Inductors and RL Circuits Study Notes

Chapter 11: Inductors

Overview
  • Topics Covered:

    • Inductors

    • Inductance

    • Inductors in DC

    • Inductors in AC

    • RL Circuits and Filters

    • Inductor Applications

    • Capacitor vs Inductor


Inductors

  • Definition: When a length of wire is formed into a coil, it operates as a basic inductor.

  • Formation of Magnetic Field:

    • When current flows in the inductor, it generates magnetic lines of force around each loop of the coil.

    • These lines combine with the adjoining loops, creating a strong electromagnetic field within and around the coil.

  • Induced Voltage:

    • A change in current causes the magnetic field to change, inducing a voltage across the inductor that opposes the change in current.

  • Types of Inductors:

    • Basic Inductor

    • Encapsulated Inductor

    • Toroidal Inductor

    • Variable Inductor


Inductance

  • Definition: Inductance, denoted as L and measured in henries (H), describes the coil's ability to establish an induced voltage due to current changes, referred to as self-inductance.

  • Henry Definition:

    • One henry (H) is the inductance of a coil when a current changing at a rate of one ampere per second induces one volt across the coil.

    • Typically, coils are much smaller than 1 H; millihenries (mH) and microhenries (μH) are commonly used units.

  • Factors Affecting Inductance:

    • Increased number of turns in the coil.

    • Use of a magnetic material core (air, iron, ferrite).

  • Formulas:

    • The inductance can be calculated using the formula:
      L=racN2imesextμimesAlL = rac{N^2 imes \boldsymbol{ ext{μ}} imes A}{l}

    • Where:

    • L = Inductance in henries

    • N = Number of turns

    • μ = Permeability in H/m (Wb/At-m) of core material

    • A = Cross-sectional area of the coil in square meters

    • l = Length of the coil in meters

    • Energy Stored in an Inductor:
      E=rac12LI2E = rac{1}{2}L I^2


Example Problem

  • Inductance Calculation:

    • Given:

    • Length l = 2 cm

    • Turns N = 150

    • Diameter = 0.5 cm (radius r = 0.25 cm = 0.0025 m)

    • Permeability of low carbon steel μ = $2.5 imes 10^{-4}$ H/m

    • Area Calculation:
      A=extπr2=extπ(0.0025)2=7.85imes105extm2A = \boldsymbol{ ext{π}} r^2 = \boldsymbol{ ext{π}} (0.0025)^2 = 7.85 imes 10^{-5} ext{ m}^2

    • Inductance Calculation:
      L=rac(150)2imes(2.5imes104)imes(7.85imes105)0.02=22extmHL = rac{(150)^2 imes (2.5 imes 10^{-4}) imes (7.85 imes 10^{-5})}{0.02} = 22 ext{ mH}

    • Energy Calculation:

    • If current I = 1 A:
      E=rac12imes22imes103extHimes(1)2E = rac{1}{2} imes 22 imes 10^{-3} ext{ H} imes (1)^2

    • Energy stored = 0.011 J


Series and Parallel Inductors

Series Inductors

  • Total Inductance Formula:
    L<em>T=L</em>1+L<em>2++L</em>nL<em>T = L</em>1 + L<em>2 + … + L</em>n

  • Example Problem:

    • When a 1.5 H inductor is connected in series with a 680 mH inductor,
      LT=1.5H+0.680H=2.18HL_T = 1.5 H + 0.680 H = 2.18 H

Parallel Inductors

  • Total Inductance Formula:

    • The reciprocal of the total inductance equals the sum of the reciprocals of the individual inductances.
      rac1L<em>T=rac1L</em>1+rac1L<em>2++rac1L</em>nrac{1}{L<em>T} = rac{1}{L</em>1} + rac{1}{L<em>2} + … + rac{1}{L</em>n}

  • Example Problem:

    • For a 1.5 H inductor connected in parallel with a 680 mH inductor:
      rac1LT=rac11.5H+rac10.680H extCalculatedTotalInductance=468extmHrac{1}{L_T} = rac{1}{1.5 H} + rac{1}{0.680 H} \ ext{Calculated Total Inductance} = 468 ext{ mH}


Inductors in DC Circuits

Series RL Circuit

Current Behavior
  • At 5τ (tau) time, all source voltage drops across the resistor (none across inductor).

  • Current at 5τ is maximum, equal to I=racVsRI = rac{V_s}{R}.

  • Instantaneously upon switch closure, inductor acts open, source voltage across it and initial current = 0.

  • Current build-up is exponential while the induced coil voltage decreases.

  • Voltage across the resistor increases with current increase.

RL Time Constant

  • Definition: Determines the rate of current change, established by the ratio of inductance to resistance.

  • Formula:
    au=racLRau = rac{L}{R}

  • Current Increase: - In one time constant (τ), current reaches approx. 63% of its full value after the switch is closed.

  • Final Current: Reaching its full value takes approximately 5τ seconds.

  • Behavior with DC: Inductor acts as a short circuit under constant DC conditions, causing no induced voltage.


