Work, Power, and Simple Machines Study Guide

Principles of Work and Power

  • Definition of Work: In the field of science, work is defined as the transfer of energy to an object by a force that causes that object to move in the same direction as the force.
  • Condition for Work: Work is strictly considered to be done only while the force is being actively applied to the object.
  • Formula for Work:
    • Work (in Joules / J)=Force (in Newtons / N)×Distance (in meters / m)\text{Work (in Joules / } J) = \text{Force (in Newtons / } N) \times \text{Distance (in meters / } m)
    • W=F×dW = F \times d
  • Application Example: If a person pushes a book for a distance of 0.25 m0.25\,m and the book continues to slide for another 1 m1\,m after the person stops pushing, the distance used to calculate the work performed by the person is only the 0.25 m0.25\,m during which the force was applied.

Calculating Work, Force, and Distance

Work Calculation Problems
  • Problem 1 (Maria and the Box): Maria pushes a box with a force of 20 N20\,N across the floor for a distance of 3 m3\,m.
    • Solution: 20 N×3 m=60 J\text{Solution: } 20\,N \times 3\,m = 60\,J
  • Problem 2 (Cart Pulling): A boy pulls a cart using 15 N15\,N of force for 4 m4\,m.
    • Solution: 15 N×4 m=60 J\text{Solution: } 15\,N \times 4\,m = 60\,J
  • Problem 3 (Stair Climb): A student weighing 400 N400\,N climbs up a staircase that is 3 m3\,m high.
    • Work against gravity: 400 N×3 m=1200 J\text{Work against gravity: } 400\,N \times 3\,m = 1200\,J
  • Work Comparison:
    • Case A: 10 N10\,N force over 5 m=50 J5\,m = 50\,J
    • Case B: 20 N20\,N force over 2 m=40 J2\,m = 40\,J
    • Conclusion: Case A involves more work (50 J>40 J50\,J > 40\,J).
Force Calculation Problems
  • Formula: F=WdF = \frac{W}{d}
  • Problem 1: A worker does 120 J120\,J of work moving a box 4 m4\,m.
    • Force: 120 J4 m=30 N\text{Force: } \frac{120\,J}{4\,m} = 30\,N
  • Problem 2: A person lifts a load through 2 m2\,m while doing 100 J100\,J of work.
    • Force: 100 J2 m=50 N\text{Force: } \frac{100\,J}{2\,m} = 50\,N
  • Problem 3: A student does 250 J250\,J of work to push a box 5 m5\,m.
    • Force: 250 J5 m=50 N\text{Force: } \frac{250\,J}{5\,m} = 50\,N
  • Problem 4: It takes 450 J450\,J of work to move a suitcase 3 m3\,m.
    • Force: 450 J3 m=150 N\text{Force: } \frac{450\,J}{3\,m} = 150\,N
Distance Calculation Problems
  • Formula: d=WFd = \frac{W}{F}
  • Problem 1: A force of 25 N25\,N performs 200 J200\,J of work.
    • Distance: 200 J25 N=8 m\text{Distance: } \frac{200\,J}{25\,N} = 8\,m
  • Problem 2: An applied force of 50 N50\,N produces 400 J400\,J of work.
    • Distance: 400 J50 N=8 m\text{Distance: } \frac{400\,J}{50\,N} = 8\,m
  • Problem 3: A student exerts a force of 10 N10\,N and does 70 J70\,J of work.
    • Distance: 70 J10 N=7 m\text{Distance: } \frac{70\,J}{10\,N} = 7\,m
  • Problem 4: A force of 60 N60\,N does 180 J180\,J of work.
    • Distance: 180 J60 N=3 m\text{Distance: } \frac{180\,J}{60\,N} = 3\,m

Understanding Power

  • Definition of Power: Power represents the rate at which work is performed. It describes how fast work is being done.
  • Formula for Power:
    • Power (in Watts / W)=Work (in Joules / J)Time (in seconds / s)\text{Power (in Watts / } W) = \frac{\text{Work (in Joules / } J)}{\text{Time (in seconds / } s)}
    • P=WtP = \frac{W}{t}
    • Since W=F×dW = F \times d, the formula can also be written as P=F×dtP = \frac{F \times d}{t}.
  • Relationship to Speed: The faster work is accomplished, the higher the power output. For example, running up stairs generates more power than walking up the same stairs slowly.
Common Power Scenarios and Problems
  • A car problem: A car exerts a force of 500 N500\,N to move 100 m100\,m in 50 s50\,s.
    • Work: 500 N×100 m=50,000 J\text{Work: } 500\,N \times 100\,m = 50,000\,J
    • Power: 50,000 J50 s=1000 W\text{Power: } \frac{50,000\,J}{50\,s} = 1000\,W
  • Crate movement: A 100 N100\,N force moves a crate 12 m12\,m in 6 s6\,s.
    • Work: 100 N×12 m=1200 J\text{Work: } 100\,N \times 12\,m = 1200\,J
    • Power: 1200 J6 s=200 W\text{Power: } \frac{1200\,J}{6\,s} = 200\,W
  • Object movement: A 50 kg50\,kg object moves 20 m20\,m in 5 s5\,s. Note: Standard gravity (9.8 m/s29.8\,m/s^2 or approximately 10 m/s210\,m/s^2) would be needed to find weight/force if it is being lifted, but often mass problems in these slides use the force value provided.
  • Motor lifting: A motor generates 500 W500\,W while lifting a 200 N200\,N load for 4 s4\,s.
    • Work: Power×Time=500 W×4 s=2000 J\text{Work: } \text{Power} \times \text{Time} = 500\,W \times 4\,s = 2000\,J
  • Staircase Force: A 75 kg75\,kg person climbs a staircase 5 m5\,m high in 10 s10\,s.
    • Force (Weight): 75 kg×9.8 m/s2=735 N (approximate)\text{Force (Weight): } 75\,kg \times 9.8\,m/s^2 = 735\,N \text{ (approximate)}
  • Time calculation: Work is 3000 J3000\,J with a power of 500 W500\,W.
    • Time: WP=3000 J500 W=6 s\text{Time: } \frac{W}{P} = \frac{3000\,J}{500\,W} = 6\,s

