Modeling Atoms, Atomic Emission Spectra, and Bohr's Model

Fundamentals of Atomic Structure and Subatomic Particles

  • Subatomic Particle Characteristics:

    • Protons: Positively charged subatomic particles located within the dense central nucleus. Each proton carries a relative charge of +1+1 and a relative mass of approximately 1 amu1\,\text{amu}.
    • Neutrons: Uncharged (neutral) subatomic particles residing inside the nucleus. Each neutron carries a relative charge of 00 and a relative mass of approximately 1 amu1\,\text{amu}.
    • Electrons: Negatively charged subatomic particles occupying the electron cloud or energy levels surrounding the nucleus. Each electron carries a relative charge of −1-1 and has a negligible mass (approximately 11836 amu\frac{1}{1836}\,\text{amu}).
  • Distribution of Atomic Mass and Volume:

    • Mass Distribution: The nucleus, containing protons and neutrons, accounts for virtually all (>99.9%> 99.9\%) of an atom's mass.
    • Volume Distribution: The electron cloud, where electrons orbit the nucleus, accounts for virtually all of an atom's physical volume.
  • Concept of a Neutral Atom:

    • An atom is electrically neutral when the total positive charge of its protons equals the total negative charge of its electrons.
    • Condition for Neutrality:     Net Charge=Protons−Electrons=0\text{Net Charge} = \text{Protons} - \text{Electrons} = 0
    • To create a neutral atom, the number of electrons orbiting the nucleus must equal the exact number of protons present inside the nucleus.

Chemical Identification, Atomic Numbers, and Chemical Symbols

  • Atomic Number (ZZ) as a Unique Identifier:

    • The atomic number (ZZ) represents the number of protons in an atom's nucleus.
    • The atomic number dictates the fundamental identity of an element. No two different elements share the same atomic number.
    • In a neutral atom, the atomic number correlates directly with both the proton count and the electron count:     Atomic Number (Z)=Number of Protons=Number of Electrons\text{Atomic Number } (Z) = \text{Number of Protons} = \text{Number of Electrons}
  • Subatomic Structure of Selected Elements:

    • Helium (HeHe): Atomic number Z=2Z = 2. A neutral helium atom contains 2 protons and 2 electrons.
    • Carbon (CC): Atomic number Z=6Z = 6. A neutral carbon atom contains 6 protons and 6 electrons.
    • Fluorine (FF): Atomic number Z=9Z = 9. A neutral fluorine atom contains 9 protons, 9 electrons, and 10 neutrons (for Fluorine-19, mass number A=19A = 19).
    • Silver (AgAg): Atomic number Z=47Z = 47. A neutral silver atom contains 47 protons and 47 electrons.
    • Iodine (II): Atomic number Z=53Z = 53. A neutral iodine atom contains 53 protons, 53 electrons, and 74 neutrons (for Iodine-127, mass number A=127A = 127).
  • Chemical Symbols and Formulas:

    • Elements are represented by chemical symbols consisting of one capitalized letter (e.g., HH for Hydrogen, OO for Oxygen, CC for Carbon) or a capitalized letter followed by a lowercase letter (e.g., HeHe for Helium, CuCu for Copper, SiSi for Silicon, BrBr for Bromine).
    • Chemical formulas represent compounds by combining elemental symbols with numerical subscripts that indicate the ratio of atoms present (e.g., H2OH_2O for water, indicating 2 hydrogen atoms bonded to 1 oxygen atom).

Light Emission Phenomena: Neon Signs vs. Fireworks

  • Atomic Mechanism of Light Emission:
    1. Electron Excitation: Atoms or ions absorb external energy (electrical or thermal). This input of energy promotes electrons from a lower energy level (ground state) to a higher energy level (excited state).
    2. Emission of Light: Because the excited state is unstable, electrons rapidly drop back down to lower energy levels. As they transition downward, they release energy in the form of visible light photons. The energy difference between the levels determines the specific color and wavelength of light emitted.

