Chemistry Review: Key Terms from Lecture (Chapter 1–3)
Molar Mass, Empirical vs Molecular Formulas, and Percent Composition
Key definitions
Molar mass (formula mass, formula weight): the mass of one mole of a substance, calculated by summing the atomic masses of all atoms in the formula. For a compound with subscripts, M = ∑(ni × Mi).
Molar ratio: the fixed ratio of atoms of each element within one mole of a compound, derived directly from the formula.
Empirical formula: the simplest whole-number ratio of the elements in a compound.
Molecular formula: the actual number of each type of atom in a molecule.
Empirical vs Molecular relationship: empirical formula may or may not equal the molecular formula. If you know the empirical formula and the molar mass, you can determine the molecular formula by finding an integer n such that Molecular formula = (Empirical formula) × n.
Elemental analysis (percent by mass): experimental determination of the mass percentages of elements in a compound, used to derive empirical formulas.
Example: Glucose (C6H12O6) and ribose
Molecular formula glucose: C6H12O6. Molar mass ≈ M{C6H{12}O6} = 6MC + 12MH + 6MO \ (MC \,≈\, 12.01\, g/mol, MH \≈\, 1.008\, g/mol, MO \≈\, 16.00\, g/mol)
M \approx 6(12.01) + 12(1.008) + 6(16.00) \approx 180.16\, g/mol.
Empirical formula for glucose: CH2O (same as for ribose, which has the same empirical formula but a different molecular formula).
Empirical formula is the lowest whole-number ratio. Molecular formula is the actual composition; sometimes identical, sometimes not.
To determine empirical formula experimentally, you determine percent by mass for each element and convert to moles, then reduce to the smallest whole-number ratio.
Percent by mass (ppm, mass percent)
Formula: ext{Percent by mass of element } X = rac{mX}{M{ ext{compound}}} imes 100 ext{%}
Example calculation for glucose (C6H12O6):
Carbon:
Carbon mass = 6 imes M_C = 6 imes 12.01 = 72.06\, \text{g}
Percent C ≈ \frac{72.06}{180.16} \times 100\% \approx 40.0\%.
Hydrogen:
Hydrogen mass = 12 \times M_H = 12 \times 1.008 = 12.096\, \text{g}
Percent H ≈ \frac{12.096}{180.16} \times 100\% \approx 6.71\%.
Oxygen:
Oxygen mass = 6 \times M_O = 6 \times 16.00 = 96.00\, \text{g}
Percent O ≈ \frac{96.00}{180.16} \times 100\% \approx 53.29\%.
Use the percentages to derive the empirical formula by converting each percent to moles (divide by the element’s atomic mass) and reducing to the smallest whole-number ratio.
Important note: Always verify calculated percentages with accurate atomic masses and molar mass; class notes may show approximations, but use standard atomic masses for exams.
Experimental determination and relationships
Empirical formula is obtained from elemental analysis (percent composition).
Molecular formula is determined from empirical formula and molar mass data: find n such that (Empirical formula) × n gives the molecular formula.
Sometimes, several formulas share the same empirical formula (e.g., an empirical formula of CH2O could correspond to multiple molecular formulas, depending on molar mass).
Isotopes and atomic structure (key concepts)
Subatomic particles and notation
Proton (p): positive charge, located in the nucleus; mass ≈ 1 amu.
Neutron (n): neutral, located in the nucleus; mass ≈ 1 amu.
Electron (e−): negative charge, located in the electron cloud; mass ≈ 0 amu.
Atomic number Z: number of protons; defines the element.
Mass number A: total number of protons and neutrons; A = Z + N.
Isotopes: atoms with the same Z and different N (different A).
Ions: atoms with a net charge due to loss or gain of electrons.
Cation: positively charged (loss of electrons).
Anion: negatively charged (gain of electrons).
Atomic symbol interpretation (example): for a symbol with A, Z, and N information, you can determine protons, neutrons, and electrons in neutral or charged states.
If Z = 11 and A = 22 (symbol often written as $^{22}_{11}$X):
Protons = Z = 11
Electrons in a neutral atom = Z = 11; if the species has a positive charge (+1), electrons = Z − 1 = 10
Neutrons = A − Z = 22 − 11 = 11
Weighted atomic mass: the atomic mass on the periodic table is the weighted average of naturally occurring isotopes, not a single isotope mass.
Avogadro’s number and mole concept
Avogadro’s number: N_A = 6.022 imes 10^{23} particles per mole.
Purpose: convert between moles and particles (atoms, molecules, or ions).
Common conversions:
Moles ⇄ Grams: use molar mass M: n = rac{m}{M}, m = nM.
Moles ⇄ Particles: N = n imes N_A.
Molar mass, formula weight, and molecular weight are numerically the same value; the difference lies in the units (g/mol vs amu per atom or per molecule).
Measurements, accuracy, precision, and significant figures
Qualitative vs quantitative data
Qualitative: descriptive, non-naceted (e.g., color, state).
Quantitative: numerical measurements (e.g., 4.56 g).
