Energy Measurement and Enthalpy

Calorie

  • Definition: The amount of energy required to raise the temperature of one gram of water by one degree Celsius.
  • Important Note: This is NOT the calorie commonly associated with food.

Kilocalorie (Food Calorie)

  • The calorie we typically think about in the context of food is actually a kilocalorie.
  • Representations:
    • Written with a capital C (Calorie).
    • Equivalent to 1,000 little 'c' calories.
  • 1 Calorie (big C)=1 kilocalorie=1000 calories (little c)1 \text{ Calorie (big C)} = 1 \text{ kilocalorie} = 1000 \text{ calories (little c)}
  • Significance: Our bodies require a substantial amount of energy to function, hence the use of kilocalories for measuring food energy.

Joule

  • The official scientific unit for energy.
  • Relationship to calorie:
    • 1 calorie (little c)=4.18 joules1 \text{ calorie (little c)} = 4.18 \text{ joules}
  • Utility: Allows conversion between food calories (kilocalories) and the scientific unit of energy (joules).

Calorie to Kilojoule Conversion Example

  • Goal: Convert a 150 Calorie (big C) beverage into kilojoules.
  • Relationships/Conversion Factors:
    • 1 Calorie (big C)=1000 calories (little c)1 \text{ Calorie (big C)} = 1000 \text{ calories (little c)}
    • 1 calorie (little c)=4.18 joules1 \text{ calorie (little c)} = 4.18 \text{ joules}
    • 1 kilojoule=1000 joules1 \text{ kilojoule} = 1000 \text{ joules}
  • Step-by-step Conversion using Dimensional Analysis:
    • Start with 150 Calories (big C).
    • Convert Calories to calories: 150 Cal×1000 cal1 Cal150 \text{ Cal} \times \frac{1000 \text{ cal}}{1 \text{ Cal}}
    • Convert calories to joules: 1000 cal1 Cal×4.18 J1 cal\frac{1000 \text{ cal}}{1 \text{ Cal}} \times \frac{4.18 \text{ J}}{1 \text{ cal}}
    • Convert joules to kilojoules: 4.18 J1 cal×1 kJ1000 J\frac{4.18 \text{ J}}{1 \text{ cal}} \times \frac{1 \text{ kJ}}{1000 \text{ J}}
    • Calculation: 150×1000×4.181×1×1000=627 kJ\frac{150 \times 1000 \times 4.18}{1 \times 1 \times 1000} = 627 \text{ kJ}
  • Result: A 150 Calorie beverage is equivalent to 627 kilojoules. This is what would be labeled on the product in Europe.

Heat Energy (q)

  • Symbol: Represented by the letter 'q' (can be uppercase or lowercase).
  • Units: Typically measured in joules, but can also be expressed in kilojoules.
  • Scope: Refers to the heat energy of a specific sample or substance.

Enthalpy (ΔH)

  • Definition: Energy gained or lost per mole of a substance.
  • Significance: Allows comparisons of energy changes, similar to stoichiometry.
  • Formula: Represented as delta H (ΔH\Delta H).
  • Units: Measured in kilojoules per mole (kJ/mol).
  • Incorporates: Combines heat energy (q) with the amount of substance (moles).

Enthalpy Calculation Example

  • Problem: Ten grams of C8H18 releases 480,000 joules of energy. Determine the enthalpy for the reaction.
  • Given:
    • Mass of C8H18 = 10 grams
    • Heat energy (q) = -480,000 joules (negative because energy is released)
  • Unknown: Enthalpy ($\Delta H$)
  • Step 1: Convert joules to kilojoules.
    • 480,000 J×1 kJ1000 J=480 kJ-480,000 \text{ J} \times \frac{1 \text{ kJ}}{1000 \text{ J}} = -480 \text{ kJ}
  • Step 2: Convert grams of C8H18 to moles using molar mass.
    • Molar mass of C8H18: (8×12.01)+(18×1.01)=114.26 g/mol(8 \times 12.01) + (18 \times 1.01) = 114.26 \text{ g/mol}
    • 10 g×1 mol114.26 g=0.0875 mol10 \text{ g} \times \frac{1 \text{ mol}}{114.26 \text{ g}} = 0.0875 \text{ mol}
  • Step 3: Calculate enthalpy ($\Delta H)bydividingkilojoulesbymoles.<ul><li>) by dividing kilojoules by moles.<ul> <li>\Delta H = \frac{-480 \text{ kJ}}{0.0875 \text{ mol}} = -5485.7 \text{ kJ/mol}
  • Step 4: Apply Significant Figures (2 significant figures due to “480,000” given).
    • $\Delta H \approx -5500 \text{ kJ/mol}
  • Final Answer: The enthalpy for the reaction is approximately -5500 kJ/mol.
  • Key Takeaway

    • Be aware of the difference between the food calorie (kilocalorie) and the scientific calorie when dealing with energy measurements.