PEMDAS Order of Operations Practice

Order of Operations Framework (PEMDAS)

  • The order of operations defines the standardized procedural hierarchy for evaluating mathematical expressions, abbreviated as PEMDAS:

    • P (Parentheses and Grouping Symbols): Operations enclosed in grouping symbols must be evaluated first from the innermost set outward. Grouping symbols include:

    • Standard parentheses: ( )( \, )

    • Square brackets: [ ][ \, ]

    • Absolute value bars: ∣ ∣| \, |, which also require taking the non-negative magnitude of the evaluated interior expression.

    • Fraction bars: A horizontal fraction bar acts as an implicit grouping symbol, requiring complete evaluation of the entire numerator and the entire denominator before performing division.

    • E (Exponents): Powers, exponents, and roots are evaluated immediately after all operations inside grouping symbols are completed.

    • Base sign distinction: (−a)n(-a)^n includes the negative sign in the exponentiation, whereas −an-a^n evaluates the power first and then applies the negative sign.

    • Even powers of negative bases yield positive values: (−a)2k>0(-a)^{2k} > 0.

    • Odd powers of negative bases yield negative values: (−a)2k+1<0(-a)^{2k+1} < 0.

    • Zero exponent rule: Any non-zero real number raised to the zero power equals one (x0=1x^0 = 1 for x≠0x \neq 0).

  • MD (Multiplication and Division): Evaluated from left to right in the order they appear. Neither multiplication nor division takes inherent priority over the other.

  • AS (Addition and Subtraction): Evaluated from left to right in the order they appear. Subtraction is mathematically equivalent to adding the opposite (additive inverse): a−b=a+(−b)a - b = a + (-b).

Rules for Signed Integer Operations

  • Integer Addition:

    • Summing integers with the same sign: Add absolute values and preserve the common sign (−a+(−b)=−(a+b)-a + (-b) = -(a + b)).

    • Summing integers with opposite signs: Subtract the smaller absolute value from the larger absolute value and retain the sign of the number with the larger absolute value.

  • Integer Subtraction:

    • Transform subtraction into addition of the opposite: a−(−b)=a+ba - (-b) = a + b and a−b=a+(−b)a - b = a + (-b).

  • Integer Multiplication and Division:

    • Product or quotient of two numbers with identical signs is positive: (+)×(+)=(+)(+) \times (+) = (+) and (−)×(−)=(+)(-) \times (-) = (+).

    • Product or quotient of two numbers with opposing signs is negative: (+)×(−)=(−)(+) \times (-) = (-) and (−)×(+)=(−)(-) \times (+) = (-).

    • When multiplying more than two integers, sign parity depends solely on the number of negative factors:

    • An even count of negative factors yields a positive product.

    • An odd count of negative factors yields a negative product.

Multi-Step Algebraic Evaluations

  • Evaluation of −2(−15+8)2-2(-15 + 8)^2:

    • Step 1 (Parentheses): Evaluate the expression inside the parentheses:     −15+8=−7-15 + 8 = -7

    • Step 2: Substitute the result back into the expression:     −2(−7)2-2(-7)^2

    • Step 3 (Exponents): Evaluate the squared negative term:     (−7)2=49(-7)^2 = 49

    • Step 4 (Multiplication): Multiply the leading coefficient by the squared value:     −2(49)=−98-2(49) = -98

    • Final value: −98-98

  • Evaluation of −12−3⋅8+(−1)-12 - 3 \cdot 8 + (-1) (Problem j):

    • Step 1 (Multiplication): Perform multiplication prior to addition or subtraction:     3⋅8=243 \cdot 8 = 24

    • Step 2: Rewrite the expression as additions of signed terms:     −12−24+(−1)=−12+(−24)+(−1)-12 - 24 + (-1) = -12 + (-24) + (-1)

    • Step 3 (Addition Left-to-Right): Combine the first two negative terms:     −12+(−24)=−36-12 + (-24) = -36

    • Step 4 (Final Addition): Add the remaining term:     −36+(−1)=−37-36 + (-1) = -37

    • Final value: −37-37

  • Evaluation of −10⋅(−5)2−(−15)-10 \cdot (-5)^2 - (-15) (Problem l):

    • Step 1 (Exponents): Compute the exponent value:     (−5)2=25(-5)^2 = 25

    • Step 2 (Subtraction of Negative): Convert −(−15)- (-15) to addition of a positive integer:     −(−15)=+15- (-15) = + 15

    • Step 3 (Multiplication): Compute the product of the coefficient and the squared base:     −10×25=−250-10 \times 25 = -250

    • Step 4 (Addition): Combine the terms:     −250+15=−235-250 + 15 = -235

    • Final value: −235-235

  • Evaluation of −78−19−32+(−17)-78 - 19 - 32 + (-17) (Problem m):

    • Step 1: Convert all subtractions into addition of negative integers:     −78+(−19)+(−32)+(−17)-78 + (-19) + (-32) + (-17)

    • Step 2: Group and sum terms pairwise:     −78+(−19)=−97-78 + (-19) = -97     −32+(−17)=−49-32 + (-17) = -49

