Comprehensive Notes on Electrostatic Potential and Capacitance

Introduction to Electrostatic Potential and Conservative Forces

  • Conservative Forces: The notion of potential energy, introduced in earlier studies of mechanics (Class XI, Chapters 5 and 7), applies to forces where the work done in moving a body between two points is independent of the path taken. Examples include spring force and gravitational force.
  • Work and Potential Energy: When an external force performs work $W$ in moving a body against a conservative force, that work is stored as potential energy. Upon removal of the external force, the body recovers this energy as kinetic energy, such that the total mechanical energy (sum of kinetic and potential) is conserved.
  • Coulomb Force as a Conservative Force: The electrostatic (Coulomb) force between two stationary charges is conservative. This is due to its inverse-square dependence on distance (Fimes1r2F imes \frac{1}{r^2}), mirroring the law of universal gravitation. The primary difference lies in the constants: masses in gravitation are replaced by charges in electrostatics.
  • Electrostatic Potential Energy Definition: For a test charge qq moved in an electric field E\mathbf{E} produced by a source charge configuration (e.g., a charge QQ at the origin), the work done by an external force F<em>ext\mathbf{F}<em>{ext} moving qq from point RR to point PP is given by:     * W</em>RP=RPF<em>extdr=RPFEdrW</em>{RP} = \int_R^P \mathbf{F}<em>{ext} \cdot d\mathbf{r} = - \int_R^P \mathbf{F}_E \cdot d\mathbf{r}     * Here, FE\mathbf{F}_E is the electrostatic force. For the movement to purely store energy without adding kinetic energy, the external force must exactly counter the electric force (F</em>ext=FE\mathbf{F}</em>{ext} = -\mathbf{F}_E), meaning the charge moves with an infinitesimally slow constant speed (no acceleration).

Potential Energy Difference and Absolute Potential

  • Potential Energy Difference (\Delta U): The difference in potential energy between points PP and RR is defined as the work done by the external force to move the charge from RR to PP:     * ΔU=UPUR=WRP\Delta U = U_P - U_R = W_{RP}     * This depends only on the initial and final positions, a hallmark of conservative forces.
  • Reference Point and Arbitrary Constants: Potential energy is defined within an additive constant α\alpha. Only the difference UPURU_P - U_R is physically significant. To define an absolute value, a reference point for zero potential energy must be chosen. The standard convention is to set potential energy to zero at infinity (U=0U_{\infty} = 0).
  • Work-Energy Definition at a Point: The potential energy of a charge qq at point PP is the work done by an external force to bring the charge from infinity to that point:     * UP=WPU_P = W_{\infty P}

Electrostatic Potential (V)

  • Definition: Electrostatic potential VV is the work done per unit test charge in bringing a unit positive charge from infinity to a specific point in an electric field without acceleration.     * VPVR=UPURq=WRPqV_P - V_R = \frac{U_P - U_R}{q} = \frac{W_{RP}}{q}
  • Significant Characteristics:     * It is independent of the test charge qq and characterizes the electric field of the source configuration.     * Unit: Volts (V), named after Alessandro Volta.
  • Alessandro Volta (1745–1827): An Italian physicist who demonstrated that electricity (previously observed in frog tissues by Luigi Galvani) could be generated by sandwiching wet bodies between dissimilar metals. This led to the creation of the first battery, the voltaic pile.

Potential due to a Point Charge

  • Derivation: Consider a charge QQ at the origin. To find the potential at point PP at distance rr, we calculate the work to bring a unit positive charge from infinity. Choosing a radial path:     * The force at an intermediate point rr' is F=Q4πϵ0r2r^\mathbf{F} = \frac{Q}{4\pi\epsilon_0 r'^2} \hat{\mathbf{r}}'     * Total work W=rQ4πϵ0r2dr=[Q4πϵ0r]r=Q4πϵ0rW = -\int_{\infty}^r \frac{Q}{4\pi\epsilon_0 r'^2} dr' = \left[ \frac{Q}{4\pi\epsilon_0 r'} \right]_{\infty}^r = \frac{Q}{4\pi\epsilon_0 r}
  • Formula: The potential VV at distance rr from a point charge QQ is:     * V(r)=Q4πϵ0rV(r) = \frac{Q}{4\pi\epsilon_0 r}
  • Sign Dependencies:     * If Q > 0, then V > 0 (work is done against repulsion).     * If Q < 0, then V < 0 (work is done by the field; external work is negative).
  • Comparison of E and V: Electric field EE varies as 1r2\frac{1}{r^2}, while potential VV varies as 1r\frac{1}{r}.

