Lecture 4: Vector and Triple Products

Vector Product (Cross Product) Overview

Definition of Vector Product

  • Scalar Product Recap: A scalar product (dot product) combines two vectors to produce a scalar (Vector $\cdot$ Vector $\Rightarrow$ Scalar).

  • Vector Product (Cross Product) Definition: A vector product (cross product) combines two vectors to produce a vector (Vector $\times$ Vector $\Rightarrow$ Vector).

  • Formula: The vector product of two vectors aa and bb is given by: a×b=absinθe^a \times b = |a| |b|\sin \theta \hat{e} where:

    • a|a| is the magnitude of vector aa.

    • b|b| is the magnitude of vector bb.

    • θ\theta is the angle between vectors aa and bb (0θπ0 \le \theta \le \pi).

    • e^\hat{e} is a unit vector perpendicular to both aa and bb.

  • Direction of e^\hat{e}: The direction of e^\hat{e} is determined by the right-hand rule. If you curl the fingers of your right hand from vector aa to vector bb through the angle θ\theta, your thumb points in the direction of e^\hat{e}. The illustration of the right-hand rule demonstrates this concept.

  • Magnitude and Direction: The vector a×ba \times b has a magnitude of absinθ|a| |b|\sin \theta and a direction given by e^\hat{e}.

Vector Product for Parallel Vectors

  • General Formula: a×b=absinθe^a \times b = |a| |b|\sin \theta \hat{e}

  • Zero Vector Condition: If either vector aa or vector bb is the zero vector (a=0a = 0 or b=0b = 0), then their cross product is the zero vector (a×b=0a \times b = 0).

  • Parallel Vector Condition: If vectors aa and bb are parallel, the angle between them is either 00 (same direction) or π\pi (opposite directions). In both cases, sinθ=0\sin \theta = 0. Therefore, if aa and bb are parallel, then a×b=0a \times b = 0.

  • Special Case: The cross product of a vector with itself is always the zero vector (a×a=0a \times a = 0) since a vector is parallel to itself.

  • Undefined Unit Vector: The unit vector e^\hat{e} is not defined if aa and bb are parallel or one of them is a zero vector. Despite this, the cross product a×ba \times b is still well-defined as the zero vector (00).

  • Converse: If a×b=0a \times b = 0 and both aa and bb are non-zero vectors, it implies that sinθ=0\sin \theta = 0. This means θ=0\theta = 0 or θ=π\theta = \pi, which indicates that vectors aa and bb are parallel.

  • Diagnostic Tool: The scalar product is used to test for perpendicular vectors (ab=0a \cdot b = 0). Conversely, the vector product is used to test for parallel vectors (a×b=0a \times b = 0).

Vector Product Properties

Let aa, bb, cc be vectors and λ\lambda be a scalar:

  • Anticommutative Property: The order of the vectors in a cross product matters. Swapping the order reverses the direction of the resulting vector. b×a=(a×b)b \times a = - (a \times b)

    • Explanation: When a×ba \times b is calculated, e^\hat{e} points in a specific direction. For b×ab \times a, the right-hand rule dictates that e^\hat{e} will point in the opposite direction (e^-\hat{e}).

  • Distributive over Vector Addition: The cross product is distributive over vector addition.

    • a×(b+c)=(a×b)+(a×c)a \times (b + c) = (a \times b) + (a \times c)

    • (a+b)×c=(a×c)+(b×c)(a + b) \times c = (a \times c) + (b \times c)

  • Associative over Scalar Multiplication: A scalar factor can be factored out or in with any of the vectors.
    (λa)×b=λ(a×b)=a×(λb)(\lambda a) \times b = \lambda (a \times b) = a \times (\lambda b)

  • Parallel Condition (revisited): If aa and bb are non-zero vectors, then a×b=0a \times b = 0 if and only if aa and bb are parallel. As a specific instance, a×a=0a \times a = 0.

  • Non-Associative in General: The vector product is generally not associative for three vectors.
    a×(b×c)(a×b)×ca \times (b \times c) \neq (a \times b) \times c

Area of a Parallelogram

  • The magnitude of the vector product of two vectors aa and bb (originating from the same point) represents the area of the parallelogram formed by these two vectors as adjacent sides.

