Geometry TEKS Test Review
Geometry TEKS Test Review Notes 2025-26
Section 1: Examples of Geometric Concepts
- Choose the examples from the box that apply for each description:
- Collinear points:
- Possible examples: FAC, ZEAC.
- Non-collinear points:
- Possible examples: A, B, C, I.
- Adjacent angles:
- Possible examples: <BAC and DAC, <FAE and LEAD.
- Vertical angles:
- Possible examples: <ZBAC.
- Supplementary angles:
- Possible examples: F, A, and D.
- Complementary angles:
- Possible examples: B, C, and D.
- Linear pair:
- Possible examples: <FAB and LEAD.
- Right angle:
- Possible examples: <ZBAC and <ZEAC.
- Acute angle:
- Possible examples: <ZFAE.
- Obtuse angle:
- Specify needed examples.
Section 2: Triangular Prisms and Statements
- Prism Analysis: In the figure presented:
- Statement a: AC || DF - True.
- Statement b: ABAD - True.
- Statement c: AC and BC are coplanar - True.
- Statement d: DE and CF are skew - True.
- Statement e: EF and BC are skew - False.
Section 3: Logical Statements and Truth Values
- Identify the converse, inverse, and contrapositive of the statement: "If two angles have the same measure, then they are congruent."
- Converse: If two angles are congruent, then they have the same angle measure. (Answer: C) - True.
- Inverse: If two angles do not have the same measure, then they are not congruent. (Answer: A) - True.
- Contrapositive: If two angles are not congruent, then they do not have the same angle measure. (Answer: B) - True.
Section 4: Counterexamples to Statements
- Counterexamples for statements:
- Statement a: If two lines are not parallel, then they intersect.
- Counterexample: Skew lines.
- Statement b: If a triangle has 2 acute angles, then its 3rd angle is obtuse.
- Counterexample: Any right triangle.
Section 5: Diagram Analysis and Inferences
- Indicate if statements can be inferred from the figure:
- Statement a: KG = GL - No.
- Statement b: <ZEGL = <ZKGM - Yes.
- Statement c: m/LGJ = 90° - No.
- Statement d: m2FGE + mZEGL = mZFGL - Yes.
- Statement e: mZEGM + mZLGM = 180° - Yes.
Section 6: Segment Lengths and Equations
- Draw segments AB and CD for the given points:
- Point A (-2, 8), Point B (2, 0), Point C (3, -8), Point D (7, -2).
- Determine the length of AB:
- Formula: d = ext{√}((x2 - x1)^2 + (y2 - y1)^2)
- Calculation: d = ext{√}((2 - (-2))^2 + (0 - 8)^2) = 455.
- Write the equation of the perpendicular bisector of AB:
- Slope of AB: M_{AB} = rac{0-8}{2-(-2)} = -2; the midpoint: (2, 0).
- Bisector equation: y = rac{1}{2}x + 4.
- Equation of a line parallel to CD passing through B: y = -2x + 4.
- Equation of a perpendicular line to CD at (-7, -3): y - (-3) = -rac{1}{2}(x + 7).
- Midpoint of AE if Point E is located at (12, -16): Calculation yields: (5, -4).
Section 7: Triangle Angles and Relationships
- Given triangle ABC, where BD bisects angle ABC:
- Statement a: <ZDBC = 2 <DBE.
- Statement b: m<ABE + m<ABC = 2m<ABD.
- Statement c: m<ABE < m<ABC.
- Statement d: m<ABE = m<DBE.
- Statement e: Relationships about angles are provided.
Section 8: Collinear Segments and Truth Statements
- Given the segments PB and BJ collinear with B between P and J:
- Diagram to represent: PB = 12 units, PJ = 36 units.
- Statement a: PJ + B = PB - False.
- Statement b: PB - BJ = PJ - True.
- Statement c: 2BJ = PB - True.
- Statement d: 3PB = PJ - False.
- Statement e: B is the midpoint of PJ - True.
Section 9: Parallel Lines and Angle Relationships
- Given parallel lines m and t:
- Determine if the following statements are true or false:
- Statement a: 211 and 214 are alternate interior angles - True.
- Statement b: 4 and 27 are alternate exterior angles - False.
- Statement c: 21 and 12 are corresponding angles - True.
- Statement d: 24 and 211 are same-side interior angles - False.
- Statement e: 21 and 23 are vertical angles - False.
Section 10: Triangle Classification
- Classify each triangle based on angle measures and side lengths:
- Example a: 25°, 100°, 55° - Classified as: obtuse scalene.
- Example b: 90°, 45°, 45° - Classified as: right isosceles.
- Example c: 60°, 60°, 60° - Classified as: acute equilateral.
- Example d: 122°, 29°, 29° - Classified as: obtuse isosceles.
- Example e: 90°, 30°, 60° - Classified as: right scalene.
- Example f: 55°, 70°, 55° - Classified as: acute isosceles.
Section 11: Triangle Attributes and Perpendicular Bisectors
- Given line g is the perpendicular bisector of PK:
- True statements about the diagram:
- PK and line g intersect at the midpoint of PK.
- Points on line g are equidistant from points P and K.
- Slopes of line g and line PK are opposite reciprocals.
Section 12: Solving Angle Measures
- Determine angle measures given VGHJ:
- Angle measures: m∠G = 64.2°, m∠GH = 78°, side GH = 37.8.
- Longest side identification: GJ is longest since it is across from the largest angle <JHG.
- Given triangles ABC and DF are shown on the grid:
- Transformation performed: Translation down and left.
- List congruent parts due to transformations.
- For proving triangles congruent:
- Example a: Missing measure for the included angle or third side.
- Example b: Missing measure of the hypotenuse.
Section 15: Similarity Statements and Scale Factors
- Similarity statements for triangles:
- Each statement must include the similarity postulate - SS, SAS, etc.
- Calculate and confirm the scale factor for transformations between triangles.
Section 16: Algebraic Solving for Variables
- For solving for x and y in expressions:
- Examples provided included algebraically solving for dimensions in geometry problems involving triangles and ratios.
Section 17: Final Calculations
- Example for determining height of a pole using shadows of a player and the pole:
- Given: Height of a player- 2 m, length of shadow- 1.6 m, length of pole’s shadow- 4.4 m.
- Pole height calculation: results in a height of approximately 5.5 m.