Potential due to an Electric Dipole

  • Configuration: Two charges qq and q-q separated by distance 2a2a. Dipole moment p\mathbf{p} has magnitude p=q×2ap = q \times 2a and points from q-q to +q+q.
  • Derivation via Superposition: The potential at a distant point PP (where r >> a) is the sum of potentials from both charges:     * V=14πϵ0(qr1qr2)V = \frac{1}{4\pi\epsilon_0} \left( \frac{q}{r_1} - \frac{q}{r_2} \right)     * Using geometry and binomial expansion (ignoring terms higher than the first order in a/ra/r):     * 1r11r(1+acos(θ)r)\frac{1}{r_1} \approx \frac{1}{r} (1 + \frac{a \cos(\theta)}{r}) and 1r21r(1acos(θ)r\frac{1}{r_2} \approx \frac{1}{r} (1 - \frac{a \cos(\theta)}{r}
  • Final Formula: V=14πϵ0pcos(θ)r2=14πϵ0pr^r2V = \frac{1}{4\pi\epsilon_0} \frac{p \cos(\theta)}{r^2} = \frac{1}{4\pi\epsilon_0} \frac{\mathbf{p} \cdot \hat{\mathbf{r}}}{r^2}
  • Key Differences from Point Charge:     * Dipole potential falls off as 1r2\frac{1}{r^2} (faster than point charge 1r\frac{1}{r}).     * It depends on the angle θ\theta between r\mathbf{r} and p\mathbf{p}.     * On the dipole axis (θ=0,π\theta = 0, \pi): V=±p4πϵ0r2V = \pm \frac{p}{4\pi\epsilon_0 r^2}.     * On the equatorial plane (θ=π/2\theta = \pi/2): V=0V = 0.

Potential due to a System of Charges

  • Superposition Principle: The total potential at a point produced by a collection of charges q1,q2,,qnq_1, q_2, …, q_n is the algebraic sum of individual potentials:     * V=14πϵ0i=1nqiriPV = \frac{1}{4\pi\epsilon_0} \sum_{i=1}^n \frac{q_i}{r_{iP}}
  • Continuous Charge Distribution: For a distribution with density ρ(r)\rho(\mathbf{r}), potential is found by integrating:     * V=14πϵ0ρdvrV = \frac{1}{4\pi\epsilon_0} \int \frac{\rho \, dv}{r}
  • Uniformly Charged Spherical Shell:     * Outside (rRr \geq R): V=q4πϵ0rV = \frac{q}{4\pi\epsilon_0 r} (behaves like a point charge at the center).     * Inside (r < R): Potential is constant and equal to the value at the surface, V=q4πϵ0RV = \frac{q}{4\pi\epsilon_0 R}, because the electric field inside is zero.

Equipotential Surfaces

  • Definition: A surface where the electrostatic potential is constant at every point.
  • Properties:     * No work is required to move a charge between two points on an equipotential surface.     * The electric field E\mathbf{E} is always normal to the equipotential surface at every point. This is because if there were a tangential component, work would be required to move a charge along the surface, contradicting the definition.
  • Visual Representations:     * Point Charge: Concentric spheres centered on the charge.     * Uniform Electric Field: Parallel planes perpendicular to the field lines.     * Dipole/Two Positive Charges: Distorted closed surfaces (complex shapes).
  • Relation Between Field and Potential:     * The magnitude of electric field is the change in potential per unit displacement normal to the equipotential surface: E=δVδlE = -\frac{\delta V}{\delta l}.     * The negative sign indicates that the electric field points in the direction of steepest potential decrease.