Bohr electron shell structures for noble gases Helium, Neon, and Argon

  • Comparison Between Neon Signs and Fireworks:   | Aspect | Neon Signs | Fireworks |   | :--- | :--- | :--- |   | Source of Energy | Electrical energy excites neon atoms inside a sealed glass tube. | Thermal energy from burning gunpowder excites metal atoms/ions in chemical salts. |   | Type of Atoms / Compounds | Noble gases (e.g., Neon →\rightarrow red-orange light, Argon →\rightarrow blue light, Krypton →\rightarrow white light). | Metal salts (e.g., Strontium salts →\rightarrow red light, Copper salts →\rightarrow blue light, Sodium salts →\rightarrow yellow light). |   | Light Emission Process | Continuous, steady glow sustained as long as electrical current flows. | Brief, intense flashes of light emitted during explosive chemical reactions. |

Isotopes and Isotopic Charge Equivalence

  • Definition of Isotopes:
    • Isotopes are atoms of the same chemical element that possess the exact same number of protons (same atomic number ZZ) but different numbers of neutrons in their nuclei, leading to distinct mass numbers (AA).

Isotopes of Oxygen showing Oxygen 16, Oxygen 17, and Oxygen 18 subatomic compositions

  • Isotopic Models of Oxygen:

    • Oxygen-16 (16O^{16}\text{O}): Contains 8 Protons, 8 Electrons, and 8 Neutrons (A=16 amuA = 16\,\text{amu}).
    • Oxygen-17 (17O^{17}\text{O}): Contains 8 Protons, 8 Electrons, and 9 Neutrons (A=17 amuA = 17\,\text{amu}).
    • Oxygen-18 (18O^{18}\text{O}): Contains 8 Protons, 8 Electrons, and 10 Neutrons (A=18 amuA = 18\,\text{amu}).
  • Explanation of Charge Equivalence:

    • The overall charge of an atom depends exclusively on the balance between positive protons and negative electrons.
    • For Oxygen-16: Net Charge=(+8)+(−8)=0\text{Net Charge} = (+8) + (-8) = 0
    • For Oxygen-17: Net Charge=(+8)+(−8)=0\text{Net Charge} = (+8) + (-8) = 0
    • For Oxygen-18: Net Charge=(+8)+(−8)=0\text{Net Charge} = (+8) + (-8) = 0
    • Neutrons carry zero electrical charge. Adding or subtracting neutrons alters the mass of the nucleus, but leaves the net charge unchanged.

Natural Abundance and Average Atomic Mass Calculations

  • Concept of Natural Abundance:

    • Natural abundance refers to the percentage of each naturally occurring isotope of an element found in nature.
  • Average Atomic Mass Formula:   Average Atomic Mass=(m1×f1)+(m2×f2)+⋯+(mn×fn)\text{Average Atomic Mass} = (m_1 \times f_1) + (m_2 \times f_2) + \dots + (m_n \times f_n)   Where:

    • m1,m2,…m_1, m_2, \dots are the precise masses of individual isotopes (in amu\text{amu}).
    • f1,f2,…f_1, f_2, \dots are fractional abundances, calculated as:     fi=Percent Abundance100f_i = \frac{\text{Percent Abundance}}{100}
  • Isotopic Natural Abundance Reference Data:   | Element | Isotope | Abundance [%] |   | :--- | :--- | :--- |   | Hydrogen | 1H^{1}\text{H} | 99.985%99.985\% |   | Hydrogen | 2H^{2}\text{H} | 0.015%0.015\% |   | Oxygen | 16O^{16}\text{O} | 99.76%99.76\% |   | Oxygen | 17O^{17}\text{O} | 0.04%0.04\% |   | Oxygen | 18O^{18}\text{O} | 0.2%0.2\% |   | Carbon | 12C^{12}\text{C} | 98.9%98.9\% |   | Carbon | 13C^{13}\text{C} | 1.1%1.1\% |

  • Step-by-Step Practice Problems:

    • Problem 1: Calculate the average atomic mass of Silicon (SiSi) given three isotopes:
    • Silicon-28: Mass = 27.9769 amu27.9769\,\text{amu}, Abundance = 92.2297%92.2297\% (f1=0.922297f_1 = 0.922297)
    • Silicon-29: Mass = 28.9765 amu28.9765\,\text{amu}, Abundance = 4.6832%4.6832\% (f2=0.046832f_2 = 0.046832)
    • Silicon-30: Mass = 29.9738 amu29.9738\,\text{amu}, Abundance = 3.0872%3.0872\% (f3=0.030872f_3 = 0.030872)

    Solution Calculation:     Average Mass=(27.9769×0.922297)+(28.9765×0.046832)+(29.9738×0.030872)\text{Average Mass} = (27.9769 \times 0.922297) + (28.9765 \times 0.046832) + (29.9738 \times 0.030872)Average Mass=25.80302+1.35703+0.92535\text{Average Mass} = 25.80302 + 1.35703 + 0.92535Average Mass=28.0854 amu\text{Average Mass} = 28.0854\,\text{amu}

  • Problem 2: Bromine (BrBr) has two naturally occurring isotopes. Bromine-79 has a mass of 78.918 amu78.918\,\text{amu} and an abundance of 50.69%50.69\%. Using the periodic table atomic mass (79.904 amu79.904\,\text{amu}), determine the mass of Bromine-81.

