BIOL 151 Exam 1 Notes
Exam Structure
The exam consists of multiple true/false questions and multiple choice questions.
For true/false questions, record responses as "A" for True and "B" for False.
Answers are numbered, and a total of 66 answers should be recorded on the answer sheet.
Problem Set Details
Problem 1-8: Statements About Living Cells
All living things are made of cells (including single-cell life forms).
Answer: A (True)
Somatic (body) cells are made from cell division.
Answer: A (True)
Stem cells are created from the assembly of molecules in the environment and not from cell division.
Answer: B (False)
Cells can receive signals through receptors but cannot send signals to other cells.
Answer: B (False)
Mitosis is a process that divides cells into two and assures that both cells have identical copies of the genetic material.
Answer: A (True)
Self-renewal stem cell divisions allow stem cells to make copies of themselves and create new stem cells.
Answer: A (True)
Transit amplifying cells display receptors for signaling pathways that cause them to differentiate into mature cell types.
Answer: A (True)
The only stem cells left in the adult body are located in the skin.
Answer: B (False)
Problem 9-15: Cellular Processes Timing
Determine the phase in which the processes occur:
A = Occurs during interphase
B = Occurs during mitosis but before the metaphase to anaphase transition.
C = Occurs right at the metaphase to anaphase transition.
D = Occurs after the metaphase to anaphase transition.
The replication of homologs to form sister chromatids.
Answer: C
The breakdown of Cohesin.
Answer: C
Cytokinesis - the name for the full separation of dividing cells into two cells.
Answer: B
Signaling from unattached kinetochores.
Answer: B
The replication of centrioles and their movement to opposite poles in the cell.
Answer: A (Centrioles are the structures that spindle fibers extend from.)
The spindle fibers pull the sister chromatids to opposite sides of the cell.
Answer: C
The attachment of Ubiquitin to Securin.
Answer: C
Problem 16-19: Normal Healthy Cells in Anaphase Conditions
Some kinetochores have not yet attached to spindle fibers.
Answer: A (True)
MAD is binding to CDC20.
Answer: A (True)
Expression of the Securin gene has stopped.
Answer: B (False)
Cohesin has been destroyed, but new Cohesin is being made and binding sister chromatids together through protein turnover.
Answer: A (True)
Problem 20-30: Effects on Mitosis
Gain of function mutations cause kinetochores to release the "unattached" signal even when attached to kinetochores.
Answer: A (premature anaphase)
Loss of function in MAD prevents it from changing shape when the "unattached" signal is not present.
Answer: B (stuck in metaphase)
Gain of function mutation in MAD that produces twice as much MAD protein as normal.
Answer: C (completes mitosis normally)
Gain of function mutation in CDC20 that produces twice as much CDC20 protein as normal.
Answer: A
Gain of function mutation in APC that produces twice as much APC protein as normal.
Answer: B
Gain of function mutation in Separase that produces twice as much Separase protein as normal.
Answer: C
Gain of function mutation in Securin that produces twice as much Securin as normal.
Answer: B (stuck in metaphase)
Loss of function mutation in Separase that prevents it from binding to Securin.
Answer: (Insufficient context provided)
Gain of function mutation in Separase that causes it to break down APC even if bound to Securin.
Answer: A
Loss of function mutation in tubulin that prevents spindle fibers from growing/shrinking.
Answer: B
Reduction in the rate of protein turnover of APC that causes APC proteins to last longer in the cell.
Answer: C
Problem 31-35: Kinase Cascade Signaling Pathway
When no signal is present there is not ATP in the cell, causing no proteins to be phosphorylated.
Answer: B (False)
Activation of the kinase activity of TFa causes it to enter the nucleus.
Answer: A (True)
Activation of the kinase activity of TK2 causes TFa to enter the nucleus.
Answer: A (True)
An active phosphatase that targets TK2 could prevent TFa from entering the nucleus.
Answer: A (True)
Activation of the kinase function of the receptor causes TK1 to be phosphorylated and activated.
Answer: A (True)
Problem 36-40: Effects on Kinase Cascade Pathway
If TK1 activated TK2 and a new kinase, TK3, that targeted TFa.
Answer: A (functional but non-oscillating pathway)
If TFa activated a gene encoding a phosphatase that targets TK1.
Answer: B (pathway that would go on and off)
If TFa activated a gene that encodes a kinase that targets TK2.
Answer: C (permanent pathway for signaling)
If TKa activated a gene that caused receptor mediated endocytosis in degradation mode.
Answer: D (non-functional pathway)
If TK2 targeted TFa and activated a phosphatase that also targeted Ta.
Answer: D (non-functional pathway)
Problem 41-44: Oscillating Pathway Involving TFa
Ubiquitin-dependent proteolysis of TFa is underway at timepoints 2 and 3, but not at timepoint 1.
Answer: A (True)
TFa is unphosphorylated at timepoint 3; expression of the gene encoding the phosphatase has stopped.
Answer: A (True)
The pathway would oscillate more quickly if the phosphatase targeted TK1 rather than TK2.
Answer: B (False)
TK1 is not undergoing protein turnover.
Answer: A (True)
Problem 45-49: Properties of Ras in EGF Pathway
When Ras is bound to GTP, it can activate a kinase.
Answer: A (True)
When Ras is bound to GDP, it can get phosphorylated and activated by a kinase.
Answer: A (True)
Ras activates other proteins by making physical contact with them.
Answer: A (True)
NF1, the Ras GAP, is the enzyme that cuts the third phosphate off of GTP to make GDP.
Answer: A (True)
SOS, the Ras GEF, is a kinase that phosphorylates GDP to make GTP and activate Ras.
Answer: B (False)
Problem 50-56: Effects on EGF Pathway
A mutation in Raf that deleted the RBD (Ras-binding domain) of Raf protein.
Answer: A (it would block the pathway)
A mutation in Raf that causes it to target and phosphorylate MEK when Ras is binding to GDP.
Answer: B (over-activate the pathway)
A mutation in HER2 causing over-expression and production of many extra HER2 receptors.
Answer: B (over-activate the pathway)
A mutation in Cbl binding site of EGF receptor preventing Cbl from ubiquitinating the cytoplasmic domain of the receptor.
Answer: B (over-activate the pathway)
A mutation in the kinase domain of the receptor causing it to activate when no signal is present.
Answer: B (over-activate the pathway)
A mutation in Ras that blocks Ras GTPase function.
Answer: B (over-activate the pathway)
Increased expression of the gene encoding the phosphatase PTP1B that targets the cytoplasmic domain of the EGF receptor.
Answer: A (it would block the pathway)
Problem 57-61: Facts about Cancer
As you age, your chance of developing cancer increases.
Answer: A (True)
Cancer results from the accumulation of mutations in cells.
Answer: A (True)
As cancer spreads, signals from the original tumor cause healthy cells to mutate and become cancer cells.
Answer: A (True)
Cancerous cells can break away from the original tumor and move to other places in the body to form new tumors.
Answer: A (True)
Cancer detection and treatment is improving.
Answer: A (True)
Cancer rates are increasing among younger people for reasons that are not yet clear.
Answer: A (True)
These notes serve as a detailed guide for BIOL 151 Exam 1, encompassing key concepts, true/false responses, the impact of biological mutations on cellular processes, and significant facts about cancer. They offer exhaustive coverage necessary for a comprehensive understanding of the exam content.