Conversion process from binomial distribution to normal approximation.
Acknowledgement of possible underestimation or overestimation.
Importance of correction factors in adjustments.
Ensuring conditions for normal approximation are met.
Example: Checking binomial success probabilities to satisfy conditions (e.g., np and nq > 10).
Determine the binomial distribution parameters.
Compute mean and standard deviation for binomial distribution:
Mean (µ) calculation: µ = np
Standard deviation (σ) calculation: σ = √(npq)
For example, with n = 500 and p = 0.06:
Mean: µ = 500 * 0.06 = 30
Standard deviation: σ = √(500 * 0.06 * 0.94) = 5.31
Correction factor is necessary when calculating probabilities:
Adjust x values for continuity adjustment: e.g., P(x < a) becomes P(x < a - 0.5).
For finding P(x < 25) with correction:
Calculate z-score: z = (24.5 - 30) / 5.31 = -1.04.
Reference z-table for probability: P(Z < -1.04) = 0.1492.
Conclusion: Approximately 15% probability that fewer than 25 adults have cancer.
For exact probabilities, compute using continuity correction on both sides:
Example for P(x = 28): Compute for P(27.5 < X < 28.5).
Z-scores:
Lower bound: z = (27.5 - 30) / 5.31 = -0.47.
Upper bound: z = (28.5 - 30) / 5.31 = -0.28.
Use z-table to find probabilities for both z-scores and calculate the difference.
Importance of verifying conditions for using normal approximation.
Regular practice with these types of problems will improve proficiency in statistical conversion methods.