MATH 101 - 102: Lecture 7 Study Notes

MATH 101 - 102: Lecture 7

Instructor Information

  • Instructor: Nima Eslami

  • The University of British Columbia, Okanagan Campus

  • Department of Mathematics, Computer Science, Physics, and Statistics

  • Irving K. Barber Faculty of Science

  • Date of Lecture: January 27, 2026

Agenda

  • Today we will cover the following integration techniques:

    • u-substitution

    • reverse u-substitution

    • rationalizing substitutions

    • integration by parts

First Technique of Integration: U-Substitution

The U-Substitution Strategy for Definite Integrals

To evaluate an integral of the form ∫abf(g(x))g′(x) dx\int_{a}^{b} f(g(x)) g'(x) \, dx, follow these steps:

  1. Choose the substitution:

    • Set u=g(x)u = g(x).

  2. Differentiate:

    • Differentiate both sides to relate dudu and dxdx:
      du=g′(x) dxdu = g'(x) \, dx (equivalently, dx=1g′(x) dudx = \frac{1}{g'(x)} \, du).

  3. Rewrite the integrand:

    • Substitute u=g(x)u = g(x) and du=g′(x) dxdu = g'(x) \, dx into the integral so that everything is expressed in terms of uu:
      ∫abf(g(x))g′(x) dx=∫f(u) du\int_{a}^{b} f(g(x)) g'(x) \, dx = \int f(u) \, du.

  4. Change the bounds:

    • Convert the limits of integration from x-bounds to u-bounds using the substitution:

    • When x=ax = a, then u=g(a)u = g(a);

    • When x=bx = b, then u=g(b)u = g(b).

    • Therefore,
      ∫<em>abf(g(x))g′(x) dx=∫</em>g(a)g(b)f(u) du\int<em>{a}^{b} f(g(x)) g'(x) \, dx = \int</em>{g(a)}^{g(b)} f(u) \, du.

  5. Integrate and evaluate:

    • If F′(u)=f(u)F'(u) = f(u), then
      ∫<em>g(a)g(b)f(u) du=F(u)∣</em>g(a)g(b)=F(g(b))−F(g(a))\int<em>{g(a)}^{g(b)} f(u) \, du = F(u) \bigg|</em>{g(a)}^{g(b)} = F(g(b)) - F(g(a)).

Note: Substituting Back to the Original Variable
  • If you change the bounds to u-bounds (recommended), typically you do not substitute back to xx inside the antiderivative; simply evaluate using u=g(a)u = g(a) and u=g(b)u = g(b).

  • If you keep the original bounds aa and bb in xx, you must substitute back u=g(x)u = g(x) before evaluating:
    ∫<em>abf(g(x))g′(x) dx=F(g(x))∣</em>ab=F(g(b))−F(g(a))\int<em>{a}^{b} f(g(x)) g'(x) \, dx = F(g(x)) \bigg|</em>{a}^{b} = F(g(b)) - F(g(a)).

Indefinite Integrals and U-Substitution
  • For indefinite integrals, there are no bounds to change. After substituting u=g(x)u = g(x) and du=g′(x) dxdu = g'(x) \, dx, follow these steps:

    1. Integrate with respect to uu:
      ∫f(g(x))g′(x) dx=∫f(u) du\int f(g(x)) g'(x) \, dx = \int f(u) \, du.

    2. After integration, substitute back:
      =F(u)+C= F(u) + C.

    3. Replace uu with g(x)g(x) including the constant of integration:
      =F(g(x))+C= F(g(x)) + C.

Example
  1. Calculate the following indefinite integral:

    • ∫2xsin⁡(x2+5) dx\int 2x \sin(x^2 + 5) \, dx.

Additional Examples
  1. Calculate the following indefinite integral:

    • ∫8sin⁡(x)cos⁡2(2x)+1 dx\int \frac{8 \sin(x)}{\cos^2(2x) + 1} \, dx.

  2. Calculate the following definite integral:

    • ∫010(2x+9)(2x2+9x) dx\int_{0}^{10} (2x + 9)(2x^2 + 9x) \, dx.

  3. Calculate the following definite integral:

    • ∫3Lxet2 dx\int_{3}^{L} xe^{t^2} \, dx.

  4. Calculate the following definite integral:

    • ∫0T(3+4x) dx\int_{0}^{T} (3 + 4x) \, dx from x2+1x^2 + 1.

Practice Questions
  • Calculate the following definite integrals:

    1. ∫0π44sec⁡2(θ)(tan⁡7(θ)+1) dθ\int_{0}^{\frac{\pi}{4}} 4 \sec^2(\theta)(\tan^7(\theta) + 1) \, d\theta.

    2. ∫−21w+52w2+1 dw\int_{-2}^{1} \frac{w + 5}{2w^2 + 1} \, dw.

    3. ∫ee2(5+ln⁡(2x))(4+(ln⁡(2x))3)7x dx\int_{e}^{e^2} \left(5 + \ln(2x) \right) \left(4 + (\ln(2x))^3 \right)7x \, dx.

    4. ∫14(3−x)2x dx\int_{1}^{4} (3 - \sqrt{x}) 2\sqrt{x} \, dx.

A Technical Note
  • Suppose that F(x)F(x) is an antiderivative of f(x)f(x), and consider ∫f(ax+b) dx\int f(ax + b) \, dx, where a,b∈Ra, b \in \mathbb{R} and a≠0a \neq 0.

  • Make the change of variables:

    • Set u=ax+bu = ax + b.

    • Thus, du=a dxdu = a \, dx, leading to dx=1a dudx = \frac{1}{a} \, du.

  • Now substitute and integrate:
    ∫f(ax+b) dx=∫f(u)⋅1a du\int f(ax + b) \, dx = \int f(u) \cdot \frac{1}{a} \, du.

  • Therefore, it results in:
    =F(u)a+C=F(ax+b)a+C= \frac{F(u)}{a} + C = \frac{F(ax + b)}{a} + C.

  • Example: Evaluate ∫sin⁡(3x+2) dx\int \sin(3x + 2) \, dx.

Reverse U-Substitution

Example
  • Calculate the integral:
    ∫x1+x dx\int \frac{x}{1+x} \, dx.

Additional Examples
  1. Calculate the following indefinite integral:

    • ∫2−x dx\int \sqrt{2 - \sqrt{x}} \, dx.

  2. Calculate the following definite integral:

    • ∫023x−22x+1 dx\int_{0}^{2} \frac{3x-2}{2x + 1} \, dx.

Practice Questions
  • Calculate the following integrals using reverse u-substitution:

    1. ∫(23x3+3x) dx\int (2 \sqrt{3} x^3 + \sqrt{3} x) \, dx.

    2. ∫5m24−2m dm\int 5m^2 \sqrt{4 - 2m} \, dm.

    3. ∫24z+22z−1 dz\int_{2}^{4} \frac{\sqrt{z+2}}{2z-1} \, dz.

Rationalizing Substitutions

Example
  • Use a rationalizing substitution to calculate the following integral:

    • ∫x−9x dx\int \frac{\sqrt{x}-9}{x} \, dx.

Additional Examples
  • Use a rationalizing substitution to calculate the following integrals:

    1. ∫1x+x1/3 dx\int \frac{1}{x + x^{1/3}} \, dx.

Integration by Parts

Example
  • Compute the integral:

    • ∫xcos⁡(x) dx\int x \cos(x) \, dx.