College Physics - Chapter 14: Heat and Heat Transfer Methods
Heat and Heat Transfer Methods
Introduction to Heat
- Heat transfer occurs due to temperature differences between objects or systems.
- Heat is defined as energy that is transferred solely because of a temperature difference.
- When objects with different temperatures interact (e.g., a soft drink and ice), energy is transferred until they reach thermal equilibrium at the same temperature (T').
Mechanical Equivalent of Heat
- It's possible to alter a substance's temperature by performing work on it.
- This demonstrates that heat is a form of energy.
- James Prescott Joule's experiments established the mechanical equivalent of heat, which relates work to heat transfer.
- 1.00 \text{ kcal} = 4186 \text{ J}
Heat Transfer and Temperature Change
- The amount of heat transferred is directly proportional to the temperature change.
- Doubling the temperature change requires twice the heat.
- The amount of heat transferred is directly proportional to the mass.
- Doubling the mass requires twice the heat for an equivalent temperature change.
- The amount of heat transferred depends on the substance and its phase.
- Different substances require different amounts of heat to achieve the same temperature change.
Factors Affecting Heat Transfer
- Transferred heat (Q) depends on:
- Change in temperature (\Delta T)
- Mass of the system (m)
- Substance and its phase
- Equation for heat transfer: Q = mc\Delta T
- Q = heat transfer
- m = mass
- \Delta T = change in temperature
- c = specific heat (depends on the material and phase)
- SI unit for specific heat: J/(kg·K) or J/(kg·°C)
- Specific heat is the amount of heat needed to change the temperature of 1.00 kg of a substance by 1.00 °C.
Example: Heating Water in an Aluminum Pan
- A 0.500 kg aluminum pan is used to heat 0.250 kg of water from 20.0 °C to 80.0 °C.
- Specific heat of water: 4186 J/kg·°C
- Specific heat of aluminum: 900 J/kg·°C
- The pan and water are at the same temperature.
- When the pan is heated, both the pan and water experience the same temperature increase.
Phase Change and Latent Heat
- During a phase change (e.g., ice melting), no temperature change occurs despite heat transfer.
- Most substances exist in solid, liquid, or gas phases.
- Phase changes occur at fixed temperatures for a given substance and pressure (boiling and freezing/melting points).
- Heat absorbed or released during phase changes is given by:
- Q = mL_f (melting/freezing)
- Q = mL_v (vaporization/condensation)
- L_f = latent heat of fusion
- L_v = latent heat of vaporization
Example: Chilling Soda with ice cubes
- Three ice cubes at 0 °C are used to chill 0.25 kg of soda at 20 °C.
- Each ice cube has a mass of 6.0 g.
- The soda is in a foam container to minimize heat loss.
- Assume the soda has the same heat capacity as water (4186 J/kg·°C).
- Latent heat of fusion of water: 334 kJ/kg
- Melting of ice occurs in two steps: phase change (ice to water at 0°C), then temperature increase of the water.
Heat Transfer Methods
- Heat is transferred by conduction, convection, and radiation.
- In a fireplace, radiation is primarily responsible for heat transfer.
- Conduction occurs at a slower rate.
- Convection occurs through air movement (cold air entering, hot air leaving).
Conduction
- Conduction is heat transfer between objects in direct contact.
- Example: Heat transferring to your hands when holding a hot cup of coffee.
- The rate of conductive heat transfer is given by: \frac{Q}{t} = kA\frac{(T2 - T1)}{d}
- \frac{Q}{t} = rate of heat transfer (energy per unit time)
- d = thickness or distance between objects
- A = contact area
- k = thermal conductivity
- T2 - T1 = temperature difference
Example: Ice Box
- A styrofoam ice box has a total area of 0.950 m² and walls with an average thickness of 2.50 cm.
- The box contains ice, water, and canned beverages at 0 °C.
- The outside temperature is 35 °C.
- Thermal conductivity of styrofoam: 0.010 J/s·m·°C
- Latent heat of fusion of water: 334 kJ/kg
Convection
- Convection is heat transfer by the macroscopic movement of mass.
- Convection can be natural or forced and is generally faster than conduction.
- Example: Steaming milk for hot cocoa.
Radiation
- Radiation is heat transfer through the emission or absorption of electromagnetic waves.
- Example: Reheating coffee in a microwave.
- The rate of heat transfer by radiation is determined by the Stefan-Boltzmann law: \frac{Q}{t} = \sigma eAT^4
- \frac{Q}{t} = rate of heat transfer (energy per unit time)
- \sigma = Stefan-Boltzmann constant (5.67 x 10-8 J/s·m²·K⁴)
- e = emissivity of the body (0 to 1)
- A = surface area
- T = temperature in Kelvin
- The net rate of heat transfer by radiation is related to both the object's temperature and its surroundings' temperature:
- \frac{Q{net}}{t} = \sigma eA(T1^4 - T_2^4)
Example: Radiation from a Person
- An unclothed person is standing in a dark room with an ambient temperature of 22.0 °C.
- The person's skin temperature is 33.0 °C, and the surface area is 1.50 m².
- The emissivity of skin is 0.97.
- Stefan-Boltzmann constant: 5.67 x 10-8 J/s·m²·K⁴
- T_2 = 22°C + 273 = 295 K
- T_1 = 33°C + 273 = 306 K
- \frac{Q}{t} = (5.67 × 10^{-8} J/s m^2 K^4)(0.97)(1.50 m^2)((306K)^4 - (295K)^4) = - 99 J/s = -99 W