Review of Coordinate Geometry and Non-Linear Relationships

Review of Coordinate Geometry

  • The chapter starts with a review of coordinate geometry, building upon concepts studied in Year 9.

  • Key techniques to remember include how to determine length, gradient, and midpoint of a line segment are important and was covered in exercise 1.08

Length, Gradient, and Midpoint

  • Length of AB (Distance between A and B): AB=(x<em>2x</em>1)2+(y<em>2y</em>1)2AB = \sqrt{(x<em>2 - x</em>1)^2 + (y<em>2 - y</em>1)^2}

  • Gradient (Slope) of AB: m=y<em>2y</em>1x<em>2x</em>1m = \frac{y<em>2 - y</em>1}{x<em>2 - x</em>1}

  • Midpoint of AB: M=(x<em>1+x</em>22,y<em>1+y</em>22)M = (\frac{x<em>1 + x</em>2}{2}, \frac{y<em>1 + y</em>2}{2})

Graphing Straight Lines

  • To graph a straight line, find coordinates of two or more points on the line using its equation.

  • The x-intercept is found by setting y=0y = 0 and solving for xx.

  • The y-intercept is found by setting x=0x = 0 and solving for yy.

Equations of Lines

  • Lines can be uniquely determined by certain conditions, leading to different forms of equations:

    • Gradient-Intercept Form: y=mx+by = mx + b, where mm is the gradient and bb is the y-intercept.

    • Point-Gradient Form: yy<em>1=m(xx</em>1)y - y<em>1 = m(x - x</em>1), where mm is the gradient and (x<em>1,y</em>1)(x<em>1, y</em>1) is a point on the line.

    • Two-Point Form: yy<em>1=y</em>2y<em>1x</em>2x<em>1(xx</em>1)y - y<em>1 = \frac{y</em>2 - y<em>1}{x</em>2 - x<em>1}(x - x</em>1), where (x<em>1,y</em>1)(x<em>1, y</em>1) and (x<em>2,y</em>2)(x<em>2, y</em>2) are points on the line.

    • General Form: ax+by+c=0ax + by + c = 0, where aa, bb, and cc are integers and a > 0. Only one way to write the equation of a line in general form

Parallel and Perpendicular Lines

  • Two straight lines are parallel if their gradients are equal.

  • The gradients of two lines are equal if the lines are parallel.

  • A condition for two lines to be perpendicular might be that the product of their gradients is equal to 1-1.

  • If two lines are perpendicular, the product of their gradients is 1-1. That is, m<em>1m</em>2=1m<em>1 m</em>2 = -1 (where neither gradient is zero).

  • If the product of the gradients of two lines is 1-1, then the lines are perpendicular.

  • Two lines with gradients of m<em>1m<em>1 and m</em>2m</em>2 are:

    • Parallel if m<em>1=m</em>2m<em>1 = m</em>2.

    • Perpendicular if m<em>1m</em>2=1m<em>1 m</em>2 = -1 that is m<em>1=1m</em>2m<em>1 = -\frac{1}{m</em>2} where neither m<em>1m<em>1 nor m</em>2m</em>2 can equal zero.

  • The symbol for parallel lines is \parallel.

  • The symbol for perpendicular lines is \perp.

Using Coordinate Geometry

  • Coordinate geometry techniques can be applied to solve geometric problems.

Special Forms of the Parabola

Parabolas of the form y=ax2y = ax^2
  • What is the effect on the graph of varying the value of aa?.

Parabolas of the form y=ax2+ky = ax^2 + k
  • For the equation y=x2+cy = x^2 + c, what is the effect on the graph of varying the value of cc?

Parabolas of the form y=(x+a)2y = (x + a)^2 and y=(x+a)2+ky = (x + a)^2 + k

Parabolas of the form y=ax2+bx+cy = ax^2 + bx + c

Finding the y-intercept
  • To find the y-intercept of y=x2+x12y = x^2 + x - 12, we let x=0x = 0.

Finding the x-intercepts
  • To find the x-intercepts of y=x2+x12y = x^2 + x - 12, we let y=0y = 0.

  • The formula x=b±b24ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} could have been used to find the x-intercepts.

Finding the axis of symmetry
  • The axis of symmetry of the parabola y=ax2+bx+cy = ax^2 +bx+ c is given by the equation: x=b2ax=-\frac{b}{2a}.

Finding the vertex (or turning point)
  • As the vertex lies on the axis of symmetry, its x-coordinate will be the same as that of the axis of symmetry.

  • The y-coordinate can be found by substituting this x-value into the equation of the parabola.

  • The vertex can also be found by finding the midpoint of the interval joining the x-intercepts.

  • The method of completing the square can also be used to find the vertex.

Exponential Graphs

  • Exponential equations involve calculating varying powers of a fixed positive number, often called the base.

  • Exponential graphs can be drawn by producing a table of values and plotting the resulting points on a number plane.

  • Analyzing the equation of the curve will enable you to predict the shape of the curve.

The Hyperbola

Graphs of the form y=kxy = \frac{k}{x}
  • No value for yy exists when x=0x = 0. This is because no number can be divided by zero.

  • The graph has two parts and the curve approaches two lines (the x- and y-axes) but will never touch them. These lines are called asymptotes.

Graphs of the form y=kx+cy = \frac{k}{x} + c
  • Moving the curve vertically will also change the horizontal asymptote.

