Born-Haber Cycle Notes

Born-Haber Cycle

Overview

  • The Born-Haber Cycle was developed by Max Born and Fritz Haber to analyze reaction enthalpies by examining individual reactions.

The Born-Haber Cycle

  • Max Born and Fritz Haber used known thermodynamic data to develop a simplified, cyclic method for determining unknown lattice energies of ionic crystals.

Definition of the Born-Haber Cycle

  • The Born-Haber Cycle calculates lattice enthalpy by comparing the standard enthalpy change of formation of an ionic compound to the enthalpy required to create gaseous ions from its elements.
  • It's primarily used to calculate lattice enthalpies, which are hard to measure directly.

Born-Haber Cycle Components

  • The cycle involves transforming elements (metal and non-metal) into an ionic compound via gaseous ions.
  • Process:
    • Break bonds to form gaseous ions.
      • Metals lose electrons and become positively charged (+ve).
      • Non-metals gain electrons and become negatively charged (-ve).
    • Lattice Energy:
      • Is the attraction between the positive and negative ions.
  • It is a specific type of Hess’ Cycle.
  • ΔHf\Delta H_f represents the enthalpy of formation.

Example: Sodium Chloride (NaCl)

  • The formation of NaCl(s) from Na(s) and Cl2(g) can be broken down into intermediate steps:
    • Na(s)+12Cl2(g)NaCl(s)Na(s) + \frac{1}{2} Cl_2(g) \rightarrow NaCl(s)
    • (i) Metallic sodium into gaseous sodium atom
    • (ii) Dissociation of chlorine molecule into chlorine atoms
    • (iii) Gaseous sodium atom into gaseous cation
    • (iv) Gaseous chlorine atom into gaseous anion
    • (v) Combination of oppositely charged gaseous ions to form solid crystal

Step 1: Metallic Sodium to Gaseous Sodium

  • The energy required to convert 1 mole of sodium metal into gaseous sodium atoms is the enthalpy of sublimation (ΔHs\Delta H_s).
  • This step is energy-consuming.
  • Na(s)+ΔHsNa(g)Na(s) + \Delta H_s \rightarrow Na(g)
  • ΔHs=108.5kJmol\Delta H_s = 108.5 \frac{kJ}{mol}

Step 2: Dissociation of Chlorine Molecule

  • The energy required to form 1 mole of chlorine atoms from chlorine molecules is the enthalpy of dissociation (ΔHd\Delta H_d).
  • Cl<em>2(g)+2ΔH</em>d2Cl(g)Cl<em>2(g) + 2\Delta H</em>d \rightarrow 2Cl(g)
  • 12Cl<em>2(g)+ΔH</em>dCl(g)\frac{1}{2} Cl<em>2(g) + \Delta H</em>d \rightarrow Cl(g)
  • ΔHd=121.0kJmol\Delta H_d = 121.0 \frac{kJ}{mol}

Step 3: Gaseous Sodium Atom to Gaseous Cation

  • The energy required to remove 1 mole of electrons from 1 mole of gaseous atoms is the First Ionization Energy (IE).
  • Na(g)+IENa+(g)+eNa(g) + IE \rightarrow Na^+(g) + e^-
  • IE=495.8kJmolIE = 495.8 \frac{kJ}{mol}

Step 4: Gaseous Chlorine Atom to Gaseous Anion

  • The energy released when 1 mole of gaseous atoms accepts 1 mole of electrons is the First Electron Affinity (EA).
  • This process releases energy.
  • Cl(g)+eCl(g)+EACl(g) + e^- \rightarrow Cl^-(g) + EA
  • EA=349kJmolEA = -349 \frac{kJ}{mol}

Step 5: Combination of Oppositely Charged Gaseous Ions

  • The energy released when oppositely charged gaseous ions combine to form 1 mole of an ionic compound is the lattice energy (U).
  • Na+(g)+Cl(g)NaCl(s)+UNa^+(g) + Cl^-(g) \rightarrow NaCl(s) + U
  • U=769.8kJmolU = -769.8 \frac{kJ}{mol}

Calculating ΔHf (Enthalpy of Formation)

  • According to Hess’s Law, the sum of the energy changes during the various steps equals the enthalpy of formation (ΔHf\Delta H_f) of NaCl(s).
  • ΔH<em>f=ΔH</em>s+ΔHd+IE+EA+U\Delta H<em>f = \Delta H</em>s + \Delta H_d + IE + EA + U
  • ΔHf=108.5+121.0+495.8+(349)+(769.8)=393.5kJmol\Delta H_f = 108.5 + 121.0 + 495.8 + (-349) + (-769.8) = -393.5 \frac{kJ}{mol}

Calculating Lattice Enthalpy

  • The Born-Haber Cycle can calculate the lattice energy of an ionic solid if other thermodynamic data are known.
  • Example: Magnesium Fluoride (MgF2)
    • Sublimation Energy (S) of Mg = 146.4kJmol146.4 \frac{kJ}{mol}
    • IE1 of Mg = 737kJmol737 \frac{kJ}{mol}
    • IE2 of Mg = 1449kJmol1449 \frac{kJ}{mol}
    • Dissociation energy (D) of F = 158.8kJmol158.8 \frac{kJ}{mol}
    • EA of F = 328kJmol-328 \frac{kJ}{mol}
    • ΔHf\Delta H_f of MgF2 = 1096.5kJmol-1096.5 \frac{kJ}{mol}