Master Study Guide: Functions, Graphs & Transformations

Introduction and Core Concepts of Functions

  • Definition of a Function: A rule where every allowed input has exactly one output.

  • Machine Analogy: Put an input xx into the machine, the function rule acts on xx, and exactly one output yy-value comes out.

  • Key Test for Functionality:

    • One input xx cannot produce two different output yy-values.

    • Different input xx-values are permitted to produce the exact same output yy-value.

  • Vertical Line Test:

    • A visual method to determine if a graph represents yy as a function of xx.

    • If any vertical line intersects a graph at more than one point, the graph does not represent yy as a function of xx.

  • Illustrative Function Examples:

    • Function Example: y=x2y = x^2 is a function. Evaluating at x=3x = 3 yields exactly one output, y=9y = 9.

    • Non-Function Example: x=y2x = y^2 is not yy as a function of xx. Evaluating at x=4x = 4 produces two outputs, y=2y = 2 and y=2y = -2.

Function Notation and Evaluation

  • Function Notation f(x)f(x):

    • Naming Output: f(x)f(x) is another way of naming the output yy.

    • Operational Meaning: It means the function ff evaluated at xx, and does NOT mean ff times xx.

  • Substitution Rule: Whatever expression or value appears inside the parentheses replaces xx everywhere in the function rule.

  • Basic Evaluation Example:

    • Given: f(x)=2x+5f(x) = 2x + 5

    • Evaluating f(3)f(3) requires replacing every xx with 33: f(3)=2(3)+5=11f(3) = 2(3) + 5 = 11

  • Algebraic Substitution Examples:

    • Given: f(x)=x24x+1f(x) = x^2 - 4x + 1

    • Substituting aa yields: f(a)=a24a+1f(a) = a^2 - 4a + 1

    • Substituting x+hx+h yields: f(x+h)=(x+h)24(x+h)+1f(x+h) = (x+h)^2 - 4(x+h) + 1

Domain, Range, and Radical Behavior

  • Domain: The set of every possible input xx.

  • Range: The set of every possible output yy.

  • General Domain Finding Strategy:

    • Start by assuming the domain includes all real numbers (,)(-\neq, \neq).

    • Inspect the function expression for potential algebraic restrictions:

    • Polynomials: Expressions like x2+3x1x^2 + 3x - 1 have no restrictions and allow all real numbers for xx.

    • Fractions / Rational Functions: The denominator cannot equal zero (00).

    • Even Square Roots: Even-root radicands cannot contain negative real numbers; the interior must be greater than or equal to zero (0\neq 0).

  • Even Root Domain Calculation Example:

    • For x+7√{x+7}, set the interior x+70x + 7 ≥ 0.

    • Solving for xx gives x7x ≥ -7.

  • Odd Roots vs. Even Roots Behavior:

    • Odd roots (such as cube roots and fifth roots) can contain negative numbers inside the radicand.

    • Example Equation 1: x4+y5=23x^4 + y^5 = 23 simplifies to y=[5]23x4y = √[5]{23 - x^4}. This produces exactly one real yy for every real xx, so it is a valid function.

    • Example Equation 2: x4+y2=23x^4 + y^2 = 23 simplifies to y=±23x4y = ±√{23 - x^4}. The ±± creates two distinct outputs for many inputs, so it is not yy as a function of xx.

Interval Notation

  • Overview: Compact notation for describing sets of real numbers.

  • Inclusion and Exclusion Symbols:

    • Parentheses ()(\,) exclude an endpoint.

    • Brackets [][\,] include an endpoint.

    • Infinity and negative infinity -∞ always use parentheses.

  • Interval Examples:

    • Inequality x7x ≥ -7 becomes [7,)[-7, ∞).

    • Inequality 2<x5-2 < x ≤ 5 becomes (2,5](-2, 5].

    • All real numbers becomes (,)(-∞, ∞).

Linear Functions

  • Definition: A linear function graphs as a straight line and can be written in slope-intercept form y=mx+by = mx + b, where:

    • mm represents the slope.

    • bb represents the y-intercept.

