Integral Evaluation Overview
This section presents various integrals to be evaluated using the substitution method, also known as u-substitution. Each integral is denoted with a specific letter for easy reference.
Integral (a)
Evaluate the integral:
∫(x2+5)48xdx
Steps for Evaluation
Substitution: Let ( u = x^2 + 5 ).
Derivative: Then, ( du = 2x \, dx or dx = \frac{du}{2x} </p></li><li><p><strong>ChangeofVariables:</strong>Substitute(x2=u−5),thustheintegraltransformsinto(∫u48x2xdu=∫u44du).</p></li><li><p><strong>IntegralResult:</strong>Theintegralcannowbeevaluatedas(−3u34+C),where(C)istheconstantofintegration.</p></li><li><p><strong>BackSubstitute:</strong>Resubstituting(u)givesthefinalanswer.</p></li></ul><h4>Integral(b)</h4><p>Evaluatetheintegral:<br>\int (3\cos(3x) + 7) e^{\sin(3x)} \, dx</p><h5>StepsforEvaluation</h5><ul><li><p><strong>Substitution:</strong>Let(u=sin(3x)),then(du=3cos(3x)dx or dx=3cos(3x)du).</p></li><li><p><strong>ChangeoftheIntegral:</strong>Theintegraltransformsto(∫(1+3cos(3x)7eu)du alongside the term for ( 3\cos(3x) ).
Integral (c)
Evaluate the integral:
∫1+tan2(4x)sec2(4x)dx
Steps for Evaluation
Integral (d)
Evaluate the integral:
∫−4xdx
Steps for Evaluation
Integral (e)
Evaluate the integral:
∫cos(60)1(2−sin(60))7dx
Steps for Evaluation
Integral (f)
Evaluate the integral:
∫(2x2+9)dx
Steps for Evaluation
Integral (g)
Evaluate the integral:
∫sin3(t)cos(t)dt
Steps for Evaluation
Substitution: Let ( u = \sin(t), du = \cos(t) \, dt).
Transforming Integral: This leads to the integral ( \int u^3 \, du).
Evaluating: Results in ( \frac{1}{4} u^4 + C = \frac{1}{4} \sin^4(t) + C ).
Integral (h)
Evaluate the integral:
∫(3x+1)5dx
Steps for Evaluation
Substitution: Let ( u = 3x + 1 ), ( du = 3 \, dx), therefore ( dx = \frac{du}{3} .
Transforming the Integral: The new integral is ( \int u^5 \frac{du}{3} = \frac{1}{18} u^6 + C).
Back Substitute: Resubstitute for ( u ) to get final answer.
Integral (i)
Evaluate the integral:
∫x3+23x2dx
Steps for Evaluation
Substitution: Let ( u = x^3 + 2 \, then ( du = 3x^2 \, dx), thus simply ( \int \frac{1}{u} du = \ln|u| + C).
Integral (j)
Evaluate the integral:
∫sin(20)cos(20)dx
Steps for Evaluation
Integral (k)
Evaluate the integral:
∫(2x+5)46dx
Steps for Evaluation
Substitution: Let ( u = 2x + 5, \quad du = 2dx \quad or \quad dx = \frac{du}{2})
Evaluating Integral: This becomes ( \int 3u^{-4} du = -\frac{3}{3u^3} + C.</p></li><li><p><strong>BackSubstitute:</strong>Replace(u)withtheoriginalvariableforthefinalanswer.</p></li></ul><h4>Integral(l)</h4><p>Evaluatetheintegral:<br>\int \frac{\cos(0)}{4 - \sin^2(0)} \, dx</p><h5>StepsforEvaluation</h5><ul><li><p><strong>ConstantEvaluation:</strong>Calculateconstantstosimplifytheintegral.Discussimplicationsofundefinedsegmentsinthefunctionanalysis.</p></li></ul><h4>Integral(m)</h4><p>Evaluatetheintegral:<br>\int \frac{2 \sin(2x)}{3 + \cos(2x)} \, dx</p><h5>StepsforEvaluation</h5><ul><li><p><strong>Substitution:</strong>Let(u=cos(2x);du=−2sin(2x)dx),leadingto(−∫3+u1du).</p></li></ul><h4>Integral(n)</h4><p>Evaluatetheintegral:<br>\int \frac{(x + 4)^{3/2}}{5x} \, dx</p><h5>StepsforEvaluation</h5><ul><li><p><strong>SimplifyingExpression:</strong>Tosimplifytheintegral,breakitdownasfractionsorequivalentcompositeterms.</p></li></ul><h4>Integral(o)</h4><p>Evaluatetheintegral: \int (x^2 - 6)^6 \, dx $$
Steps for Evaluation
Conclusion
Each integral requires a detailed exploration of the u-substitution method, integrating both the algebraic manipulations and crucial evaluations for accuracy. Make sure to back substitute wherever necessary for deriving the final results accurately.