Current Equations in RL Circuits

Exponential Relationships

  • Rising Exponential: i=I<em>F+(I</em>iIF)eracRtLi = I<em>F + (I</em>i - I_F)e^{- rac{Rt}{L}}

    • Where:

    • IFI_F = final current value

    • IiI_i = initial current value

    • ii = instantaneous current value.

  • Falling Exponential:

    • The final current decreases below the initial current during magnetic field collapse.

General Current Formula

  • Example: For RL circuits experiencing increasing and decaying current:

    • Current values might represent percent of the final value across time constants (t).

  • Graph: Plotting across time against percentage of the final current.


Inductors in AC Circuits

Inductive Reactance

  • Definition: Inductive reactance is the opposition to sinusoidal current; it directly varies with frequency.

  • Formula:
    XL=extjimesextωL=2extπfLX_L = \boldsymbol{ ext{j}} imes \boldsymbol{ ext{ω}} L = 2 \boldsymbol{ ext{π}} f L

  • Phase Shift: There is a phase shift between voltage and current; voltage leads current by 90 degrees when a sine wave is applied to an inductor.

  • Graphical Representation:

    • When drawing the reactance, it is important to factor in this phase shift for accurate predictions and actions.


Series Inductive Reactance Examples

  • Example:

    • Reactance of a 33 mH inductor at 550 kHz:
      XL=2extπimes(550extkHz)imes(33extmH)=114extkΩX_L = 2 \boldsymbol{ ext{π}} imes (550 ext{ kHz}) imes (33 ext{ mH}) = 114 ext{ kΩ}

  • Further Problem:

    • If three 220μH inductors are in series with a 455 kHz ac source, calculate total reactance, yielding 1.89 kΩ.


Parallel Inductive Reactance

  • Example: Reactance when the same individual inductors are placed in parallel.

    • Each inductor (at 455 kHz) has an individual reactance calculated.

    • Total reactance for three inductors in parallel leads to a calculated result of 210 Ω.


Impedance of Series RL Circuits

  • Components:

    • Total impedance Z is from phasor sum of resistance R and inductive reactance X_L.

  • Impedance Triangle:

    • Visual representation plotting R along the x-axis and X_L along the y-axis.

  • Magnitude of Impedance:
    Z=racR2+XL2Z = rac{R^2 + X_L^2}

  • Phase Angle:
    heta=an1racXLRheta = an^{-1} rac{X_L}{R}

  • Problem Example:

    • R = 1.2 kΩ; (X_L = 960Ω) leads to Z = 1.33 kΩ, and an angle of approx 39°.


Filters and RL Circuits

Phase Angle Variation

  • Reactance phasors depict frequency-dependent behavior.

  • Changes in frequency influence output voltage or gain in reactive filters.

  • Frequency Response Equation:
    Gain=racV<em>outV</em>inGain = rac{V<em>{out}}{V</em>{in}}

Low Pass Filters

  • Characteristics:

    • Passes frequencies ≤ $oldsymbol{f_c}$ and rejects all others.

    • Output V_out is taken across the resistor.

    • Formula for cutoff frequency:
      fc=racR2extπLf_c = rac{R}{2 \boldsymbol{ ext{π}} L}

  • Example Data:

    • At 1 kHz, output yields 8.46 V rms from a 10 V input under 10 mH and 100Ω resistance. Data illustration trends over selected frequencies.


High Pass Filters

  • Characteristics:

    • Output across the inductor increases with input frequencies ≥ $oldsymbol{f_c}$ and rejects lower frequencies.

    • Basic lag network with output leading input voltage.

    • Similar formula for cutoff frequency.

  • Example Data: At varying frequencies, voltage outputs adjust accordingly.


Applications of Inductors

  • Traffic Sensors: Utilize the inductance change to detect vehicle presence above buried coils.

  • Tuned Circuits and Filters: Essential in electronic communication systems to manage frequencies.

  • RF Chokes: Suppress conducted and radiated noise in high-frequency applications.


Capacitor vs. Inductor

Similarities & Differences
  • Both are energy storage devices with diverse functions across electrical circuits.

    • Capacitor: Comprises two conducting surfaces separated by a dielectric. Stores energy in an electric field, opposes voltage changes, and has current leading voltage by 90 degrees.

    • Inductor: A coiled conductor with magnetic properties. Stores energy in a magnetic field, opposes current changes, leads to voltage lagging by 90 degrees.

  • Overall Function: Both provide reactive control in circuits, essential for filter designs, resonant arrangements, and support high-frequency signal management.


Faraday’s Law and Lenz’s Law

  • Faraday’s Law: Voltage induced in a coil is proportional to the rate of change of magnetic field.

  • Lenz’s Law: States that the direction of induced voltage acts against the change in current through a coil, emphasizing conservation of energy principles.


Reference

  • Electronics Fundamentals: Circuits, Devices & Applications

    • 9th Edition, by Thomas L Floyd, David M. Buchla, Gary D. Snyder

    • Published by Pearson © 2022

    • Print ISBN: 9780135583739

    • eText ISBN: 9780135583845