  • The curve y=kx+cy = \frac{k}{x} + c is obtained by translating the curve y=kxy = \frac{k}{x}

    • cc units up if cc is positive

    • cc units down if cc is negative.

  • The asymptotes are x=0x = 0 and y=cy = c.

Graphs of the form y=kxby = \frac{k}{x - b}
  • The hyperbola y=kxby = \frac{k}{x - b} is obtained by translating the curve y=kxy = \frac{k}{x}

    • bb units to the right if bb is positive

    • bb units to the left if bb is negative.

  • The asymptotes are x=bx =b and y=0y = 0.

  • Notice that when the curve is moved horizontally, the vertical asymptote moves as well.

Circles and Their Equations

  • Every point on a circle is the same distance away from the centre.

  • The equation of a circle that has centre (p,q)(p, q) and radius rr is given by the equation: (xp)2+(yq)2=r2(x-p)^2 +(y-q)^2 =r^2.

Curves of the Form y=ax3y = ax^3 and y=ax3+dy = ax^3 + d

  • Curves of the form y=ax3+dy = ax^3 + d are called cubics because of the x3x^3 term.

Curves of the Form y=axny = ax^n and y=axn+dy = ax^n + d

  • Graphing curves of the form y=axny = ax^n is simple if you recognise the relationship between the signs of xx and yy for different values of aa and nn.

  • To find the sign of yy when y=axny = ax^n we need to realise that:

    • If nn is even: xnx^n is always positive (except for x=0x = 0).

    • If nn is odd: xnx^n is positive when xx is positive. xnx^n is negative when xx is negative.

  • The signs of aa and xnx^n will then determine the sign of yy.

  • As xx becomes smaller, axnax^n (and therefore yy) becomes smaller.

  • As xx becomes larger, axnax^n (and therefore yy) becomes larger.

  • If x=0x = 0, y=0y = 0; and if y=0y = 0, x=0x = 0.

  • Hence, the curve only crosses the x-axis once, at the point (0,0)(0, 0).

  • Curves with an even value of nn will have shapes like parabolas (y=ax2y = ax^2).

  • Curves with an odd value of nn will have shapes like cubics (y=ax3y = ax^3).

  • As nn increases, the steepness of the curve increases, e.g. y=x4y = x^4 will be steeper than y=x2y = x^2.

  • The curve with the higher value of nn will be above the other curve for all values of xx except from 1-1 to 11.

  • As we have already seen in 7:09 for the curve y=ax3y = ax^3, changing aa changes the 'steepness' of the curve. Hence, for the same value of nn, a larger value of aa will result in a steeper curve.

  • e. g. y=2x5y = 2x^5 will be steeper than y=x5y = x^5.

  • Curves of the form y=axn+dy = ax^n + d can be obtained by translating the curve y=axny = ax^n up or down.

    • If dd is positive, translate it up dd units.

    • If dd is negative, translate it down dd units.

Curves of the Form y=a(xr)ny = a(x - r)^n

  • If the curve y=axny = ax^n is moved (horizontally):

    • rr units to the right, the equation of the new curve is y=a(xr)ny = a(x - r)^n.

    • rr units to the left, the equation of the new curve is y=a(x+r)ny = a(x + r)^n.

Curves of the Form y=(xr)(xs)(xt)y = (x - r)(x - s)(x - t)

  • For all the other values of xx, yy is either positive or negative.

  • The three x-intercepts divide the x-axis into four sections.

  • In each of these sections the yy values will be either positive or negative.

  • Testing a point in each of the sections will determine whether that section is positive or negative.

The Intersection of Graphs

  • Both graphical and algebraic methods can be used to find the point or points of intersection of a line with a parabola, circle or hyperbola.

Algebraic method
  • This method is based on the fact that at a point of intersection the x-coordinates on both curves are equal and the y-coordinates on both curves are equal.

For all the graphs met in this chapter it is important that you can:
  • Identify different types of graphs from their equations

  • Determine a possible equation of a given graph.

Key features to identify from the equation
  • Type of Graph

  • Straight line

    • x- and y-intercepts

    • slope

    • horizontal and vertical lines

    • Parabola

    • x- and y-intercepts (when they exist)

    • vertex

    • axis of symmetry

    • concavity

    • Hyperbola

    • x- and y-intercepts (where they exist)

    • asymptotes

    • orientation (Quadrants 1 and 3 or Quadrants 2 and 4)

    • Circle

    • centre

    • radius

    • Cubic

    • basic shape (Is it an increasing or decreasing curve?)

    • Exponential

    • x- and y-intercepts (where they exist)

    • concavity

    • Is it increasing or decreasing?

    • asymptote

Translation: Terms in an equation indicate that the curve has been formed by translating a simpler curve in either a vertical or horizontal direction.
  • y=ax3+dy = ax^3 + d has been formed by translating y=ax3y = ax^3, dd units in a vertical direction.

  • y=a(xr)2y = a(x - r)^2 has been formed by translating y=x2y = x^2, rr units in a horizontal direction.

Symmetry: Graphs that contain an even power of xx have an axis of symmetry.
  • If the yy-axis is an axis of symmetry then the equation will be identical when xx is replaced by x-x.

  • e.g. y=x2+4y = x^2 + 4, y=1+x6y = 1 + x^6, x2+y2=1x^2 + y^2 = 1