Measured values come with uncertainty (instrumental error).
Accuracy: closeness of measurements to the true value.
Precision: closeness of a set of measurements to each other.
Significant figures (sig figs): denote measurement precision. Rules to follow during calculations:
For multiplication/division: the result should have the same number of sig figs as the measurement with the fewest sig figs.
For addition/subtraction: the result should have the same number of decimal places as the measurement with the fewest decimal places.
Scientific notation is essential for handling very large or small numbers; do not overestimate precision from calculator display when it isn’t present in the measurement.
Density and unit conversions
Density as a conversion factor:
ho = rac{m}{V}Useful conversions involving density include turning volume into mass and vice versa (e.g., using density to convert mL to g).
Volume units: 1 mL = 1 cm^3; 1 L = 1000 mL.
The relationship between mass, volume, and density is often used to convert between grams, milliliters, and cubic centimeters.
Non-metric and metric conversions
Base metric steps: kg → g, g → mg, L → mL, etc. Use known equalities: 1 kg = 1000 g; 1 g = 1000 mg; 1 L = 1000 mL; 1 mL = 1 cm^3.
Temperature scales: Celsius to Kelvin: K = C + 273.15 (and conversely C = K - 273.15).
Chemical nomenclature and bonding basics (Chapter 3 overview)
Ionic vs covalent compounds
Ionic: typically metal + nonmetal; electrons transferred; formula units and names reflect ions (e.g., NaCl, MgO).
Covalent (molecular): typically nonmetals; sharing electrons; names use prefixes for the number of each atom (e.g., CO = carbon monoxide, SO3 = sulfur trioxide).
Diatomic molecules (to know by heart): H2, N2, O2, F2, Cl2, Br2, I2.
Polyatomic ions: common ions that contain more than one atom (e.g., sulfate SO4^{2-}, nitrate NO3^{-}, ammonium NH4^{+}); names and formulas must be memorized or derived from standard tables.
Ionic naming rules (basic): name of cation (metal or polyatomic ion) + name of anion (nonmetal with -ide suffix or polyatomic ion name).
Ionic compounds with variable oxidation states (transition metals): use charge to balance; e.g., iron oxides can be FeO (iron(II) oxide) or Fe2O3 (iron(III) oxide).
Molecular naming: prefixes indicate numbers (mono-, di-, tri-, etc.) except for the common first element which often does not use the prefix if it has a single atom (e.g., CO is carbon monoxide, not monocarbon monoxide).
Oxyacids and binary acids: naming rules differ between acids that contain hydrogen with a halogen (binary acids) and those with polyatomic oxyanions (oxyacids). Typical forms include hydro- + -ic acid for binary acids (e.g., HCl → hydrochloric acid) and the -ic/-ous naming for oxyacids depending on the polyatomic anion.
Examples from class: diphosphorus pentoxide (P2O5), sulfur trioxide (SO3), carbon monoxide (CO).
Practical exam-ready tips
Be fluent with converting between grams, moles, and number of particles (atoms/molecules) using M and N_A.
Be competent with empirical formula derivation from percent composition, and with determining molecular formulas from empirical formulas and molar mass.
Practice reading measuring devices and applying significant figures correctly in all steps.
Review metric prefixes, common density conversions, and the Celsius↔Kelvin temperature conversions.
Familiarize yourself with basic ionic vs covalent distinctions, common polyatomic ions, and basic molecular naming conventions.
Remember: the exact numbers for atomic masses in class notes may be rounded; use standard atomic masses from the periodic table when performing calculations.
Quick reference formulas to memorize
Molar mass: M =
\sumi ni M_iPercent by mass: ext{Percent}{X} = \frac{mX}{M} \times 100\%
Avogadro’s number: N_A = 6.022 \times 10^{23}
Moles to grams: n = \frac{m}{M} \quad ext{and} \ m = nM
Moles to particles: N = n N_A
Density: \rho = \frac{m}{V}
Volume conversions: 1 L = 1000 mL; 1 mL = 1 cm^3; 1 cm^3 = 1 mL
Temperature: K = C + 273.15
State of matter and energy notes: kinetic energy is associated with motion; potential energy is stored energy (e.g., in chemical bonds).
Summary equation reminders
Empirical formula derivation concept: identify smallest whole-number ratios from experimental data.
Molecular formula determination: if you know the empirical formula and the molar mass, compute n such that Molecular = (Empirical) × n.
Atomic composition from a symbol: given Z (protons) and A (mass number), infer neutrons N = A − Z and electrons (for neutral atoms, E = Z).
Isotopes and stability: heavier elements require more neutrons to remain stable; isotopes differ in neutron count while keeping Z constant.
Note on exam expectations (from course context)
Expect questions on: percent composition, empirical vs molecular formulas, molar mass calculations, conversion factors (metric and density-based), significant figures, measurement uncertainty, and basic ionic/molecular naming and formulas.
You may be given a dataset (percent composition) and asked to derive an empirical formula, or to compute a molecular formula from a given molar mass.