Potential Energy of a System of Charges

  • Two-Charge System: The work done in bringing q1q_1 (work = 0) and then q2q_2 from infinity to separation r12r_{12}:     * U=14πϵ0q1q2r12U = \frac{1}{4\pi\epsilon_0} \frac{q_1 q_2}{r_{12}}
  • Three-Charge System: Sum of interactions for all pairs:     * U=14πϵ0(q1q2r12+q1q3r13+q2q3r23)U = \frac{1}{4\pi\epsilon_0} \left( \frac{q_1 q_2}{r_{12}} + \frac{q_1 q_3}{r_{13}} + \frac{q_2 q_3}{r_{23}} \right)
  • Potential Energy in an External Field:     * Single charge qq in potential V(r)V(\mathbf{r}): U=qV(r)U = qV(\mathbf{r}).     * Two charges q1,q2q_1, q_2 in external field: U=q1V(r<em>1)+q2V(r2)+q1q24πϵ0r</em>12U = q_1 V(\mathbf{r}<em>1) + q_2 V(\mathbf{r}_2) + \frac{q_1 q_2}{4\pi\epsilon_0 r</em>{12}}.
  • Electron Volt (eV): The energy gained by an electron accelerated through a potential difference of 1 Volt.     * 1eV=1.6×1019J1\,eV = 1.6 \times 10^{-19}\,J.     * Common multiples: 1keV=103eV1\,keV = 10^3\,eV, 1MeV=106eV1\,MeV = 10^6\,eV, 1GeV=109eV1\,GeV = 10^9\,eV, 1TeV=1012eV1\,TeV = 10^{12}\,eV.

Potential Energy of a Dipole in an External Field

  • Torque: In a uniform field E\mathbf{E}, a dipole experiences torque τ=p×E=pEsin(θ)\tau = \mathbf{p} \times \mathbf{E} = pE \sin(\theta).
  • Work Done to Rotate: Work to rotate from θ0\theta_0 to θ1\theta_1:     * W=θ0θ1pEsin(θ)dθ=pE[cos(θ0)cos(θ1)]W = \int_{\theta_0}^{\theta_1} pE \sin(\theta) d\theta = pE [ \cos(\theta_0) - \cos(\theta_1) ]
  • Potential Energy Formula: By choosing θ0=π/2\theta_0 = \pi/2 as the reference (U(π/2)=0U(\pi/2) = 0):     * U(θ)=pEcos(θ)=pEU(\theta) = -pE \cos(\theta) = -\mathbf{p} \cdot \mathbf{E}

Electrostatics of Conductors

  1. Field Inside: The electrostatic field is zero inside a conductor. Mobile charges redistribute until they cancel the external field.
  2. Surface Field Direction: At the surface, the field must be normal. A tangential component would cause surface charges to move, violating the static assumption.
  3. Interior Charge: No excess charge exists inside a conductor in statics. By Gauss’s Law, since E=0E=0, net flux is zero, meaning net charge is zero. Excess charge resides on the surface.
  4. Constant Potential: Potential is constant throughout the volume and surface of a conductor. Since E=0E=0, no work is done moving charges within the conductor.
  5. Surface Field Magnitude: E=σϵ0n^E = \frac{\sigma}{\epsilon_0} \hat{\mathbf{n}}, where σ\sigma is surface charge density.
  6. Electrostatic Shielding: In a cavity within a conductor (with no charges inside), the electric field is zero regardless of external fields or charges on the conductor. This is used to protect sensitive equipment.

Dielectrics and Polarisation

  • Nature of Dielectrics: Non-conductors with no mobile charges. An external field reduces the internal field by inducing a dipole moment but does not cancel it entirely.
  • Molecules:     * Non-Polar: Centers of positive and negative charges coincide (e.g., O2,H2O_2, H_2). Field induces a dipole moment by displacing charges slightly.     * Polar: Possess permanent dipole moments (e.g., HCl,H2OHCl, H_2O). Field aligns these pre-existing dipoles despite thermal agitation.
  • Polarisation (P): Dipole moment per unit volume. For linear isotropic dielectrics:     * P=ϵ0χeE\mathbf{P} = \epsilon_0 \chi_e \mathbf{E}, where χe\chi_e is electric susceptibility.
  • Bound Charges: Polarisation creates induced surface charge densities ±σp\pm \sigma_p on the dielectric boundaries, which produce an opposing field.

Capacitors and Capacitance

  • Capacitor: A system of two conductors separated by an insulator (dielectric). Conductors carry charges QQ and Q-Q with potential difference VV.
  • Capacitance (C): The ratio of charge to potential difference: C=QVC = \frac{Q}{V}.     * Unit: Farad (F); 1F=1C/V1\,F = 1\,C/V. Common units: μF,nF,pF\mu F, nF, pF.     * CC depends on geometry (shape, size, spacing) and the dielectric constant.
  • Dielectric Strength: The maximum electric field a dielectric can withstand before breakdown; for air, it is 3×106V/m3 \times 10^6\,V/m.

