Converting Rectangular form to Polar form
Sal's video is teaching how to convert from rectangular form (a+bi) to polar form, which is written as:
z=r(cosθ+isinθ)z=r(cosθ+isinθ)
where:
rr = distance from the origin (the modulus)
θθ = angle from the positive x-axis (the argument).
Khan Academy+1
The idea visually
Think of 3 + 4i as a point on a graph.
Instead of describing the point as "go 3 right and 4 up," polar form says:
"Go 5 units from the origin at an angle of about 53.1°."
Same point, different description.
Step 1: Find the modulus rr
Use the Pythagorean theorem.
r=a2+b2r=a2+b2
For 3+4i:
r=32+42=9+16=5r=32+42=9+16=5
Nice. It's the classic 3-4-5 triangle.
Step 2: Find the angle θθ
Use tangent.
tanθ=batanθ=ab
So
tanθ=43tanθ=34
Take the inverse tangent:
θ≈53.1∘θ≈53.1∘
Important: This only gives the reference angle. You still have to check which quadrant the number is actually in.
Khan Academy+1
Step 3: Write the polar form
Put the two pieces together.
3+4i=5(cos53.1∘+isin53.1∘)3+4i=5(cos53.1∘+isin53.1∘)
Done.
The sneaky quadrant trick
This is where people get caught.
Take -3+4i.
The calculator says
arctan(4−3)=−53.1∘arctan(−34)=−53.1∘
But that's wrong for this point!
Why?
Because -3+4i is in Quadrant II.
So the actual angle is
180∘−53.1∘=126.9∘180∘−53.1∘=126.9∘
Always ask yourself:
Signs | Quadrant |
|---|---|
| I |
| II |
| III |
| IV |
Quick cheat sheet
Rectangular | Polar |
|---|---|
| 2(cos45∘+isin45∘)2(cos45∘+isin45∘) |
| 5(cos53.1∘+isin53.1∘)5(cos53.1∘+isin53.1∘) |
| 5(cos126.9∘+isin126.9∘)5(cos126.9∘+isin126.9∘) |
Tiny challenge (your turn 😈)
Convert −4−4i−4−4i into polar form.
Try finding:
rr
the reference angle
the correct quadrant
the final polar form
I won't spoil it immediately—I have a feeling you'll probably get this one.