Chemical and magnetic equivalence
Equivalence
Protons in methyl and most methylene (-CH₂-) groups are:
Chemically equivalent – same chemical environment.
Magnetically equivalent – same coupling constants to other nuclei.
The (n+1) rule applies to groups of equivalent nuclei.
🔹 Types of Equivalence
Chemically equivalent: same environment.
Magnetically equivalent: same coupling constants.
Note: Some protons (e.g. in aromatic rings) may be chemically equivalent but magnetically inequivalent due to differing coupling constants.
🔹 Example: Para-disubstituted Benzene
A & A′ and B & B′ are chemically equivalent.
Coupling constants differ:
Ortho (1,2): 7–9 Hz
Meta (1,3): 1–3 Hz
Para (1,4): ≤1 Hz
Therefore, proton Hₐ gives a doublet of doublets in ¹H NMR.
🔗 Connectivity
🔹 COSY (Correlation Spectroscopy)
Reveals which protons are coupled.
Useful for complex molecules or similar coupling constants.
Can be used for:
¹H–¹H coupling
¹H–¹³C coupling (in separate experiments)
🧠 ¹³C NMR Recap
🔹 Simpler than ¹H NMR:
One signal per unique carbon.
Position of signal → indicates electronegativity of neighbouring atoms.
No integration or multiplicity.
🧪 ¹³C DEPT Spectra
🔹 DEPT135
CH and CH₃ → Up
CH₂ → Down
🔹 DEPT90
CH only
🔹 ¹³C Standard Spectrum
All carbons, including quaternary.
📈 Chemical Shift
Depends on electronegativity of neighbouring atoms.
Similar trend to ¹H NMR.
🧬 Coupling in ¹³C NMR
¹³C signals split by directly attached protons.
Usually suppressed using broadband decoupling for simplicity (single signal per carbon).
🔍 DEPT Spectrum Interpretation
🔹 Why it matters:
Determines how many protons are attached to each carbon.
Helps distinguish CH, CH₂, CH₃.
🧠 Spectrum Interpretation Strategy
🔹 ¹H NMR (4 Key Rules)
Number of hydrogen environments
Chemical shift
Integration (number of protons)
Coupling/multiplicity
🔹 ¹³C NMR (3 Key Rules)
Number of carbon environments
Chemical shift
Use DEPT (to find attached protons)
🔢 Double Bond Equivalents (DBEs)
🔹 Purpose:
Indicates rings and π-bonds.
Useful for identifying aromaticity or unsaturation.
🔹 Formula:
Replace heteroatoms with equivalent CHn groups.
Alkanes: CₙH₂ₙ₊₂
DBE = ½ × (number of “missing” Hs)
🔹 Example: Hydrocarbon C₁₀H₁₆
Alkane equivalent: C₁₀H₂₂
Difference = 6 H → DBE = 6 ÷ 2 = 3
🧪 Non-Hydrocarbons
Replace other atoms (e.g. N, O, Cl) with hydrocarbon equivalents of the same valency.
🧬 Aromatic Systems
🔹 Disubstituted Benzenes
Include para-couplings, even if small (often not visible).
🔹 Monosubstituted Benzenes
Predict splitting patterns similarly.
Spectrum can become complex due to many couplings.
🔹 Practical Tip:
A messy signal in aromatic region integrating to 5H suggests a monosubstituted benzene.