Parallel Plate Capacitor

  • Construction: Two plates of area AA separated by distance dd.
  • Field: Between the plates, E=σϵ0=Qϵ0AE = \frac{\sigma}{\epsilon_0} = \frac{Q}{\epsilon_0 A}.
  • Potential: V=E×d=Qdϵ0AV = E \times d = \frac{Qd}{\epsilon_0 A}.
  • Capacitance (Vacuum): C0=ϵ0AdC_0 = \frac{\epsilon_0 A}{d}.
  • Effect of Dielectric: When a dielectric of constant KK fills the space:     * Electric field reduces to E/KE/K.     * Potential reduces to V/KV/K.     * Capacitance increases: C=KC0=Kϵ0AdC = K C_0 = \frac{K \epsilon_0 A}{d}.
  • Permittivity (\epsilon): ϵ=ϵ0K\epsilon = \epsilon_0 K. Dielectric constant K=ϵ/ϵ0K = \epsilon/\epsilon_0.

Combination of Capacitors

  • Series Combination:     * Charge QQ is the same on each capacitor.     * Total potential V=V1+V2++VnV = V_1 + V_2 + … + V_n.     * Effective capacitance: 1C=1C1+1C2++1Cn\frac{1}{C} = \frac{1}{C_1} + \frac{1}{C_2} + … + \frac{1}{C_n}.
  • Parallel Combination:     * Potential VV is the same across each capacitor.     * Total charge Q=Q1+Q2++QnQ = Q_1 + Q_2 + … + Q_n.     * Effective capacitance: C=C1+C2++CnC = C_1 + C_2 + … + C_n.

Energy Stored in a Capacitor

  • Derivation: Work done in transferring charge dqdq' at potential V=q/CV' = q'/C:     * dW=Vdq=qCdqdW = V' dq' = \frac{q'}{C} dq'     * Integrating from 00 to QQ: W=12Q2CW = \frac{1}{2} \frac{Q^2}{C}.
  • Formulas: U=12Q2C=12CV2=12QVU = \frac{1}{2} \frac{Q^2}{C} = \frac{1}{2} CV^2 = \frac{1}{2} QV.
  • Energy Density (u): Energy stored per unit volume in an electric field:     * u=12ϵ0E2u = \frac{1}{2} \epsilon_0 E^2

Questions & Discussion

  • Example 2.1: Calculate potential at PP from charge 4×107C4 \times 10^{-7}\,C at 9cm9\,cm.     * Result: V=9×109×4×1070.09=4×104VV = \frac{9 \times 10^9 \times 4 \times 10^{-7}}{0.09} = 4 \times 10^4\,V. Work to bring 2×109C2 \times 10^{-9}\,C from infinity: W=qV=8×105JW = qV = 8 \times 10^{-5}\,J. Answer is path independent.
  • Example 2.2: Zero potential points for charges 3×108C3 \times 10^{-8}\,C and 2×108C-2 \times 10^{-8}\,C separated by 15cm15\,cm.     * Result: Potential is zero at 9cm9\,cm from the positive charge (between them) and 45cm45\,cm from the positive charge (on the extended line).
  • Example 2.3: Field line signs for point charges.     * Key Logic: For positive charge, potential decreases with distance; work by field on positive charge moved against field is negative. Kinetic energy of a negative charge decreases when moved against repulsion.
  • Example 2.4: Four charges ±q\pm q at corners of square side dd.     * Result: Total work W=q24πϵ0d(42)W = -\frac{q^2}{4\pi\epsilon_0 d}(4 - \sqrt{2}). Potential at center for four equal but alternating charges is zero.
  • Example 2.7:     * Bird on wire: No potential difference between feet, so no shock.     * Man on ground: High potential difference between wire and ground leads to fatal current.     * Comb/Hair: Friction charges the comb; paper polarizes; humidity (rain) prevents charging.
  • Example 2.10: Sharing charge between capacitors.     * Result: When a charged capacitor is connected to an uncharged identical one, potential halves, and total energy is halved. The missing energy is lost as heat and electromagnetic radiation during the transient current phase.