  • Linear Conversion Example:

    • Given equation: x=6y+7x = 6y + 7

    • Solve for yy:     x7=6yx - 7 = 6y     y=16x76y = \frac{1}{6}x - \frac{7}{6}

    • Slope m=16m = \frac{1}{6} and y-intercept b=76b = -\frac{7}{6}.

  • Identifying Nonlinear Functions: Expressions containing x2x^2, x\sqrt{x}, x|x|, xyxy, or other non-linear powers are generally not linear functions.

Core Parent Functions

  • Quadratic Parent Function: y=x2y = x^2

    • U-shaped parabola with vertex at (0,0)(0,0).

  • Absolute Value Parent Function: y=xy = |x|

    • V-shaped graph with vertex at (0,0)(0,0).

  • Square-Root Parent Function: y=xy = \sqrt{x}

    • Graph starts at endpoint (0,0)(0,0) and curves to the right.

  • Linear Parent Function: y=xy = x

    • Straight line passing through (0,0)(0,0) with slope 11.

General Transformation Formula and Rules

  • Master Transformation Formula: y=af(xh)+ky = a f(x - h) + k

    • aa: Controls vertical stretch, vertical compression, and vertical reflection.

    • hh: Controls horizontal translations.

    • kk: Controls vertical translations.

  • Horizontal Shift Rules:

    • Operations inside the function perform the opposite of intuition.

    • f(x3)f(x - 3) shifts the graph RIGHT by 33 units.

    • f(x+3)f(x + 3) shifts the graph LEFT by 33 units.

  • Vertical Shift Rules:

    • Operations outside the function behave normally.

    • f(x)+4f(x) + 4 shifts the graph UP by 44 units.

    • f(x)4f(x) - 4 shifts the graph DOWN by 44 units.

  • Reflection Rules:

    • f(x)-f(x) reflects the graph vertically across the x-axis.

    • f(x)f(-x) reflects the graph horizontally across the y-axis.

Vertical Stretch and Compression

  • Parameter Evaluation: In y=af(x)y = a f(x), evaluate a|a| relative to 11:

    • If a>1|a| > 1, the graph is vertically stretched, becoming steeper and narrower.

    • If 0<a<10 < |a| < 1, the graph is vertically compressed, becoming flatter and wider.

  • Job Separation Principle:

    • Magnitude a|a| controls vertical stretch/compression.

    • Sign of aa controls reflection across the x-axis.

  • Example Analysis y=3x2y = -3x^2:

    • Magnitude a=3|a| = 3 stretches the parabola vertically by a factor of 33.

    • Negative sign reflects the graph across the x-axis, making the parabola open downward.

Quadratics and Parabolas

  • Parent Function: y=x2y = x^2

  • Vertex Form: y=a(xh)2+ky = a(x - h)^2 + k

    • Vertex location is (h,k)(h, k).

  • Opening Direction Rules:

    • If a>0a > 0, the parabola opens upward.

    • If a<0a < 0, the parabola opens downward.

    • Reasoning: A squared number is non-negative. A positive multiplier aa places the arms above the vertex; a negative multiplier aa reflects them below the vertex.

  • Transformation Example y=2(x3)24y = 2(x - 3)^2 - 4:

    • Vertex is (3,4)(3, -4).

    • Horizontal shift: Right 33 units.

    • Vertical shift: Down 44 units.

    • Opening direction: Opens upward (a=2>0a = 2 > 0).

    • Vertical stretch: Stretched vertically by a factor of 2$.\n\n\n# Sideways Parabolas\n\n- Standard Form: When yissquaredinsteadofis squared instead ofx,theparabolaopenssideways:, the parabola opens sideways:x = a(y - k)^2 + h\n\n- Key Coordinates: The vertex is (h, k).\n\n- Detailed Example Analysis x = y^2 + 8:\n - Vertex is (8, 0).\n - Opening direction: Opens to the right.\n - Evaluating Points:\n - Substituting y = 1yieldsyieldsx = (1)^2 + 8 = 9,givingpoint, giving point(9, 1).\n - Substituting y = -1yieldsyieldsx = (-1)^2 + 8 = 9,givingpoint, giving point(9, -1).\n - Function Status: Fails the vertical line test because input x = 9yieldstwodistinctoutputs(yields two distinct outputs (y = 1andandy = -1).\n\n\n# Absolute-Value Transformations\n\n- Parent Graph: y = |x|formsaVshapewithvertexforms a V shape with vertex(0,0).\n\n- Transformation Form: y = a|x - h| + k\n - Vertex is at (h, k).\n\n- Example Analysis y = -2|x + 3| + 1:\n - Vertex is (-3, 1).\n - Shifts: Left 3units,upunits, up1 unit.\n - Reflection: Reflected across the x-axis.\n - Stretch: Vertically stretched by a factor of 2$.

