Gauss's Law and Electric Flux - Comprehensive Study Notes
Electric Flux
- Electric flux is the scalar product of the electric field and the surface area vector perpendicular to the field
- For a flat surface with uniform E and angle θ between E and the surface normal, the flux is Φ_E = E A cosθ
- For a differential area element, dΦ_E = E · dA
- Maximum flux occurs when the surface is perpendicular to the field; flux is zero when the surface is parallel to the field
- If the field varies over the surface, ΦE = ∫S E · dA (surface integral) for the chosen surface
- Units of electric flux: N·m^2/C
- General relation for a small area element: dΦE = E dA cosφ (alternatively, ΦE = E · dA)
Gauss’s Law
- Gauss’s Law relates the total electric flux through a closed surface to the charge enclosed by that surface
- Statement: ∮S E · dA = Qenclosed / ε0
- The total flux through a closed surface can be due to charges inside or outside; Gauss’s Law counts only enclosed charge for the flux value
- Gauss’s Law is most useful when charges have high symmetry (spherical, cylindrical, planar)
- Gaussian surface is an imaginary construct you choose to exploit symmetry; it need not coincide with a real surface
- Blade of intuition: if Q_enclosed = 0, net flux through the closed surface is zero
Charge Densities
- Volume charge density: ρ = Q / V
- Surface charge density: σ = Q / A
- Linear charge density: λ = Q / L
Key Examples and Applications (Gauss’s Law in action)
Example: Field of an Infinite Plane Sheet of Charge
- For an infinite plane with surface charge density σ, the electric field is uniform and does not depend on distance r from the plane
- Magnitude on either side: E = σ / (2 ε0)
- Direction: perpendicular to the plane, away from the plane for σ > 0, toward the plane for σ < 0
- The field is the same on both sides (magnitude) but directed away from the plane on the side where σ is positive
- Note: flux through a pillbox straddling the plane yields ΦE = ∮S E · dA = (σ/ε0) A for the pillbox area A
- Consider a line with linear charge density λ
- Using a cylindrical Gaussian surface of radius r and length L, symmetry gives E perpendicular to the line and constant on the curved surface
- Magnitude: E(r) = λ / (2 π ε0 r)
- Direction: radially outward (or inward for negative λ)
- Flux through curved surface: Φ_E = E × (2π r L) = (λ L) / ε0 → per unit length, λ / ε0
Example: Infinite Conducting Cylinder (Radius R) with Line Charge per Unit Length λ
- Outside the cylinder (r > R): E(r) = λ / (2 π ε0 r)
- Inside the conductor (r < R): E(r) = 0
- Field is perpendicular to surface and radial
- Outside the sphere (r > R): E(r) = (1 / (4 π ε0)) × Q / r^2
- Inside the sphere (r ≤ R): E(r) = (1 / (4 π ε0)) × Q r / R^3
- Rationale: ρ = Q / [(4/3) π R^3] is uniform; enclosed charge scales with r^3, so E ∝ r inside
- If Q is uniformly distributed in a volume of radius R, what is the ratio of E at r = 2R (outside) to E at r = R/4 (inside)?