  • Formula: Area=a×b=absinθArea = |a \times b| = |a| |b| \sin \theta

  • Geometric Derivation: The area of the parallelogram OACB is twice the area of triangle OAB. The area of triangle OAB is 12OAh\frac{1}{2} \cdot |OA| \cdot h, where hh is the perpendicular height from B to OA. The height h=OBsinθ=bsinθh = |OB| \sin \theta = |b| \sin \theta. So, the area of triangle OAB is 12absinθ\frac{1}{2} |a| |b| \sin \theta. Therefore, the area of the parallelogram is 212absinθ=absinθ2 \cdot \frac{1}{2} |a| |b| \sin \theta = |a| |b| \sin \theta. This is precisely the magnitude of their cross product.

Vector Product in Cartesian Form

  • Cross Products of Cartesian Unit Vectors:

    • i×i=0i \times i = 0, j×j=0j \times j = 0, k×k=0k \times k = 0

    • i×j=ki \times j = k

    • j×k=ij \times k = i

    • k×i=jk \times i = j

    • j×i=kj \times i = -k

    • k×j=ik \times j = -i

    • i×k=ji \times k = -j

  • For any two vectors in Cartesian coordinates:
    Let a=a<em>1i+a</em>2j+a<em>3ka = a<em>1 i + a</em>2 j + a<em>3 k And b=b</em>1i+b<em>2j+b</em>3kb = b</em>1 i + b<em>2 j + b</em>3 k

  • Expanded Calculation: Performing the distributive property with the unit vector cross products:
    a×b=(a<em>1i+a</em>2j+a<em>3k)×(b</em>1i+b<em>2j+b</em>3k)a \times b = (a<em>1 i + a</em>2 j + a<em>3 k) \times (b</em>1 i + b<em>2 j + b</em>3 k)
    =a<em>1b</em>2(i×j)+a<em>1b</em>3(i×k)+a<em>2b</em>1(j×i)+a<em>2b</em>3(j×k)+a<em>3b</em>1(k×i)+a<em>3b</em>2(k×j)= a<em>1 b</em>2 (i \times j) + a<em>1 b</em>3 (i \times k) + a<em>2 b</em>1 (j \times i) + a<em>2 b</em>3 (j \times k) + a<em>3 b</em>1 (k \times i) + a<em>3 b</em>2 (k \times j)
    =a<em>1b</em>2k+a<em>1b</em>3(j)+a<em>2b</em>1(k)+a<em>2b</em>3i+a<em>3b</em>1j+a<em>3b</em>2(i)= a<em>1 b</em>2 k + a<em>1 b</em>3 (-j) + a<em>2 b</em>1 (-k) + a<em>2 b</em>3 i + a<em>3 b</em>1 j + a<em>3 b</em>2 (-i)
    =(a<em>2b</em>3a<em>3b</em>2)i+(a<em>3b</em>1a<em>1b</em>3)j+(a<em>1b</em>2a<em>2b</em>1)k= (a<em>2 b</em>3 - a<em>3 b</em>2) i + (a<em>3 b</em>1 - a<em>1 b</em>3) j + (a<em>1 b</em>2 - a<em>2 b</em>1) k

  • Determinant Form (Easier to Remember): The vector product can be concisely calculated using the determinant of a 3×33 \times 3 matrix:
    a×b=i^amp;j^amp;k^ a<em>1amp;a</em>2amp;a<em>3 b</em>1amp;b<em>2amp;b</em>3a \times b = \begin{vmatrix} \hat{i} &amp; \hat{j} &amp; \hat{k} \ a<em>1 &amp; a</em>2 &amp; a<em>3 \ b</em>1 &amp; b<em>2 &amp; b</em>3 \end{vmatrix}
    Expanding the determinant:
    =i^(a<em>2b</em>3a<em>3b</em>2)j^(a<em>1b</em>3a<em>3b</em>1)+k^(a<em>1b</em>2a<em>2b</em>1)= \hat{i} (a<em>2 b</em>3 - a<em>3 b</em>2) - \hat{j} (a<em>1 b</em>3 - a<em>3 b</em>1) + \hat{k} (a<em>1 b</em>2 - a<em>2 b</em>1)
    =(a<em>2b</em>3a<em>3b</em>2)i^+(a<em>3b</em>1a<em>1b</em>3)j^+(a<em>1b</em>2a<em>2b</em>1)k^= (a<em>2 b</em>3 - a<em>3 b</em>2) \hat{i} + (a<em>3 b</em>1 - a<em>1 b</em>3) \hat{j} + (a<em>1 b</em>2 - a<em>2 b</em>1) \hat{k}