  • Graphing Procedure:

    1. Plot the vertex (h,k)(h, k) first.

    2. Use a|a| to determine how quickly each arm rises or falls for every 11 unit moved left or right.

Square-Root Transformations

  • Parent Graph: y=xy = \sqrt{x} begins at (0,0)(0,0) and extends right.

  • Transformation Form: y=axh+ky = a\sqrt{x - h} + k

    • Starting endpoint is (h,k)(h, k).

  • Example Analysis y=x+7y = \sqrt{x + 7}:

    • Begins at endpoint (7,0)(-7, 0) because x+7=0x + 7 = 0 when x=7x = -7.

    • Domain is [7,)[-7, \infty).

  • Useful Reference Points: Select perfect square inputs for evaluating parent function points:

    • x=0y=0x = 0 \rightarrow y = 0

    • x=1y=1x = 1 \rightarrow y = 1

    • x=4y=2x = 4 \rightarrow y = 2

    • x=9y=3x = 9 \rightarrow y = 3

The Difference Quotient

  • Formula: f(x+h)f(x)h\frac{f(x+h) - f(x)}{h} where h0h \ne 0

  • Purpose: Measures the average rate of change and serves as the foundation for derivatives in calculus.

  • Step-by-Step Evaluation for f(x)=x2f(x) = x^2:

    1. Evaluate f(x+h)f(x+h): f(x+h)=(x+h)2=x2+2xh+h2f(x+h) = (x+h)^2 = x^2 + 2xh + h^2

    2. Subtract f(x)f(x): (x2+2xh+h2)x2=2xh+h2(x^2 + 2xh + h^2) - x^2 = 2xh + h^2

    3. Divide by hh: 2xh+h2h=h(2x+h)h=2x+h\frac{2xh + h^2}{h} = \frac{h(2x + h)}{h} = 2x + h

  • Simplification Rules:

    • An expression like 6hh\frac{6h}{h} simplifies to 66 because hh=1\frac{h}{h} = 1 when h0h \ne 0

  • Common Error Warning: A primary mistake is forgetting to distribute subtraction across every term in f(x)f(x).

Translating Word Problems into Functions

  • Translation Procedure: First identify unknown quantities, then establish algebraic relationships using geometric or physical constraints.

  • Example Problem Walkthrough:

    • Scenario: A rectangle has a perimeter of 420m420\,m.

    • Step 1: Write the perimeter equation:     P=2L+2W=420P = 2L + 2W = 420

    • Step 2: Simplify by dividing by 22:     L+W=210L + W = 210

    • Step 3: Express width in terms of length:     W=210LW = 210 - L

    • Step 4: Express area as a function of length LL:     A=L×WA = L \times W     A(L)=L(210L)=210LL2A(L) = L(210 - L) = 210L - L^2

    • Step 5: Units verification: Area uses square meters (m2m^2) because meters times meters equals m2m^2.

    • Step 6: Determine physical domain restrictions:

    • Both physical dimensions must be strictly positive (L>0L > 0 and 210L>0210 - L > 0).

    • Solving 210L>0210 - L > 0 gives L<210L < 210

    • Physical Domain: 0<L<2100 < L < 210

Reliable Graphing Strategy

  • Step 1: Identify the parent function.

  • Step 2: Rewrite the equation into transformation form if possible.

  • Step 3: Locate the primary vertex, endpoint, or intercept.

  • Step 4: Apply horizontal and vertical shifts.

  • Step 5: Apply reflection across axes and vertical stretch/compression.