- Outside at r = 2R: E_out = (1 / (4 π ε0)) × Q / (2R)^2 = Q / (16 π ε0 R^2)
- Inside at r = R/4: E_in = (1 / (4 π ε0)) × Q (R/4) / R^3 = Q / (16 π ε0 R^2)
- Ratio: Eout / Ein = 1
Example: Electrostatic Equilibrium in Conductors
- Electrostatic equilibrium: no net motion of charge within the conductor; charges reside in static positions; charges experience zero net force inside
- Inside a conductor, the electric field is zero: E = 0 everywhere
- Isolated conductor with net charge qc: the charge resides on the surface; the field inside the conductor is zero
- A conductor with a cavity and an internal charge: the inner surface of the cavity carries charge −q to cancel the field in the conductor; the outer surface carries the remainder so that the total charge on the outer surface equals qc + q (depending on the initial charge and cavity charge)
Boundary Conditions and Surface Charges on Conductors
- The field just outside a charged conductor is perpendicular to the surface and has magnitude E_out = σ / ε0 when the field inside is zero
- Boundary condition at a conductor surface: Eout,⊥ − Ein,⊥ = σ/ε0; with Ein = 0, we get Eout,⊥ = σ/ε0
- The surface charge density σ is related to the outward normal field just outside the surface
- If the conductor carries no net charge, the outer surface carries zero net charge; with cavities and inner charges, induced charges adjust accordingly
Charge Distribution – Summary of Common Configurations
- Point charge q at a point: E(r) = q / (4 π ε0 r^2)
- Point charge on the surface of a conducting sphere (radius R): outside sphere (r > R): E(r) = q / (4 π ε0 r^2); inside (r < R): E = 0
- Infinite line with linear density λ: E(r) = λ / (2 π ε0 r)
- Infinite conducting cylinder (radius R) with line density λ: outside (r > R): E(r) = λ / (2 π ε0 r); inside (r < R): E = 0
- Solid insulating sphere with uniform charge Q and radius R: outside E = (1 / (4 π ε0)) Q / r^2; inside E = (1 / (4 π ε0)) Q r / R^3
- Infinite sheet of charge with surface density σ: E = σ / (2 ε0) on each side; direction perpendicularly away from sheet for positive σ; field does not depend on distance from sheet
- Between two large conducting plates with surface charges +σ and −σ: E between plates is E = σ / ε0; outside the field is typically zero for ideal parallel plates
- Just outside a conductor: E_⊥ = σ/ε0; field is perpendicular to the surface
Connections and Implications
- Gauss’s Law provides a bridge between electric flux and enclosed charge, and it formalizes how symmetry simplifies E-field calculations
- The concept of a Gaussian surface helps translate a 3D field problem into a tractable flux integral using symmetry
- The idea that conductors in electrostatic equilibrium have E = 0 inside and charge resides on surfaces is fundamental to shielding, capacitors, and electrostatic design
- Charge distribution behavior in conductors with cavities demonstrates how local charges influence induced charges on inner vs outer surfaces
- Flux through a surface: oxed{ \PhiE = \ointS \mathbf{E} \cdot d\mathbf{A} }
- Gauss’s Law: \boxed{ \ointS \mathbf{E} \cdot d\mathbf{A} = \frac{Q{ ext{enc}}}{\varepsilon_0} }
- Volume density: \boxed{ \rho = \frac{Q}{V} }
- Surface density: \boxed{ \sigma = \frac{Q}{A} }
- Linear density: \boxed{ \lambda = \frac{Q}{L} }
- Point charge field: \boxed{ \mathbf{E} = \frac{q}{4\pi\varepsilon_0}\frac{\hat{r}}{r^2} }
- Infinite plane: \boxed{ E = \frac{\sigma}{2\varepsilon_0} }\quad \text{(on each side, direction away from plane for } \sigma>0)
- Infinite line charge: \boxed{ E(r) = \frac{\lambda}{2\pi\varepsilon_0\,r} }
- Outside a uniformly charged sphere: \boxed{ E(r) = \frac{1}{4\pi\varepsilon_0}\frac{Q}{r^2} } \text{ for } r > R
- Inside a uniformly charged sphere: \boxed{ E(r) = \frac{1}{4\pi\varepsilon_0}\frac{Q\,r}{R^3} } \text{ for } r \le R
- Field between two plates (capacitor-like): \boxed{ E = \frac{\sigma}{\varepsilon_0} }
- Boundary condition at conductor surface: \boxed{ E{\ ext{out},\perp} - E{\text{in},\perp} = \frac{\sigma}{\varepsilon0} } with E{in} = 0 inside
Note on Exericises (referenced in the transcript)
- Ex. 22.1: How to measure charge inside a box without opening it (Gaussian surface intuition; outward flux vs inward flux indicates positive vs negative charge inside)
- Ex. 22.3: Electric flux through a sphere (using ∮ E · dA) and Gauss’s Law for enclosed charge
- Ex. 22.5: Field by a conducting sphere (inside E = 0; outside behaves like a point charge)
- Ex. 22.6: Field of an infinite line charge
- Ex. 22.7: Field of an infinite plane sheet of charge
- Ex. 22.9/22.10: Field of a uniformly charged sphere and other charge configurations
- Ex. 22.x: Charges on conductors, cavities, and surface charges