Chemical Reactions and Equations – Detailed Study Notes

Page 1 – Balancing Chemical Equations (Worked Example)

Context

• Example chosen: iron reacts with steam.
• Unbalanced (skeletal) equation: Fe+H<em>2OFe</em>3O<em>4+H</em>2\text{Fe}+\text{H}<em>2\text{O}\rightarrow \text{Fe}</em>3\text{O}<em>4+\text{H}</em>2
• Objective: convert skeletal equation into a balanced chemical equation that obeys the Law of Conservation of Mass.

Hit-and-Trial / Inspection Method (Step-wise)


  1. Step I – Draw Boxes
    Surround every formula with a box so that the chemical formula itself is not modified while coefficients outside the box can change.
    Fe + H<em>2O  Fe</em>3O<em>4 + H</em>2\boxed{\text{Fe}}\ +\ \boxed{\text{H}<em>2\text{O}}\ \rightarrow\ \boxed{\text{Fe}</em>3\text{O}<em>4}\ +\ \boxed{\text{H}</em>2}

  2. Step II – Atom Count Table (Initial)

ElementReactantsProducts
Fe13
O14
H22
The equation is clearly unbalanced.
  • Step III – Start With the Species Having Maximum Atoms
  • • Compound with maximum atoms = Fe<em>3O</em>4\text{Fe}<em>3\text{O}</em>4.
    • Choose oxygen first (4 atoms RHS vs 1 LHS).
    • Multiply water by 4 to equalise oxygen: 4H<em>2O4\text{H}<em>2\text{O}. Fe+4H</em>2OFe<em>3O</em>4+H2\text{Fe}+4\text{H}</em>2\text{O}\rightarrow \text{Fe}<em>3\text{O}</em>4+\text{H}_2
  • Step IV – Balance Second Element (Hydrogen)
  • • LHS H-atoms = 4×2=84\times2=8, RHS H-atoms = 2.
    • Multiply hydrogen molecule by 4: 4H<em>24\text{H}<em>2. Fe+4H</em>2OFe<em>3O</em>4+4H2\text{Fe}+4\text{H}</em>2\text{O}\rightarrow \text{Fe}<em>3\text{O}</em>4+4\text{H}_2
  • Step V – Balance Remaining Element (Iron)
  • • Fe: LHS 1 vs RHS 3 ⇒ multiply Fe by 3.
    3Fe+4H<em>2OFe</em>3O<em>4+4H</em>23\text{Fe}+4\text{H}<em>2\text{O}\rightarrow \text{Fe}</em>3\text{O}<em>4+4\text{H}</em>2
  • Step VI – Verification
  • ElementLeftRight
    ----------------------
    Fe33
    H88
    O44
    All atoms tally → equation balanced.
  • Step VII – Add Physical States & Conditions
  • • Steam is gaseous, iron & its oxide are solids, hydrogen is gas.
    3Fe(s)+4H<em>2O(g)Fe</em>3O<em>4(s)+4H</em>2(g)3\text{Fe(s)}+4\text{H}<em>2\text{O(g)}\rightarrow \text{Fe}</em>3\text{O}<em>4\text{(s)}+4\text{H}</em>2\text{(g)}

    Key Take-aways

    • Only the coefficients (stoichiometric numbers) may be changed; formulae inside boxes stay intact.
    • The procedure systematically balances one element at a time, beginning with the most complex compound.
    • When all elements are balanced and coefficients are the smallest whole numbers, the equation honours the Law of Conservation of Mass.
    • Adding states (s, l, g, aq) or reaction conditions (temperature, pressure, catalysts, light, etc.) makes an equation more informative, e.g.
    CO(g)+2H<em>2(g)340atmCH</em>3OH(l)\text{CO(g)}+2\text{H}<em>2\text{(g)}\xrightarrow{340\,\text{atm}}\text{CH}</em>3\text{OH(l)}
    6CO<em>2(aq)+12H</em>2O(l)SunlightChlorophyllC<em>6H</em>12O<em>6(aq)+6O</em>2(aq)+6H2O(l)6\text{CO}<em>2\text{(aq)}+12\text{H}</em>2\text{O(l)}\xrightarrow[\text{Sunlight}]{\text{Chlorophyll}}C<em>6H</em>{12}O<em>6\text{(aq)}+6\text{O}</em>2\text{(aq)}+6\text{H}_2\text{O(l)}


    Page 2 – Atom-Inventory Method Revisited

    Re-statement of the Example (Eq 1.4)

    Fe+H<em>2OFe</em>3O<em>4+H</em>2\text{Fe}+\text{H}<em>2\text{O}\rightarrow \text{Fe}</em>3\text{O}<em>4+\text{H}</em>2

    Atom Inventory Before Balancing (Unbalanced Eq 1.5)
    ElementLHSRHS
    Fe13
    O14
    H22
    Reasons for the Chosen Order of Balancing
    1. Choose compound with maximum atom count per formulaFe<em>3O</em>4\text{Fe}<em>3\text{O}</em>4.
    2. Within that compound, select element with maximum atoms → Oxygen (4).
    3. Balance O by introducing coefficient 4 before water.
    4. Balance H next since it’s now unbalanced (8 vs 2).
    5. Finally balance Fe.
    Partly Balanced Snapshots

    • After balancing O: Fe+4H<em>2OFe</em>3O<em>4+H</em>2\text{Fe}+4\text{H}<em>2\text{O}\rightarrow \text{Fe}</em>3\text{O}<em>4+\text{H}</em>2
    • After balancing H: Fe+4H<em>2OFe</em>3O<em>4+4H</em>2\text{Fe}+4\text{H}<em>2\text{O}\rightarrow \text{Fe}</em>3\text{O}<em>4+4\text{H}</em>2
    • After balancing Fe: 3Fe+4H<em>2OFe</em>3O<em>4+4H</em>23\text{Fe}+4\text{H}<em>2\text{O}\rightarrow \text{Fe}</em>3\text{O}<em>4+4\text{H}</em>2

    Terminology

    Skeletal Equation – formulae are present but atom counts do not match.
    Hit-and-Trial Method – repeated adjustment of coefficients until balance is achieved.


