Comprehensive Physics Study Notes: Magnetic Effects of Current

Biot-Savart Law and Ampere's Circuital Law\n\n* The Biot-Savart Law: The magnetic field contribution dBdB produced by a small current element dldl carrying current II at a point located at distance rr is given by:\n dB=μ04πIdlsin(θ)r2dB = \frac{\mu_0}{4 \pi} \frac{I \, dl \sin(\theta)}{r^2}\n\n* Vector Form of Biot-Savart Law:\n dB=μ04πI(dl×r)r3d\mathbf{B} = \frac{\mu_0}{4 \pi} \frac{I (d\mathbf{l} \times \mathbf{r})}{r^3}\n\n* Ampere's Circuital Law: The line integral of the magnetic field B\mathbf{B} around any closed loop is equal to μ0\mu_0 times the total current II passing through the surface enclosed by the loop:\n Bdl=μ0I\oint \mathbf{B} \cdot d\mathbf{l} = \mu_0 I\n\n# Magnetic Fields Produced by Current-Carrying Conductors\n\n* Straight Current-Carrying Conductor: For a wire of finite length with angles ϕ1\phi_1 and ϕ2\phi_2 subtended at the point of observation located at a perpendicular distance aa from the wire:\n B=μ0I4πa(sin(ϕ1)+sin(ϕ2))B = \frac{\mu_0 I}{4 \pi a} (\sin(\phi_1) + \sin(\phi_2))\n\n* Infinite Long Current-Carrying Conductor: For an infinitely long straight wire, the magnetic field is:\n B=μ0I2πaB = \frac{\mu_0 I}{2 \pi a}\n\n* Semi-Infinite Wire: The magnetic field at one end of a semi-infinite wire is:\n B=μ0I4πaB = \frac{\mu_0 I}{4 \pi a}\n\n* Circular Current-Carrying Loop:\n * At the center of the loop (radius RR):\n B=μ0I2RB = \frac{\mu_0 I}{2 R}\n * At a point on the axis of the loop at a distance xx from the center:\n B=μ0IR22(R2+x2)3/2B = \frac{\mu_0 I R^2}{2 (R^2 + x^2)^{3/2}}\n\n* Current-Carrying Arc: For an arc of a circle with radius RR subtending an angle θ\theta at the center:\n B=μ0I2R×θ360B = \frac{\mu_0 I}{2 R} \times \frac{\theta}{360}\n\n* Solenoid:\n * Magnetic field inside a solenoid: B=μ0nIB = \mu_0 n I, where n=Nln = \frac{N}{l} (number of turns per unit length).\n * Magnetic field at the end of a solenoid: B=μ0nI2B = \frac{\mu_0 n I}{2}\n\n* Toroidal Solenoid: The magnetic field inside the core of a toroid is:\n B=μ0nIB = \mu_0 n I, where n=N2πRn = \frac{N}{2 \pi R}\n\n# Force Experienced by Charges and Conductors\n\n* Force on a Moving Charge: The magnetic force F\mathbf{F} on a charge qq moving with velocity v\mathbf{v} in a magnetic field B\mathbf{B} is:\n F=q(v×B)\mathbf{F} = q (\mathbf{v} \times \mathbf{B})\n F=qvBsin(θ)F = q v B \sin(\theta)\n\n* Force on a Current-Carrying Conductor: A conductor of length ll carrying current II in a magnetic field B\mathbf{B} experiences a force:\n F=I(l×B)\mathbf{F} = I (\mathbf{l} \times \mathbf{B})\n F=IlBsin(θ)F = I l B \sin(\theta)\n\n* Force Between Two Parallel Current-Carrying Conductors:\n * Total force on length ll with separation distance dd:\n F=μ0I1I2l2πdF = \frac{\mu_0 I_1 I_2 l}{2 \pi d}\n * Force per unit length:\n Fl=μ0I1I22πd\frac{F}{l} = \frac{\mu_0 I_1 I_2}{2 \pi d}\n * Direction of Force: If the currents flow in the same direction, the conductors experience an attractive force. If the currents flow in opposite directions, the conductors experience a repulsive force.\n\n# Motion of a Charged Particle in a Magnetic Field\n\n* Case 1: θ=0\theta = 0: The particle moves in a straight line.\n\n* Case 2: θ=90\theta = 90^\circ: The particle follows a circular path.\n * Radius of the circle: r=mvqBr = \frac{m v}{q B}\n * Time Period: T=2πmqBT = \frac{2 \pi m}{q B}\n\n* Case 3: 0<θ<900 < \theta < 90^\circ: The particle follows a helical path (θ\theta is the angle between velocity v\mathbf{v} and magnetic field B\mathbf{B}).\n * Radius of the helix: r=mvsin(θ)qBr = \frac{m v \sin(\theta)}{q B}\n * Pitch of the helix (linear distance covered per rotation): p=vcos(θ)×Tp = v \cos(\theta) \times T\n\n# Magnetic Dipole Moment and Torque\n\n* Magnetic Dipole Moment (MM or mm):\n * For a single current loop: M=IAM = I A\n * For a coil with NN turns: M=NIAM = N I A\n\n* Torque on a Current-Carrying Coil: A coil in a magnetic field experiences a torque τ\tau defined as:\n τ=NIBAsin(θ)\tau = N I B A \sin(\theta)\n τ=MBsin(θ)\tau = M B \sin(\theta)\n τ=M×B\mathbf{\tau} = \mathbf{M} \times \mathbf{B}