of the equation x25x+8=2x^2 - 5x + 8 = 2?

    • Solution:

      • First, rewrite the equation in standard quadratic form: x25x+82=0x25x+6=0x^2 - 5x + 8 - 2 = 0 \Rightarrow x^2 - 5x + 6 = 0

        • Here, a=1a = 1 and c=6c = 6.

      • Product of roots = 61=6\frac{6}{1} = 6

  6. Problem: What is the product of the solutions of 2x24=4x2+62x^2 - 4 = 4x^2 + 6?

    • Solution:

      • Rewrite the equation: 2x24x246=02x210=02x^2 - 4x^2 - 4 - 6 = 0 \Rightarrow -2x^2 - 10 = 0

      • Here, a=2a = -2 and c=10c = -10.

      • Product of roots = 102=3\frac{-10}{-2} = -3

Factors and Roots/Solutions

  • Factors: (x3)(x - 3) and (x+2)(x + 2)

  • Roots/Solutions: x=3x = 3 and x=2x = -2

  • X-intercepts: where y=0y = 0

Problems Involving Factors and Roots

  1. Problem: If (x+1)(x + 1) is a factor of x35x2+kx+2x^3 - 5x^2 + kx + 2, then what is the value of kk?

    • Solution:

      • Since (x+1)(x + 1) is a factor, x=1x = -1 is a root. Substitute x=1x = -1 into the equation:
        (1)35(1)2+k(1)+2=0(-1)^3 - 5(-1)^2 + k(-1) + 2 = 0
        15k+2=0-1 - 5 - k + 2 = 0
        4k=0-4 - k = 0
        k=4k = -4

  2. Problem: If both (x1)(x - 1) and (x2)(x - 2) are factors of x33x2+2x4bx^3 - 3x^2 + 2x - 4b, then what must bb be?

    • Solution:

      • Since (x1)(x - 1) is a factor, x=1x = 1 is a root. Substitute x=1x = 1 into the equation:
        (1)33(1)2+2(1)4b=0(1)^3 - 3(1)^2 + 2(1) - 4b = 0
        13+24b=01 - 3 + 2 - 4b = 0
        04b=00 - 4b = 0
        b=0b = 0

Constant Determination

  1. Problem: Given the function P(x)=x211x+kP(x) = x^2 - 11x + k, where kk is a constant. If 2 is a zero of the function, what is the value of kk?

    • Solution:

      • Since 2 is a zero, P(2)=0P(2) = 0. Substitute x=2x = 2 into the equation:
        (2)211(2)+k=0(2)^2 - 11(2) + k = 0
        422+k=04 - 22 + k = 0
        18+k=0-18 + k = 0
        k=18k = 18

  2. Problem: The function h(x)=x2ax3h(x) = x^2 - ax - 3 has zeros at x=3x = 3 and x=1x = -1. What is the value of aa?

    • Solution:

      • Since 3 is a zero, h(3)=0h(3) = 0. Substitute x=3x = 3 into the equation:
        0=(3)23a30 = (3)^2 - 3a - 3
        93a3=09 - 3a - 3 = 0
        63a=06 - 3a = 0
        3a=6-3a = -6
        a=2a = 2

Quadratic Functions

General Forms

  1. Y-intercept Form:

    • f(x)=ax2+bx+cf(x) = ax^2 + bx + c

    • Y-intercept: (0,c)(0, c)

  2. Factored Form (X-intercept Form):

    • f(x)=a(xx<em>1)(xx</em>2)f(x) = a(x - x<em>1)(x - x</em>2)

    • X-intercepts: (x<em>1,0)(x<em>1, 0), (x</em>2,0)(x</em>2, 0)

  3. Vertex Form:

    • f(x)=a(xh)2+kf(x) = a(x - h)^2 + k

    • Vertex: (h,k)(h, k)

Key Concepts

  • Graphs: Parabolas that open upwards or downwards.

  • Vertex: The minimum or maximum point of the parabola.

  • Axis of Symmetry: A vertical line that passes through the vertex, dividing the parabola into two symmetrical halves. Its equation is x=hx = h.

  • Range: The set of all possible output values (y-values) of the function.

Vertex Calculation

  • The x-coordinate (abscissa) of the vertex is given by: h=b2ah = -\frac{b}{2a}

Example Problems

  1. For the quadratic function f(x)=3x2+6x9f(x) = 3x^2 + 6x - 9

    • The y-intercept is (0,9)(0, -9)

    • The x-coordinate of the vertex is: x=62(3)=1x = -\frac{6}{2(3)} = -1

  2. Problem: What is the abscissa of the vertex of the function f(x)=3x218x+4f(x) = 3x^2 - 18x + 4?

    • Solution:

      • Using the formula h=b2ah = -\frac{b}{2a}:
        h=182(3)=186=3h = -\frac{-18}{2(3)} = \frac{18}{6} = 3

  3. Problem: For the function f(x)=5x22x8f(x) = 5x^2 - 2x - 8, for what value of xx does f(x)f(x) obtain its minimum value?

