Limits and One-Sided Limits: Graphical Intuition and Transcript-Based Notes

Graphical interpretation of limits

  • Core idea: The limit of f(x) as x approaches a is the y-value that f(x) gets arbitrarily close to as x gets arbitrarily close to a, regardless of the actual value of f(a) (even if the function is undefined at a).
  • Graphical intuition: examine the part of the graph near x = a from both sides. If the left-hand limit and the right-hand limit match, the two-sided limit exists and equals that common value.
  • Notation (two-sided):
    limxaf(x)=L\lim_{x\to a} f(x) = L
  • One-sided limits: lim<em>xaf(x)=L,lim</em>xa+f(x)=L+\lim<em>{x\to a^-} f(x) = L^- ,\quad \lim</em>{x\to a^+} f(x) = L^+
    • If $L^- = L^+ = L$, the limit exists and equals L.
    • If LL+L^- \neq L^+, the two-sided limit does not exist.
  • What the limit cares about vs the function value:
    • The limit only depends on the behavior of f(x) as x approaches a (from the left and/or right).
    • It does not require f(a) to be defined, nor equal to the limit.
  • Continuity (brief connection):
    • A function is continuous at a if
      limxaf(x)=f(a).\lim_{x\to a} f(x) = f(a).
    • If the limit exists and equals f(a), the function is continuous at a; otherwise discontinuous at a.

The function example from the transcript: (f(x) = \dfrac{2x^2 - 4}{x+2}) with a hole at (x = -2)

  • Function as written (domain excludes x = -2):
    f(x)=2x24x+2,x2.f(x) = \dfrac{2x^2 - 4}{x+2}, \quad x \neq -2.
  • The lecturer’s algebraic step (and a common error):
    • The transcript states: (2x^2 - 4 = (x+2)(x-2)), so the expression would cancel to (x-2) with a hole at (x = -2).
    • Correct note: this cancellation is incorrect because
      2x24(x+2)(x2)since(x+2)(x2)=x24.2x^2 - 4 \neq (x+2)(x-2) \quad\text{since}\quad (x+2)(x-2) = x^2 - 4.
    • The actual numerator factors as
      2x24=2(x22),2x^2 - 4 = 2(x^2 - 2),
      which does not share a factor of (x+2). Thus there is no legitimate cancellation to yield a simple line.
  • What would happen if the numerator were (x^2 - 4) instead? (Related aside to clarify)
    • If f(x)=x24x+2=(x+2)(x2)x+2=x2,x2,f(x) = \dfrac{x^2 - 4}{x+2} = \dfrac{(x+2)(x-2)}{x+2} = x-2,\quad x\neq -2,
    • then the graph would be the line (y = x-2) with a hole at ((-2, -4)).
  • Graphical implication (as per the transcript, noting the inconsistencies):
    • The lecturer claimed the graph is basically the line (y = x-2) with a hole at (x = -2).
    • The lecture also suggested the limit as (x\to -2) has a particular value (described as approaching 4 in the spoken notes), which is inconsistent with the corrected algebraic interpretation. The correct limit for the corrected cancellation scenario would be the y-value of the line at (x = -2), i.e. (f(x)\to -4) if the simplification were valid, but note that the actual function as written does not simplify this way.
  • Key takeaway: a removable discontinuity (a hole) can occur when a factor cancels in a simplified form, but only if the cancellation is valid; in the given transcript, the algebraic step is not valid for the stated function.

What a limit is, using the graphical approach

  • The limit is the y-value that you can get arbitrarily close to by taking x-values sufficiently close to a.
  • As a concrete guide:
    • If you take values of x that approach a (from the left, from the right, or from both), the corresponding y-values f(x) approach some number L.
    • If both one-sided approaches yield the same L, then
      limxaf(x)=L.\lim_{x\to a} f(x) = L.
    • If the one-sided approaches yield different values, the limit does not exist.
  • Example discussions from the transcript:
    • When the limit at a point is discussed, the teacher often uses a case where the function is not defined at that point, yet a limit still exists.
    • A particular claim in the transcript: "What is the limit as x goes to 0? 3." This is presented as a conclusion in the lecture, though later comments show some inconsistency with the algebraic form used in that example.
  • Emphasis from the transcript:
    • The limit focuses on what happens very close to the point (on the x-axis side near a) and ignores distant values.
    • The limit can exist even if the function is undefined at the point or even if the function value at the point is something else.

