Arithmetic Sequences and Series — Quick Reference

Understand Arithmetic Sequences

  • An arithmetic sequence has a constant difference between consecutive terms, called the common difference dd.
  • General term (explicit form): a<em>n=a</em>1+(n1)da<em>n = a</em>1 + (n-1)d where a1a_1 is the first term and nNn\in\mathbb{N}.
  • Recursive form: a<em>n=a</em>n1+da<em>n = a</em>{n-1} + d with initial term a1a_1.
  • Distinction: explicit gives any term directly; recursive uses the previous term.

Write a Function for an Arithmetic Sequence

  • Recursive function form: f(1)=a1,f(n)=f(n1)+d.f(1) = a_1\,,\quad f(n) = f(n-1) + d\,.
  • Explicit function form: f(n)=a1+(n1)d.f(n) = a_1 + (n-1)d\,.
  • Example structure: a term is defined by the previous term plus dd (with an initial condition).

Examples (conceptual)

  • Sequence 3, 8, 13, 18, 23, ⋯
    • a<em>1=3, d=5; a</em>n=3+(n1)5a<em>1 = 3,\ d = 5\,;\ a</em>n = 3 + (n-1)\cdot 5
    • Next term: a6=3+55=28a_6 = 3 + 5\cdot 5 = 28
  • Sequence 4, 7, 10, 13, 16, ⋯
    • a<em>1=4, d=3  a</em>n=4+(n1)3a<em>1 = 4,\ d = 3\; a</em>n = 4 + (n-1)\cdot 3
    • Next term: a6=4+53=19a_6 = 4 + 5\cdot 3 = 19

Translate Between Recursive and Explicit Forms

  • From recursive to explicit: a<em>n=a</em>1+(n1)da<em>n = a</em>1 + (n-1)d
  • From explicit to recursive: a<em>n=a</em>n1+d, a<em>1=a</em>1a<em>n = a</em>{n-1} + d,\ a<em>1 = a</em>1
  • Example: if a<em>2=a</em>1+0.5a<em>2 = a</em>1 + 0.5, then a<em>n=a</em>1+0.5(n1)a<em>n = a</em>1 + 0.5(n-1)

Solve Problems With Arithmetic Sequences

  • Example: Auditorium seating
    • Given a<em>1=18a<em>1 = 18, a</em>5=26a</em>5 = 26; difference per row: d=a<em>5a</em>151=26184=2d = \frac{a<em>5 - a</em>1}{5-1} = \frac{26-18}{4} = 2
    • Explicit: an=18+2(n1)a_n = 18 + 2(n-1)
    • Then a12=18+211=40a_{12} = 18 + 2\cdot 11 = 40
  • Sum of arithmetic sequence
    • Finite sum: S<em>n=n2(a</em>1+a<em>n)S<em>n = \frac{n}{2}\,(a</em>1 + a<em>n) or S</em>n=n2(2a1+(n1)d)S</em>n = \frac{n}{2}\,(2a_1 + (n-1)d)
  • Example: Sum of 1,4,7,10,131,4,7,10,13
    • a<em>1=1, d=3, a</em>5=13, n=5a<em>1 = 1,\ d = 3,\ a</em>5 = 13,\ n = 5
    • S5=52(1+13)=35S_5 = \frac{5}{2}\,(1 + 13) = 35

Sigma Notation

  • Sum of a sequence can be written as <em>i=1na</em>i\sum<em>{i=1}^{n} a</em>i where aia_i is the i-th term.
  • Replace aia_i with the explicit formula when using sigma notation.
  • Example: series 2+9+16++792 + 9 + 16 + \dots + 79
    • a<em>1=2, d=7, a</em>n=79, n=12a<em>1 = 2,\ d = 7,\ a</em>n = 79,\ n = 12
    • Explicit term: ai=2+7(i1)=7i5a_i = 2 + 7(i-1) = 7i - 5
    • Sigma form: i=112(7i5)=486\sum_{i=1}^{12} (7i - 5) = 486

Use a Finite Arithmetic Series

  • Pyramid example: 1, 2, 3, …, 10 rows (top row 1, bottom row 10)
    • a<em>1=1, a</em>10=10, d=1a<em>1 = 1,\ a</em>{10} = 10,\ d = 1
    • Sum: S10=102(1+10)=55S_{10} = \frac{10}{2}\,(1 + 10) = 55
  • Use explicit formula when you know a<em>1,a</em>n, or da<em>1, a</em>n,\text{ or }d

Concept Summary

  • Arithmetic sequences: a<em>n=a</em>1+(n1)da<em>n = a</em>1 + (n-1)d
  • Common difference: dd
  • Recursive vs Explicit representations
  • Arithmetic series (sums): S<em>n=n2(a</em>1+a<em>n)=n2(2a</em>1+(n1)d)S<em>n = \frac{n}{2}\,(a</em>1 + a<em>n) = \frac{n}{2}\,(2a</em>1 + (n-1)d)
  • Sigma notation: <em>i=1na</em>i\sum<em>{i=1}^{n} a</em>i

Do You Understand?

  • Essential Question: What is an arithmetic sequence, and how do you represent and find its terms and their sums?
  • Vocabulary: Distinguish between arithmetic sequence (terms) and arithmetic series (sum).
  • Error Analysis: A claim like 0, 1, 3, 6, 10 is not arithmetic; the differences are 1, 2, 3, 4, so the pattern is not constant.
  • Precision: How to calculate terms and sums accurately using the explicit or recursive forms.