Vector Representations and Addition (Polar, Unit Vectors, and Addition)

Polar form and vector notation

  • Vectors can be expressed in at least two common ways: polar form and Cartesian (component) form. It’s useful to be familiar with both and know how to move between them.
  • The polar approach emphasizes magnitude and direction, while Cartesian form emphasizes horizontal and vertical components.
  • Notation choice is flexible; you can adopt the convention that best fits the problem or the course.

Unit vectors and directionality

  • A unit vector carries direction but has unit magnitude. It serves as a directional indicator.
  • If you have a vector \vec{v}, the unit vector in its direction is
    v^=vv,\hat{v} = \frac{\vec{v}}{|\vec{v}|},
    provided that v0|\vec{v}| \neq 0.
  • Common unit vectors in 2D are i^\hat{i} (x-direction) and j^\hat{j} (y-direction). Any vector can be written as a linear combination of these:
    v=v<em>xi^+v</em>yj^.\vec{v} = v<em>x\hat{i} + v</em>y\hat{j}.
  • In 3D, add k^\hat{k} for the z-direction: v=v<em>xi^+v</em>yj^+vzk^.\vec{v} = v<em>x\hat{i} + v</em>y\hat{j} + v_z\hat{k}.

Trigonometric foundations for vectors

  • Vectors relate to right triangles via the standard trigonometric relationships: cosine, sine, and their projections onto axes.
  • If a vector makes an angle θ\theta with the positive x-axis, its Cartesian components are
    v<em>x=vcosθ,v</em>y=vsinθ.v<em>x = |\vec{v}| \cos\theta, \quad v</em>y = |\vec{v}| \sin\theta.
  • Magnitude of the vector is
    v=v<em>x2+v</em>y2.|\vec{v}| = \sqrt{v<em>x^2 + v</em>y^2}.
  • These relationships underpin both polar and Cartesian representations.

Polar form of a vector in 2D

  • In polar form, a vector with magnitude $r$ and angle θ\theta is written as
    v=r(cosθi^+sinθj^).\vec{v} = r(\cos\theta \,\hat{i} + \sin\theta \,\hat{j}).
  • Equivalently, its Cartesian coordinates are
    x=rcosθ,y=rsinθ.x = r \cos\theta, \quad y = r \sin\theta.
  • The magnitude-angle pair (r,θ)(r,\theta) is not unique because adding 2π2\pi to the angle represents the same direction; be mindful of angle conventions.

Component form and magnitude-angle conversion

  • Given v=v<em>xi^+v</em>yj^,\vec{v} = v<em>x\hat{i} + v</em>y\hat{j}, the magnitude and direction are
    v=v<em>x2+v</em>y2, and  tanθ=v<em>yv</em>x.|\vec{v}| = \sqrt{v<em>x^2 + v</em>y^2}, \ \text{and}\ \ \tan\theta = \frac{v<em>y}{v</em>x}.
  • Conversely, if you know the magnitude and angle, you can recover components via
    v<em>x=vcosθ, v</em>y=vsinθ.v<em>x = |\vec{v}| \cos\theta, \ v</em>y = |\vec{v}| \sin\theta.

Vector addition: two vectors and multiple vectors

  • Graphical view: add vectors head-to-tail to obtain a resultant vector.
  • Algebraic view: add components componentwise:
    • For two vectors, a=a<em>xi^+a</em>yj^,b=b<em>xi^+b</em>yj^\vec{a} = a<em>x\hat{i} + a</em>y\hat{j}, \vec{b} = b<em>x\hat{i} + b</em>y\hat{j}
      a+b=(a<em>x+b</em>x)i^+(a<em>y+b</em>y)j^.\vec{a} + \vec{b} = (a<em>x + b</em>x)\hat{i} + (a<em>y + b</em>y)\hat{j}.
  • For multiple vectors, the resultant is
    R=<em>k=1nv</em>k=<em>k=1n(v</em>kxi^+v<em>kyj^)=(</em>k=1nv<em>kx)i^+(</em>k=1nvky)j^.\vec{R} = \sum<em>{k=1}^{n} \vec{v}</em>k = \sum<em>{k=1}^{n} (v</em>{kx}\hat{i} + v<em>{ky}\hat{j}) = \left(\sum</em>{k=1}^{n} v<em>{kx}\right)\hat{i} + \left(\sum</em>{k=1}^{n} v_{ky}\right)\hat{j}.
  • Magnitude of the sum of two vectors (using the angle between them, \theta):
    a+b2=a2+b2+2abcosθ,|\vec{a} + \vec{b}|^2 = |\vec{a}|^2 + |\vec{b}|^2 + 2|\vec{a}||\vec{b}| \cos\theta,
    where θ\theta is the angle between the two vectors.
  • If you know components, you can also compute directly: a+b=(a<em>x+b</em>x)2+(a<em>y+b</em>y)2.|\vec{a} + \vec{b}| = \sqrt{(a<em>x + b</em>x)^2 + (a<em>y + b</em>y)^2}.

Law of cosines and its role in vectors

  • Law of cosines (triangle form): for a triangle with sides $a$, $b$, and $c$ opposite angle γ\gamma between sides $a$ and $b$,
    c2=a2+b22abcosγ.c^2 = a^2 + b^2 - 2ab \cos\gamma.
  • In vector addition, if you consider the two sides a|\vec{a}| and b|\vec{b}| with included angle θ\theta between them, the resultant side (the magnitude of a+b\vec{a} + \vec{b}) satisfies
    a+b2=a2+b2+2abcosθ.|\vec{a} + \vec{b}|^2 = |\vec{a}|^2 + |\vec{b}|^2 + 2|\vec{a}||\vec{b}| \cos\theta.
  • The angle between vectors also relates to the dot product:
    cosθ=abab, with ab=a<em>xb</em>x+a<em>yb</em>y.\cos\theta = \frac{\vec{a} \cdot \vec{b}}{|\vec{a}||\vec{b}|}, \ \text{with} \ \vec{a} \cdot \vec{b} = a<em>x b</em>x + a<em>y b</em>y.
  • Triangle area relation (useful in some vector problems):
    Area=12absinθ.\text{Area} = \frac{1}{2} |\vec{a}| |\vec{b}| \sin\theta.