    • Step 3: Combine intermediate sums:     −97+(−49)=−146-97 + (-49) = -146

    • Final value: −146-146

  • Evaluation with Absolute Value: 2⋅∣8(−2)+(−4)∣2 \cdot |8(-2) + (-4)| (Problem d):

    • Step 1 (Interior Multiplication): Multiply within the absolute value bars:     8(−2)=−168(-2) = -16

    • Step 2 (Interior Addition): Add the terms inside the absolute value:     −16+(−4)=−20-16 + (-4) = -20

    • Step 3 (Absolute Value Evaluation): Compute the magnitude:     ∣−20∣=20|-20| = 20

    • Step 4 (Exterior Multiplication): Multiply by the external factor:     2⋅20=402 \cdot 20 = 40

    • Final value: 4040

  • Evaluation with Nested Brackets: [(−15+12)3+(−11)]÷(−2)[(-15 + 12)^3 + (-11)] \div (-2) (Problem c):

    • Step 1 (Innermost Parentheses): Evaluate the addition within the parentheses:     −15+12=−3-15 + 12 = -3

    • Step 2 (Exponent within Brackets): Raise the result to the third power:     (−3)3=−27(-3)^3 = -27

    • Step 3 (Bracket Evaluation): Add the remaining term inside the brackets:     [−27+(−11)]=−38[-27 + (-11)] = -38

    • Step 4 (Division): Divide the bracketed result by −2-2:     −38÷(−2)=19-38 \div (-2) = 19

    • Final value: 1919

Multi-Factor Integer Products

  • Evaluation of (−5)(−2)(2)(−1)(-5)(-2)(2)(-1) (Problem e):

    • Negative factor tally: 3 negative factors (odd count), indicating a negative final product.

    • Step 1: Multiply the first pair of integers:     (−5)(−2)=10(-5)(-2) = 10

    • Step 2: Multiply the second pair of integers:     (2)(−1)=−2(2)(-1) = -2

    • Step 3: Multiply intermediate products:     10×(−2)=−2010 \times (-2) = -20

    • Final value: −20-20

  • Evaluation of (−3)(−4)(−2)(6)(-3)(-4)(-2)(6) (Problem f):

    • Negative factor tally: 3 negative factors (odd count), indicating a negative final product.

    • Step 1: Multiply the first two factors:     (−3)(−4)=12(-3)(-4) = 12

    • Step 2: Multiply the last two factors:     (−2)(6)=−12(-2)(6) = -12

    • Step 3: Multiply intermediate products:     12⋅(−12)=−14412 \cdot (-12) = -144

    • Final value: −144-144

Rational Expressions with Multi-Term Numerators and Denominators

  • Evaluation of 20−3(−2)−2−1+20\frac{20 - 3(-2)}{-2 - 1 + 2^0} (Problem k):

    • Numerator Analysis (Num):

    • Expression: 20−3(−2)20 - 3(-2)

    • Convert to addition: 20+(−3)(−2)20 + (-3)(-2)

    • Perform multiplication: (−3)(−2)=6(-3)(-2) = 6

    • Add terms: 20+6=2620 + 6 = 26

    • Denominator Analysis (Denom):

    • Expression: −2−1+20-2 - 1 + 2^0

    • Apply zero exponent rule: 20=12^0 = 1

    • Convert to addition: −2+(−1)+1-2 + (-1) + 1

    • Add from left to right: −2+(−1)=−3-2 + (-1) = -3, then −3+1=−2-3 + 1 = -2

    • Division of Numerator by Denominator:     26−2=−13\frac{26}{-2} = -13

    • Final value: −13-13

  • Evaluation of (−2)(16)(−1)−4\frac{(-2)(16)(-1)}{-4} (Problem g):

    • Step 1 (Numerator Product): Compute numerator terms:     (−2)(16)=−32(-2)(16) = -32     −32(−1)=32-32(-1) = 32

    • Step 2 (Denominator): Denominator is −4-4.

    • Step 3 (Division): Compute quotient of positive numerator and negative denominator:     32−4=−8\frac{32}{-4} = -8

    • Final value: −8-8

  • Evaluation of (−2)(9)−3(−1)\frac{(-2)(9)}{-3(-1)} (Problem h):

    • Step 1 (Numerator): Multiply terms in numerator:     (−2)(9)=−18(-2)(9) = -18

    • Step 2 (Denominator): Multiply terms in denominator:     −3(−1)=3-3(-1) = 3

    • Step 3 (Division): Divide numerator by denominator:     −183=−6\frac{-18}{3} = -6

    • Final value: −6-6

  • Evaluation of (−8)2−(−12)+(−1)5−5\frac{(-8)^2 - (-12) + (-1)^5}{-5} (Problem b):

    • Step 1 (Numerator Exponents):     (−8)2=64(-8)^2 = 64     (−1)5=−1(-1)^5 = -1

    • Step 2 (Numerator Signs and Addition):

    • Subtraction of negative twelve: −(−12)=+12- (-12) = + 12

    • Numerator expression: 64+12+(−1)64 + 12 + (-1)

    • Left-to-right addition: 64+12=7664 + 12 = 76, then 76+(−1)=7576 + (-1) = 75

    • Step 3 (Division by Denominator):     75−5=−15\frac{75}{-5} = -15

    • Final value: −15-15