MicroBio
Filtration Methodology in Microbiology
Filtration Process
A sample is filtered through a membrane filter with pores too small for bacteria to pass.
The process involves filtering a known liquid sample through a special filter paper.
Bacteria and cells are retained on the filter paper, while a sterile liquid passes through.
After filtration, the filter paper is placed on an agar medium to allow colonies to grow over 24 to 48 hours.
Once colonies grow, enumeration takes place.
Example of Filtration
Sample Type: Seawater, with a known volume of 100 mL filtered.
Outcome: After incubation, 20 colonies were observed.
Calculation of CFU (Colony Forming Units):
CFUs per 100 mL: [ CFU = \frac{20}{100} = 0.2 \text{ CFUs/mL} ]
Proper display: 20 CFUs per 100 mL.
Media Characteristics
MacConkey Agar
Purpose: Selective for Gram-negative bacteria; differentiates lactose fermenters.
Growth Indicators:
Lactose fermenters (e.g., E. coli) appear red due to acid production.
Non-fermenters (e.g., Salmonella) appear colorless.
CFU Calculation:
After filtering 100 mL of sample, if 10 red colonies and 5 colorless colonies were observed:
For lactose fermenting bacteria: [ CFU = \frac{10}{100} = 0.1 \text{ CFUs/mL} ]
Thus, 10 CFUs per 100 mL saline water.
Recall: Total reflects that both types observed are Gram-negative as both colonies grew on MacConkey agar.
Most Probable Number (MPN) Method
Application: Common for analyzing food and water samples.
Setup: 3 sets of 5 tubes (1 set: 10 mL, 2nd set: 1 mL, 3rd set: 0.1 mL of sample added).
Each set tests for (+) fermentation of sugar, indicated by gas production (airspace in tubes).
Results Interpretation: Count positives in each set. For example:
First set (10 mL): 4 positives
Second set (1 mL): 3 positives
Third set (0.1 mL): 1 positive.
MPN Calculation: Use a provided statistical table for the combination of observed positives to find MPN index per 100 mL.
Example: If the combination is 4-3-1, corresponding MPN index = 33.
Other MPN Scenarios:
Initial results colored red; after incubation, positive results turned yellow, indicating growth (fermentation).
Example Observations:
500 pattern: 5 positives in the first, 0 in the second, 0 in the third = MPN index of 23.
Indirect Growth Measurement
Turbidity Method:
Measures cloudiness using a spectrophotometer.
Relationship: Higher turbidity reflects more bacterial growth.
Process:
Clear (uninoculated) samples allow light transmission; turbid (inoculated) samples scatter light.
Key Definitions: Absorbance relates directly to cell concentration; higher absorbance indicates greater bacterial density.
Bacterial Genetics Overview
DNA Structure:
Definitions:
DNA (deoxyribonucleic acid) vs. RNA (ribonucleic acid):
DNA has deoxyribose sugar; RNA has ribose.
DNA includes nitrogenous bases: adenine, thymine, cytosine, guanine.
RNA includes adenine, cytosine, guanine, uracil (thymine is absent).
DNA is double-stranded, forming a double helix structure.
Base Pairing:
Adenine pairs with Thymine (A-T); Cytosine pairs with Guanine (C-G).
Antiparallel nature of strands: one strand runs 5' to 3', the other 3' to 5'.
Counting Nucleotides Example: Given a strand with specific nucleotides, the complementary strand can be derived according to base-pairing rules.
Genome Characteristics
Genomic Differences:
Prokaryotic vs. Eukaryotic Genomes:
Prokaryotes (bacteria and archaea) typically have a single, circular chromosome and are haploid.
Eukaryotes have multiple linear chromosomes and are diploid.
Chromosomal Packaging:
Bacterial DNA is supercoiled to fit within the small cell, and eukaryotic DNA is wrapped with histones.
DNA Replication Process in Bacteria
Key Terms:
Replication Begins: At the origin of replication; proceeds bi-directionally.
Enzymes Involved:
Helicase: Unzips DNA strands.
Primase: Synthesizes RNA primers.
DNA Polymerase:
DNA polymerase III synthesizes new DNA strands; DNA polymerase I replaces RNA primers with DNA.
Ligase: Joins Okazaki fragments.
Semi-Conservative Nature: Each of the new DNA molecules contains one old strand and one new strand.
Exponential Growth: DNA replication doubles the number of DNA molecules in each cycle [ P = B \times 2^n ] where $P$ is the final count and $B$ is the initial count after $n$ replications.
Example Calculation: If the process starts with 1 DNA molecule, after three cycles, the total becomes 8 DNA molecules.
Conversely, if you start with 100 molecules: [ P = 100 \times 2^4 = 1600 \text{ after 4 replications} ]