Polynomial Division: Monomial and Long Division Techniques
Defining Polynomials
- Polynomials can be simple numbers or terms multiplied by variables.
- Terms within a polynomial are separated by addition or subtraction.
- Monomial: A polynomial with a single term (e.g., 2x).
- Binomial: A polynomial with two terms.
- Trinomial: A polynomial with three terms (e.g., 8x^3 + 6x^2 + 4).
- While explicit definitions may not be tested, recognizing these forms is important for identifying when you are working with polynomials.
Dividing by a Monomial
- When dividing a polynomial by a monomial (a single term with no addition or subtraction), the process involves treating it like a fraction.
- Step 1: Rewrite as a fraction. For example, to divide (8x^3 + 6x^2 + 4) by 2x, rewrite it as \frac{8x^3 + 6x^2 + 4}{2x} or (8x^3 + 6x^2 + 4) \div (2x).
- Step 2: Divide each term of the numerator by the denominator. This means distributing the division to every term individually:
\frac{8x^3}{2x} + \frac{6x^2}{2x} + \frac{4}{2x} - Example: To divide (20y^2 + 12y - 1) by -4y, you would set it up as:
\frac{20y^2}{-4y} + \frac{12y}{-4y} - \frac{1}{-4y}
Long Division: Numerical Example (Foundation for Polynomial Long Division)
- To understand polynomial long division, it helps to recall traditional long division with numbers.
- **Example: ** Divide 875 by 25.
- Set up: 25 \text{ | } 875 .
- Estimate the first digit: Determine how many times 25 goes into 87. Three times (3 \times 25 = 75) is the closest without going over. Four times (4 \times 25 = 100) would be too much.
- Multiply and Subtract: Write 3 above the 7 in 875. Multiply 3 \times 25 = 75. Subtract 75 from 87 to get 12.
- Bring Down: Bring down the next digit (the 5) to form 125.
- Repeat: Determine how many times 25 goes into 125. This is exactly five times (5 \times 25 = 125).
- Multiply and Subtract: Write 5 next to 3 above the 5 in 875. Multiply 5 \times 25 = 125. Subtract 125 from 125 to get 0.
- The quotient is 35.
Polynomial Long Division: The Process
- The methodology for polynomial long division mirrors the numerical process.
- Step 1: Focus on Leading Terms. Only consider the first term of the divisor and the first term of the dividend.
- Example Scenario: Dividing a polynomial (starting with 2x^2 + 7x) by (x+3).
- Ask: "What times x (first term of divisor) would give us 2x^2 (first term of dividend)?" The answer is 2x.
- Step 2: Place Term in Quotient and Multiply. Write 2x above the dividend, aligning it with the x term. Then, multiply this 2x by the entire divisor (x+3). This yields 2x \times (x+3) = 2x^2 + 6x.
- Step 3: Subtract the Entire Expression (Critical Step). You must subtract the entire result from the previous step. This means changing the sign of each term in the expression you are subtracting.
- Subtract (2x^2 + 6x) from (2x^2 + 7x). This is equivalent to (2x^2 + 7x) - (2x^2 + 6x).
- The first terms should always cancel out: 2x^2 - 2x^2 = 0.
- Subtract the next terms: 7x - 6x = x.
- Step 4: Bring Down and Repeat. Bring down the next term from the original dividend (if any). Then, repeat the process with the new leading term (x in this example) and the divisor (x+3).
- Here, ask: "What times x would give x"? The answer is 1.
- Multiply 1 by (x+3) to get x+3.
- Subtract (x+3) from the current polynomial with the brought-down term (if it was for instance x+3). If it was (x+3)-(x+3) it will result in 0. If the example was (2x^2 + x - 15) ext{ divided by } (x+3), after the first step and bringing down -15 you would have -5x-15. Then you would ask "What times x is -5x?" Answer is -5. You would multiply -5(x+3) = -5x-15. Then subtract -5x-15 - (-5x-15) to get 0.
Placeholders for Missing Terms
- Importance: To maintain organization and proper alignment of terms (e.g., x^2 terms, x terms, constant terms), it is crucial to include placeholders for any missing terms in the dividend.
- Method: If a polynomial is written in descending order of degree but a term is absent (e.g., an x term in a cubic polynomial), represent it with a zero coefficient.
- Example: If you have 5x^3 - 8x^2 + 7, the x term (which would be x^1) is missing.
- Rewrite it as 5x^3 - 8x^2 + 0x + 7 before performing long division. This ensures all power positions (x^3, x^2, x^1, x^0/constant) are accounted for, allowing for neat vertical alignment during subtraction.
Handling Remainders in Polynomial Long Division
- If, after the division process, you are left with a non-zero polynomial term that cannot be further divided by the leading term of the divisor, this is your remainder.
- Format: The remainder is typically expressed as a fraction, with the remainder as the numerator and the original divisor as the denominator.
- Example: If a remainder of 4 is obtained and the divisor was (x+6), the remainder would be written as +\frac{4}{x+6} or \frac{4}{x+6} if it was negative, \frac{-4}{x+6} or simply -\frac{4}{x+6} .
Academic Logistics and Grading
- Extra Credit: Extra credit opportunities are often separate from the main exam grades and contribute to the overall score in a distinct category.
- Grading Breakdown: Exam grades (21\% for each of Exams 1, 2, and 3) constitute a significant portion of the total course grade. Homework and labs may initially appear to count for more but adjust as exam scores are entered.
- Checking Grades: Students are encouraged to carefully review their grades and calculations. If a grading error benefits the student, they should generally not report it. However, if an error negatively impacts their score, they should promptly inform the instructor for correction.