    Page 3 – Word Equations, Formula Equations & Balancing Rationale

    From Word to Formula

    • Burning magnesium:
    Word form → Magnesium + Oxygen → Magnesium oxide
    Formula form → Mg+O2MgO\text{Mg}+\text{O}_2\rightarrow \text{MgO}
    • The formula form offers brevity and shows actual combining entities.

    Balanced vs Skeletal

    • A balanced equation has equal atom counts on LHS & RHS.
    • An unbalanced (skeletal) equation violates the Law of Conservation of Mass.

    Conservation of Mass (Class IX Recall)

    “Mass can neither be created nor destroyed in a chemical reaction.”
    Mathematically for every element ii:
    n<em>i,reactants=n</em>i,products\sum n<em>{i,\,\text{reactants}} = \sum n</em>{i,\,\text{products}}

    Example (Zn + Dil. H₂SO₄)

    Word description (Activity 1.3):
    Zinc + Sulphuric acid → Zinc sulphate + Hydrogen
    Formula equation:
    Zn+H<em>2SO</em>4ZnSO<em>4+H</em>2\text{Zn}+\text{H}<em>2\text{SO}</em>4\rightarrow \text{ZnSO}<em>4+\text{H}</em>2
    Atom check table shows it is already balanced.


    Page 4 – Observing Chemical Reactions in Daily Life

    Everyday Examples of Chemical Change

    • Spoilage of milk in summer.
    • Rusting of iron cookware/nails.
    • Fermentation of grapes (→ alcohol).
    • Cooking of food.
    • Digestion in the human body.
    • Respiration.

    Diagnostic Features of a Chemical Reaction

    1. Change in state (solid ↔ liquid ↔ gas).
    2. Change in colour.
    3. Evolution of a gas.
    4. Change in temperature / enthalpy (exothermic or endothermic).

    Laboratory Activities Illustrating These Clues

    1. Activity 1.1 – Burning Mg Ribbon
      Observation: dazzling white flame, formation of white powder MgO\text{MgO}.
    2. Activity 1.2 – Lead Nitrate + Potassium Iodide
      Observation: bright yellow precipitate of PbI<em>2\text{PbI}<em>2 indicates colour change & state change. Reaction: Pb(NO</em>3)<em>2(aq)+2KI(aq)2KNO</em>3(aq)+PbI2(s)\text{Pb(NO}</em>3)<em>2\text{(aq)}+2\text{KI(aq)}\rightarrow 2\text{KNO}</em>3\text{(aq)}+\text{PbI}_2\text{(s)}
    3. Activity 1.3 – Zinc + Dil. H₂SO₄
      Observation: effervescence of H2\text{H}_2 gas & rise in temperature.
      Reaction already balanced in previous page.

    Page 5 – Syntax of Chemical Equations

    Components

    Reactants – substances consumed (written LHS).
    Products – substances formed (written RHS).
    • Arrow (→) indicates direction; plus sign (+) separates multiple species.

    Symbol Conventions for Physical States

    • (s) – solid
    • (l) – liquid
    • (g) – gas
    • (aq) – aqueous (dissolved in water)

    Noting Reaction Conditions

    Conditions such as temperature, pressure, catalyst, light, etc. are written above or below the reaction arrow, e.g.
    N<em>2(g)+3H</em>2(g)400atmFe Catalyst, 450°C2NH3(g)\text{N}<em>2\text{(g)}+3\text{H}</em>2\text{(g)}\xrightarrow[400\,\text{atm}]{\text{Fe Catalyst, }450\,\text{°C}}2\text{NH}_3\text{(g)}

    Best Practices for Writing Chemical Equations

    1. Convert descriptive words to chemical formulae.
    2. Check valencies to ensure correct formulae (do not tamper during balancing).
    3. Balance using systematic hit-and-trial or algebraic methods.
    4. Use smallest whole-number coefficients.
    5. Append physical states and reaction conditions when relevant.

    QUICK RECAP CHEAT-SHEET

    Four visual evidences of chemical change: state, colour, gas, temperature.
    Balancing order: complex compound → element with highest multiplicity → proceed until all are balanced.
    Never alter a formula; only place integer coefficients in front.
    Balanced Fe–steam reaction:
    3Fe(s)+4H<em>2O(g)Fe</em>3O<em>4(s)+4H</em>2(g)3\text{Fe(s)}+4\text{H}<em>2\text{O(g)}\rightarrow \text{Fe}</em>3\text{O}<em>4\text{(s)}+4\text{H}</em>2\text{(g)}
    Law of Conservation of Mass underpins all balancing.
    State symbols and reaction conditions add contextual clarity to chemical equations.