    Solution Calculation: - Calculate fractional abundance of Bromine-81:       fBr-81=1.0000−0.5069=0.4931f_{\text{Br-81}} = 1.0000 - 0.5069 = 0.4931 - Set up the average mass equation:       79.904=(78.918×0.5069)+(mBr-81×0.4931)79.904 = (78.918 \times 0.5069) + (m_{\text{Br-81}} \times 0.4931)79.904=40.0035+(0.4931×mBr-81)79.904 = 40.0035 + (0.4931 \times m_{\text{Br-81}})0.4931×mBr-81=79.904−40.0035=39.90050.4931 \times m_{\text{Br-81}} = 79.904 - 40.0035 = 39.9005mBr-81=39.90050.4931=80.918 amum_{\text{Br-81}} = \frac{39.9005}{0.4931} = 80.918\,\text{amu}

Atomic Emission Spectra and Spectroscopic Analysis

  • Generation of Atomic Emission Spectra:
    • An atomic emission spectrum consists of the specific set of light wavelengths emitted by an element when its excited electrons transition back down to lower energy levels.

Atomic Emission Spectra showing ground state absorption, excitation, and light emission

  • Ground State vs. Excited State:

    • Ground State: The lowest stable energy state of an atom where electrons reside in the lowest available orbitals.
    • Excited State: An unstable higher energy state reached when an electron absorbs discrete energy.
    • When falling back to lower states, electrons release energy as photons of specific light wavelengths.
  • Elemental Fingerprints:

    • Every element possesses a distinct nuclear charge and electron configuration, resulting in unique spacing between its electron energy levels.
    • Consequently, each element produces a unique emission spectrum that acts as an "elemental fingerprint," enabling scientists to identify unknown substances by analyzing their emission patterns.
  • Function of a Spectroscope and Wavelength Ranges:

    • A spectroscope uses an optical prism or diffraction grating to separate emitted light into its component wavelengths.

Spectroscope dispersing light source through a prism into visible light spectrum wavelengths

  • Visible Light Spectrum Wavelength Ranges:
    • Violet: 380–450 nm380\text{--}450\,\text{nm}
    • Blue: 450–495 nm450\text{--}495\,\text{nm}
    • Green: 495–570 nm495\text{--}570\,\text{nm}
    • Yellow: 570–590 nm570\text{--}590\,\text{nm}
    • Orange: 590–620 nm590\text{--}620\,\text{nm}
    • Red: 620–750 nm620\text{--}750\,\text{nm}

The Bohr Model of the Atom and Quantized Energy Levels

  • Principles of Bohr's Atomic Model (1913):
    • Proposed by Niels Bohr in 1913.
    • Describes electrons as revolving around the central nucleus in fixed, defined circular orbits or shells.

Bohr's Atomic Model depicting nucleus, shell energy levels K, L, M, N, and photon emission

  • Orbital Shell Designations and Energy Hierarchy:

    • Electron orbits are designated as KK (n=1n=1), LL (n=2n=2), MM (n=3n=3), and NN (n=4n=4).
    • The further an orbital shell is situated from the nucleus, the higher its energy level (EK<EL<EM<ENE_K < E_L < E_M < E_N).
  • Quantized Energy Transitions and Photon Emission:

    • Energy levels are quantized: electrons can exist only on specific energy orbits and cannot reside between orbits.
    • When an electron jumps from a higher energy orbital to a lower energy orbital, the energy difference is emitted as a photon:     ΔE=Ehigher−Elower=hν=hcλ\Delta E = E_{\text{higher}} - E_{\text{lower}} = h\nu = \frac{hc}{\lambda}
    • Larger energy drops emit photons with higher energy, higher frequency, and shorter wavelengths (e.g., violet light).
    • Smaller energy drops emit photons with lower energy, lower frequency, and longer wavelengths (e.g., red light).
  • Law of Conservation of Mass & Energy:

    • In atomic energy transitions, energy cannot be created or destroyed.
    • The total energy absorbed by an electron during excitation exactly equals the photon energy released during emission.