Examples of Vector Product Calculation

  • Example 1: Given vectors a=6i+2j3ka = 6i + 2j - 3k and b=4ij2kb = 4i - j - 2k.
    Find a×ba \times b.
    a×b=iamp;jamp;k 6amp;2amp;3 4amp;1amp;2a \times b = \begin{vmatrix} i &amp; j &amp; k \ 6 &amp; 2 &amp; -3 \ 4 &amp; -1 &amp; -2 \end{vmatrix}
    =i((2)(2)(3)(1))j((6)(2)(3)(4))+k((6)(1)(2)(4))= i((2)(-2) - (-3)(-1)) - j((6)(-2) - (-3)(4)) + k((6)(-1) - (2)(4))
    =i(43)j(12+12)+k(68)= i(-4 - 3) - j(-12 + 12) + k(-6 - 8)
    =7i0j14k= -7i - 0j - 14k
    =7i14k= -7i - 14k

  • Example 2: Find a vector perpendicular to a=4i2j+3ka = 4i - 2j + 3k and b=5i+j4kb = 5i + j - 4k.
    The cross product a×ba \times b gives a vector perpendicular to both aa and bb.
    a×b=iamp;jamp;k 4amp;2amp;3 5amp;1amp;4a \times b = \begin{vmatrix} i &amp; j &amp; k \ 4 &amp; -2 &amp; 3 \ 5 &amp; 1 &amp; -4 \end{vmatrix}
    =i((2)(4)(3)(1))j((4)(4)(3)(5))+k((4)(1)(2)(5))= i((-2)(-4) - (3)(1)) - j((4)(-4) - (3)(5)) + k((4)(1) - (-2)(5))
    =i(83)j(1615)+k(4+10)= i(8 - 3) - j(-16 - 15) + k(4 + 10)
    =5i(31)j+14k= 5i - (-31)j + 14k
    =5i+31j+14k= 5i + 31j + 14k

Triple Products

  • Triple products are operations that combine three vectors using a combination of scalar and vector products.

Scalar Triple Product
  • Definition: The scalar triple product is defined as a(b×c)a \cdot (b \times c). The result is a scalar.

  • Properties (Cyclic Permutation): The scalar triple product remains unchanged under cyclic permutation of the vectors.
    a(b×c)=c(a×b)=b(c×a)a \cdot (b \times c) = c \cdot (a \times b) = b \cdot (c \times a)

  • Determinant Form: The scalar triple product can be calculated as the determinant of a 3×33 \times 3 matrix where the rows (or columns) are the components of the three vectors. a(b×c)=a<em>1amp;a</em>2amp;a<em>3 b</em>1amp;b<em>2amp;b</em>3 c<em>1amp;c</em>2amp;c3a \cdot (b \times c) = \begin{vmatrix} a<em>1 &amp; a</em>2 &amp; a<em>3 \ b</em>1 &amp; b<em>2 &amp; b</em>3 \ c<em>1 &amp; c</em>2 &amp; c_3 \end{vmatrix}

    • This can be proven by using the determinant definition of the vector product and then performing the dot product.

  • Geometric Interpretation (Volume of Parallelepiped):

    • The absolute value of the scalar triple product, a(b×c)|a \cdot (b \times c)|, represents the volume of the parallelepiped formed by the three vectors aa, bb, and cc as coterminous edges.

    • The area of the base parallelogram formed by vectors bb and cc is b×c|b \times c|.

    • The height of the parallelepiped relative to this base is the projection of vector aa onto the normal of the base, which is acosϕ|a| |\cos \phi|, where ϕ\phi is the angle between aa and (b×c)(b \times c).

    • Volume =(AreaofBase)×(Height)=b×cacosϕ=a(b×c)= (Area of Base) \times (Height) = |b \times c| |a| |\cos \phi| = |a \cdot (b \times c)|.

  • Coplanarity Condition: If the scalar triple product a(b×c)=0a \cdot (b \times c) = 0, then the three vectors aa, bb, and cc are coplanar (lie in the same plane). This also implies they are linearly dependent, meaning one vector can be expressed as a linear combination of the other two (e.g., a=λb+μca = \lambda b + \mu c for some scalars λ\lambda and μ\mu).

Vector Triple Product
  • Definition: The vector triple product is defined as a×(b×c)a \times (b \times c). The result is a vector.

  • Non-Associative (revisited): As noted previously, the vector triple product is not associative; meaning (a×b)×ca×(b×c)(a \times b) \times c \neq a \times (b \times c).

  • Expansion Formula (BAC-CAB Rule): The vector triple product can be expanded using a formula known as the BAC-CAB rule:

    • a×(b×c)=(ac)b(ab)ca \times (b \times c) = (a \cdot c) b - (a \cdot b) c

    • (a×b)×c=(ac)b(bc)a(a \times b) \times c = (a \cdot c) b - (b \cdot c) a