One-sided limits, and why they matter

  • Notation:
    • Left-hand limit: limxaf(x)=L.\lim_{x\to a^-} f(x) = L^-.
    • Right-hand limit: limxa+f(x)=L+.\lim_{x\to a^+} f(x) = L^+.
  • Interpretation:
    • Approaching from the left means using x-values slightly less than a (x < a).
    • Approaching from the right means using x-values slightly greater than a (x > a).
  • Why the distinction exists:
    • If the left-hand and right-hand limits are the same, the (two-sided) limit exists and equals that common value.
    • If they differ, the limit does not exist.
  • The transcript’s illustrative narrative:
    • It discusses approaching x = -2 from the left and from the right and notes that, for some graphs, the left-hand limit and right-hand limit can be different (a jump discontinuity).
    • It emphasizes that the limit, when it exists, is unique.
  • Practical takeaway:
    • Always consider both one-sided limits to determine whether a two-sided limit exists.

Discontinuities and the role of the function value

  • Different possibilities at a point x = a:
    • Case A (continuous): the limit exists and equals f(a).
    • Case B (removable): the limit exists, but f(a) is not equal to the limit (often f(a) is undefined or defined differently).
    • Case C (discontinuous with jump): the left-hand and right-hand limits exist but are not equal; hence the two-sided limit does not exist.
    • Case D (infinite limit / vertical asymptote): the limit diverges to (+\infty) or (-\infty) as x approaches a.
  • Transcript-specific illustration:
    • At x = -2, the function value is given as f(-2) = 3, but the limit as x approaches -2 does not exist due to a jump (left-hand and right-hand limits differ).
  • Conceptual consequence:
    • If a limit exists, it is unique. If it does not exist, you typically have either a jump or an infinite behavior.

Worked ideas and notational clarifications from the transcript

  • The speaker introduces the idea that as x approaches a, f(x) approaches a limit L, which is a fundamental notion for defining derivatives and integrals later.
  • They emphasize the distinction between approaching a from the left vs from the right and the corresponding one-sided limits.
  • They highlight several qualitative scenarios with graphs:
    • A smooth graph where the limit exists and equals the function value (continuous).
    • A graph with a hole at a but the limit exists (removable discontinuity).
    • A graph with a jump at a where the left and right limits differ (no two-sided limit).
    • A graph with a vertical asymptote where the limit diverges to infinity.
  • Heuristic remark:
    • If the two one-sided limits agree, the limit exists and is the common value. If not, the limit does not exist.

Quick practice concepts and reminders from the transcript

  • It is common to check limits graphically first, then prove algebraically (factorization, simplification) in a follow-up step.
  • One should be careful with algebraic manipulations that seem to cancel factors; ensure the cancellation is valid for the given numerator and denominator.
  • Always distinguish between the limit of f(x) as x approaches a and the value f(a) itself.
  • Infinite limits and vertical asymptotes require recognizing that the limit does not exist in the finite sense (the values blow up without bound).
  • The transcript contains personal anecdotes (e.g., about AP Calculus), illustrating that students may be navigating long gaps since last exposure to limits; use these as motivation to review definitions (limits, one-sided limits, continuity).

Quick glossary of symbols and concepts (as used in the transcript)

  • Limit at a point: limxaf(x)=L\lim_{x\to a} f(x) = L
  • One-sided limit from the left: limxaf(x)=L\lim_{x\to a^-} f(x) = L^-
  • One-sided limit from the right: limxa+f(x)=L+\lim_{x\to a^+} f(x) = L^+
  • Definition of a limit existence: left-hand limit and right-hand limit must agree, i.e., L^- = L^+.
  • Continuity at a point: limxaf(x)=f(a)\lim_{x\to a} f(x) = f(a)
  • Removable discontinuity: the limit exists but f(a) != lim_{x\to a} f(x) (or f(a) undefined while the limit exists).
  • Jump discontinuity: the limit does not exist because L^- != L^+.
  • Infinite limit (vertical asymptote): the limit diverges to (+\infty) or (-\infty).

Note for study planning

  • The transcript contains a few algebraic misstatements (e.g., incorrect factoring leading to an asserted cancellation). When studying, verify algebraic steps carefully:
    • If you ever see a cancellation like (\dfrac{2x^2 - 4}{x+2} = x-2), check the numerator factoring: (2x^2 - 4 = 2(x^2 - 2)), not ((x+2)(x-2)).
    • For a function like (\dfrac{x^2 - 4}{x+2}), the cancellation is valid and yields (x-2) for (x\neq -2); the graph would be a line minus the point ((-2, -4)).
  • Always connect the graphical intuition with the formal definitions to avoid inconsistencies between what a graph shows and what an algebraic manipulation might imply.