  • Step 6: Plot a few easy, key points.

  • Step 7: Verify domain, range, opening direction, and test against the vertical line test.

Common Traps and Pitfalls

  • Notation Error: f(x)f(x) represents function evaluation, not multiplication of ff and x$.\n\n- Direction Confusion: Inside horizontal shifts move in the opposite direction of the sign (x + 7meansshiftLEFTbymeans shift LEFT by7).\n\n- Radical Fallacy: A square root alone does not make an expression fail to be a function. y = \sqrt{x}ISavalidfunction,whereasIS a valid function, whereasy = \pm\sqrt{x} is NOT a function.\n\n- Parameter Isolation: A negative sign on ameansreflectionacrossthexaxis,whilemagnitudemeans reflection across the x-axis, while magnitude|a| determines vertical stretch/compression.\n\n- Domain Exclusions: Even-root radicands must be \ge 0,andrationaldenominatorscannotequal, and rational denominators cannot equal0$.

  • Variable Power Orientation: x2x^2 forms a vertical parabola; y2y^2 forms a sideways parabola.

Practice Questions and Detailed Answers

  • Question 1: Is y=x2+4y = x^2 + 4 a function? Explain why.

    • Answer 1: Yes. Every input xx produces exactly one output y$.\n\n- Question 2: Is x = y^2 + 8afunctionofa function ofx? Explain with the vertical line test.\n - Answer 2: No. Many xvaluescorrespondtobothapositiveandnegative-values correspond to both a positive and negativey; a vertical line intersects the graph twice.\n\n- Question 3: Find the domain of f(x) = \sqrt{x-5} in interval notation.\n - Answer 3: Set x - 5 \ge 0 \rightarrow x \ge 5.Domainis. Domain is[5, \infty).\n\n- Question 4: Describe every transformation from y = x^2totoy = -3(x+2)^2 + 5.\n - Answer 4: Shifted left 2units,shiftedupunits, shifted up5units,verticallystretchedbyafactorofunits, vertically stretched by a factor of3, and reflected across the x-axis.\n\n- Question 5: Give the vertex and opening direction of y = 2(x-4)^2 - 7$.

    • Answer 5: Vertex is (4,7)(4, -7); opens upward because a = 2 > 0$.\n\n- Question 6: Give the vertex and direction of x = (y-3)^2 - 2$.

    • Answer 6: Vertex is (2,3)(-2, 3); opens to the right.

  • Question 7: Describe y=12x6+1y = \frac{1}{2}|x-6| + 1 relative to y = |x|$.\n - Answer 7: Shifted right 6units,shiftedupunits, shifted up1unit,andverticallycompressedbyafactorofunit, and vertically compressed by a factor of\frac{1}{2}.\n\n- Question 8: If f(x) = 3x^2 - 2x,find, findf(2).\n - Answer 8: 3(2^2) - 2(2) = 3(4) - 4 = 12 - 4 = 8.\n\n- Question 9: If f(x) = x^2,simplify, simplify\frac{f(x+h) - f(x)}{h}.\n - Answer 9: \frac{(x+h)^2 - x^2}{h} = \frac{2xh + h^2}{h} = 2x + h\n\n- Question 10: A rectangle has perimeter 100.Writeareaasafunctionof. Write area as a function ofL and give its physical domain.\n - Answer 10: Width W = 50 - L,areafunction, area functionA(L) = L(50 - L) = 50L - L^2,physicaldomain, physical domain0 < L < 50$.

Mastery Check and Recommended Study Strategy

  • Mastery Criteria: Mastery is achieved when looking at any given equation allows immediate determination of:

    • Parent function

    • Function status (whether it is a valid function)

    • Domain and range

    • All applied transformations

    • Vertex or starting endpoint coordinates

    • Opening or extension direction

    • Key graph coordinates

    • Justification for why each property is true

  • Recommended Study Strategy:

    • Do not memorize left/right/up/down rules as isolated shortcuts.

    • Start from the parent function graph and analyze what the equation mathematically does to input xx and output $$y$.

    • Transforming isolated rules into underlying reasoning allows application to unfamiliar and complex problems.