Equality of vectors and what it means

  • Two vectors are equal if and only if they have the same magnitude and direction:
    a=b    a=b and aa=bb.\vec{a} = \vec{b} \iff |\vec{a}| = |\vec{b}| \text{ and } \frac{\vec{a}}{|\vec{a}|} = \frac{\vec{b}}{|\vec{b}|}.
  • In component form, equality also means matching components: a<em>x=b</em>xanda<em>y=b</em>y.a<em>x = b</em>x \quad\text{and}\quad a<em>y = b</em>y.
  • If two Cartesian representations are equal, their polar representations are also consistent (and vice versa) after converting between forms.

Worked example (illustrative)

  • Given vectors in 2D:
    • \vec{a} with magnitude a=5|\vec{a}| = 5 and direction θa=30\theta_a = 30^{\circ}.
    • \vec{b} with magnitude b=4|\vec{b}| = 4 and direction θb=120\theta_b = 120^{\circ}.
  • Components:
    • ax=5cos30=5324.33,a_x = 5\cos 30^{\circ} = 5\cdot\frac{\sqrt{3}}{2} \approx 4.33,
    • ay=5sin30=512=2.50.a_y = 5\sin 30^{\circ} = 5\cdot\frac{1}{2} = 2.50.
    • bx=4cos120=4(12)=2.00,b_x = 4\cos 120^{\circ} = 4\left(-\tfrac{1}{2}\right) = -2.00,
    • by=4sin120=4(32)3.46.b_y = 4\sin 120^{\circ} = 4\left(\frac{\sqrt{3}}{2}\right) \approx 3.46.
  • Resultant:
    • R<em>x=a</em>x+bx4.332.00=2.33,R<em>x = a</em>x + b_x \approx 4.33 - 2.00 = 2.33,
    • R<em>y=a</em>y+by2.50+3.46=5.96.R<em>y = a</em>y + b_y \approx 2.50 + 3.46 = 5.96.
    • Magnitude: R=R<em>x2+R</em>y22.332+5.9626.40.|\vec{R}| = \sqrt{R<em>x^2 + R</em>y^2} \approx \sqrt{2.33^2 + 5.96^2} \approx 6.40.
    • Direction: θ<em>R=tan1(R</em>yRx)tan1(2.56)68.2.\theta<em>R = \tan^{-1}\left(\frac{R</em>y}{R_x}\right) \approx \tan^{-1}(2.56) \approx 68.2^{\circ}.
  • This illustrates how polar and Cartesian forms connect and how the magnitude and direction of the sum are obtained from components.

Practical implications and connections

  • Graphical intuition (head-to-tail) complements algebraic methods; both are valid and often used together.
  • The polar form is convenient for problems with angles and rotations; Cartesian form is straightforward for addition and projections on axes.
  • These concepts underpin physics (forces, velocities), engineering (resultants, trajectories), and computer graphics (vector operations).
  • Be mindful of notation choices (units, directions, sign conventions) to avoid errors, especially when converting between forms.
  • Ethical and practical considerations: accurate vector modeling is essential in design, navigation, and safety-critical systems; misinterpretation of angles or units can lead to incorrect results or hazards.

Quick references: key formulas to memorize

  • Polar to Cartesian components:
    x=rcosθ,y=rsinθ, v=xi^+yj^=r(cosθi^+sinθj^).x = r \cos\theta, \quad y = r \sin\theta, \ \vec{v} = x\hat{i} + y\hat{j} = r(\cos\theta \,\hat{i} + \sin\theta \,\hat{j}).
  • Magnitude and direction from components:
    v=v<em>x2+v</em>y2,θ=tan1(v<em>yv</em>x).|\vec{v}| = \sqrt{v<em>x^2 + v</em>y^2}, \qquad \theta = \tan^{-1}\left(\frac{v<em>y}{v</em>x}\right).
  • Component form of a vector: v=v<em>xi^+v</em>yj^.\vec{v} = v<em>x\hat{i} + v</em>y\hat{j}.
  • Equality of vectors (component form): a=b    a<em>x=b</em>x and a<em>y=b</em>y.\vec{a} = \vec{b} \iff a<em>x = b</em>x \text{ and } a<em>y = b</em>y.
  • Sum of multiple vectors: R=<em>k=1nv</em>k=(<em>k=1nv</em>kx)i^+(<em>k=1nv</em>ky)j^.\vec{R} = \sum<em>{k=1}^{n} \vec{v}</em>k = (\sum<em>{k=1}^{n} v</em>{kx})\hat{i} + (\sum<em>{k=1}^{n} v</em>{ky})\hat{j}.
  • Magnitude of sum (two vectors) with angle between them:
    a+b2=a2+b2+2abcosθ.|\vec{a} + \vec{b}|^2 = |\vec{a}|^2 + |\vec{b}|^2 + 2|\vec{a}||\vec{b}| \cos\theta.
  • Dot product and angle between vectors:
    ab=a<em>xb</em>x+a<em>yb</em>y,cosθ=abab.\vec{a} \cdot \vec{b} = a<em>x b</em>x + a<em>y b</em>y, \quad \cos\theta = \frac{\vec{a} \cdot \vec{b}}{|\vec{a}||\vec{b}|}.