Oxidation is the loss of electrons, gain of oxygen
Reduction is gain of electrons, loss of oxygen
^^u can remember this by OILRIG^^
^^Oxidation is Loss of electrons Reduction is Gain of electrons^^
sometimes oxidation and reduction happen together this reaction or process is called Redox Reactions.
Redox reactions can also be defined in terms of electron transfer
Oxidation is a reaction in which an element, ion or compound loses electrons
Reduction is a reaction in which an element, ion or compound gains electrons
O2 + 4e- → 2O2-
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Mnemonic to remember oxidation and reduction in terms of electron transfer
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Names using oxidation states
Transition elements can bond in different ways by forming ions with different charges
When naming, the charge on the ion is shown by using a Roman numeral after the element's name
The Roman numeral is the oxidation state of the element
When iron reacts with oxygen to form iron oxide, the formula depends on the oxidation state of the iron ions
Oxidation number
The oxidation state (also called oxidation number) is a number assigned to an atom or ion in a compound which indicates the degree of oxidation (or reduction)
The oxidation state helps you to keep track of the movement of electrons in a redox process
It is written as a +/- sign followed by a number (not to be confused with charge which is written by a number followed by a +/- sign)
E.g. aluminium in a compound usually has the oxidation state +3
Assigning the oxidation state
Oxidation state refers to a single atom or ion only
The oxidation number of a compound is 0 and of an element (for example Br in Br2) is also 0
The oxidation number of oxygen in a compound is always -2 (except in peroxide R-O-O-R, where it is -1)
For example in FeO, oxygen is -2 then Fe must have an oxidation number of +2 as the overall oxidation number for the compound must be 0
Writing all of the ions present and including state symbols we get:
The spectator ions (those that do not change) are SO42-(aq), removing these we can write the ionic equation as:
By analysing the ionic equation, we can split the reaction into two half equations by adding in the electrons to show how the changes in charge have occurred.
It then becomes clear that zinc has been oxidised as its oxidation state has increased from 0 in Zn to +2 in Zn2+and it has lost electrons:
Copper ions have been reduced as the oxidation state has decreased from +2 in Cu2+ to 0 in Cu and they have gained electrons:
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Example
CuO + H2 → Cu + H2O
In the above reaction, hydrogen is reducing the CuO and is itself oxidised as it has lost electrons, so the reducing agent is therefore hydrogen:
H2 → 2H+ + 2e-
The CuO is reduced to Cu by gaining electrons and has oxidised the hydrogen, so the oxidising agent is therefore copper oxide
Cu2+ +2e- → Cu
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