    • Solution:

      • Using the formula h=b2ah = -\frac{b}{2a}:
        h=22(5)=210=15h = -\frac{-2}{2(5)} = \frac{2}{10} = \frac{1}{5}

  4. Problem: Given f(x)=2x2+ax1f(x) = 2x^2 + ax - 1. What is the value of aa if the axis of symmetry of the graph of ff is equal to 2.5-2.5?

    • Solution: The axis of symmetry is x=b2ax = -\frac{b}{2a}, so:

      • 2.5=a2(2)-2.5 = -\frac{a}{2(2)}

      • 2.5=a4-2.5 = -\frac{a}{4}

      • a=10a = 10

  5. Problem: The graph of the function f(x)=2x2+8x6f(x) = -2x^2 + 8x - 6 is a parabola. If point S(h,k)S(h, k) is the vertex of the parabola, what is the value of h+kh + k?

    • Solution:

      • First, find hh (the x-coordinate of the vertex):

        • h=b2a=82(2)=2h = -\frac{b}{2a} = -\frac{8}{2(-2)} = 2

      • Next, find kk (the y-coordinate of the vertex) by substituting hh into the function:

        • k=f(2)=2(2)2+8(2)6=8+166=2k = f(2) = -2(2)^2 + 8(2) - 6 = -8 + 16 - 6 = 2

      • Finally, find h+kh + k:

        • h+k=2+2=4h + k = 2 + 2 = 4

  6. If f(x)=ax2+bx+cf(x) = ax^2 + bx + c is concave downward, which of the following must be true?

    • (A) a < 0

  7. For the equation y=2x2+10x+12y = 2x^2 + 10x + 12. What is the value of k if the graph crosses the y-axis at the point (0,k)(0, k)?

  • By substituting x=0x = 0:

    • y=2(0)2+10(0)+12y = 2(0)^2 + 10(0) + 12

    • y=12y = 12

Identifying Equations from Graphs

  1. X-intercept Form:

    • Given x-intercepts at 1/51/5 and 3/2-3/2, the equation could be: y=(5x1)(2x+3)y = (5x - 1)(2x + 3)

  2. Problem: The graph of the equation y=7x228x+21y = 7x^2 - 28x + 21 is a parabola in the xy-plane. In which of the following equivalent forms of the equation do the x-intercepts of the parabola appear as constants or coefficients?

    • Solution:

      • The x-intercepts appear as constants or coefficients in the factored form:

        • y=7(x1)(x3)y = 7(x - 1)(x - 3)

Determining Equation from Graph

  1. Problem: Which of the following is an equivalent form of the equation y=x26x+5y = x^2 - 6x + 5 that displays the x-intercepts of the parabola as constants?

  • Solution:

    • The Factored form or X-intercept form displays the x-intercepts

    • y=(x1)(x5)y = (x - 1)(x - 5)

  1. October 2020 EST Section 3

  • The graph of the function f(x)=2(x+2)(x6)f(x) = 2(x + 2) (x - 6) is a parabola. If the line x=kx=k is the axis of symmetry of the parabola, what is the value of kk?

    • x1=2x1=-2

    • x2=6x2=6

    • h=(62)/2=2h = (6-2)/2 = 2

  1. March 2021 EST Section 4

  • Consider the function f defined by f(x)=2(x3)(x+2)f(x)=2(x-3)(x+2). What is the ordinate of the vertex of function f?

  1. Official test 7 sec 3

  • The function f is defined by f(x)=(x+3)(x+1)f(x) = (x+3)(x+1). The graph of ƒ in the xy-plane is a parabola. Which of the following intervals contains the x-coordinate of the vertex of the graph of ƒ ?

    • h=31=2h = -3 - 1 = -2

  1. Panda test 6 sec 4

  • 30 y = (2x-1)(2x-11)

  1. December 2020 EST Section 3

  • 14.The graph of the function f in the xy-plane above is a parabola. Which of the following expressions defines f while showing the x-intercepts as constants or coefficients?

    • f(x) = x(x+2)

Vertex Form

  • f(x)=a(xh)2+kf(x) = a(x - h)^2 + k

  • Vertex = (h,k)(h, k)

Problem:
y=12(x3)2+ay=-\frac{1}{2}(x-3)^2+a

Ethical implications

none