Factors Affecting Work and Lifting

  • Force at an Angle: When force is applied at an angle, it is composed of a downward force and a forward force. Only the component of the force in the direction of motion contributes to the work done.
  • Work while Lifting Objects: When lifting an object vertically, the work done is equal to the weight of the object (force of gravity) multiplied by the vertical distance it is lifted.
  • Relationship to Energy: Lifting an object increases the object's potential energy. The work done on the object is effectively stored as energy.

Simple Machines

Simple machines are devices that perform work using only a single motion. There are six primary types:

1. The Lever
  • Definition: A bar that pivots or rotates around a fixed point called a fulcrum.
  • First-Class Lever:
    • The fulcrum is positioned between the input force and the output force.
    • The direction of the input force is always different from the output force.
    • Examples: Seesaw, scissors, pliers, a hammer pulling a nail, a beverage can finger tab.
  • Second-Class Lever:
    • The output force is positioned between the input force and the fulcrum.
    • Both forces act in the same direction.
    • This lever increases the output force relative to the input force.
    • Examples: Wheelbarrow, nutcracker, the human foot, stapler.
  • Third-Class Lever:
    • The input force is between the output force and the fulcrum.
    • The output force is less than the input force.
    • Both forces act in the same direction.
    • Examples: Tweezers, rake, broom.
2. Wheel and Axle
  • Definition: An axle (a shaft) attached to the center of a larger wheel so that they rotate together.
  • Mechanics: The handle (larger diameter) acts as the wheel, and the shaft acts as the axle.
  • Examples: Screwdriver, bicycle, doorknob, vehicle wheels, Ferris wheel, water faucet handle.
3. Inclined Plane
  • Definition: A flat, sloped surface (a ramp).
  • Examples: Skateboard ramp, slide, funnel, roof, water slide, road ramp.
4. Wedge
  • Definition: A type of inclined plane with one or two sloping sides that moves.
  • Example: A tooth.
5. Screw
  • Definition: An inclined plane that is wrapped around a cylinder.
  • Example: Threads of a lightbulb.
6. Pulley
  • Definition: A grooved wheel with a rope or cable wrapped around it.
  • Types:
    • Fixed Pulley: Changes the direction of the force.
    • Movable Pulley: Decreases the input force required to lift a load.
    • Pulley System: A combination of fixed and movable pulleys.
    • Example: Flagpole.

Compound Machines

  • Definition: A machine formed when two or more simple machines work together in conjunction.
  • Example: Can Opener
    • Uses a second-class lever to move the handle.
    • Uses a wheel and axle to turn the cutting blade.
    • Uses a wedge to puncture the lid of the metal can.

Class Activities and Exercises

Matching Simple Machines
  • Tooth →\rightarrow Wedge
  • Doorknob →\rightarrow Wheel and Axle
  • Threads of a lightbulb →\rightarrow Screw
  • Wheelbarrow →\rightarrow Lever
  • Ramp →\rightarrow Inclined Plane
  • Flagpole →\rightarrow Pulley
Group Relay Game
  • 1. The first player solves a problem.
  • 2. The answer is whispered to the next player in line.
  • 3. The first player moves to the back, and the next player receives a new problem.
  • 4. Group with the highest points for correct answers wins.
Poster Project Requirements
  • Poster 1 - Work: Focus on the definition (force causing movement). Draw real-life examples like lifting a backpack, pushing a shopping cart, or pulling a wagon.
  • Poster 2 - Power: Focus on the rate of work. Draw examples of high power, such as riding a bike fast, running up stairs, or using a lawnmower.
  • Section Breakdown:
    • Section A: Key Ideas (definitions and formulas).
    • Section B: Sample Problems (2 original word problems with units: N,m,J,s,WN, m, J, s, W).
    • Section C: Real-Life Examples (list at least 3, such as lifting bags or pushing chairs, and illustrate at least one).