Factoring

GCF

  • The idea is simply ab+ac=a(b+c)ab + ac = a(b + c)

  • Ex: 2x+4=2(x+2)2x + 4 = 2(x + 2)

  • This is because both are divisible by 2.

Difference of Two Perfect Squares (DOTS)

  • The idea is x2+y2=(x+y)(xy)x² + y² = (x+y)(x-y)

  • Ex: x24=(x+2)(x2)x² - 4 = (x + 2)(x - 2)

  • This is because when factoring, you get x2+2x2x4x² + 2x - 2x - 4 and 2x2x=02x - 2x = 0, so we are just left with x24x² - 4.

Trinomial

  • The idea is find two numbers that add up to b and multiply to c.

  • Ex: x2+x6=(x+3)(x2)x² + x - 6 = (x+3)(x-2)

  • This is because b is 11 and c is 6-6 so 2 numbers that would multiply to c and add up to b is 33 and 2-2. 32=63 * -2 = -6, 3+(2)=13 + (-2) = 1.

AC Method

  • The idea is similar to trinomial but this is only if a1a ≠ 1.

  • Ex: 2x2+15x+18=(2x+3)(x+6)2x² + 15x + 18 = (2x + 3)(x + 6)

  • This is because a * c = 3636, and 33 and 1212 both add up to 15 and multiply to 36. We can then do 2x2+12x+3x+182x² + 12x + 3x + 18, then separate it up into two pairs:

    ((2x2+12x)+(3x+18)(2x² + 12x) + (3x + 18)). Then we can use GCF to separate a common factor from both pairs. 2x(x+6)+3(x+6)2x(x+6) + 3(x+6)(2x+3)(x+6)(2x+3)(x+6)

Quadratic Formula

  • Formula is x=b±b24ac2ax = \frac{-b \pm \sqrt{b² - 4ac}}{2a}

  • Ex: x2+4x20-x² + 4x - 20

  • We can break this down into what aa, bb, and cc are. aa is 1-1, since x2 has a coefficient of 1-1, bb is 44, since 4x4x has a coefficient of 44, cc is 20-20, this is common sense.

  • Let’s plug this into our equation: x=(4)±(4)24(1)(20)2(1)x = \frac{-(4) \pm \sqrt{(4)² - 4(-1)(-20)}}{2(-1)}x=4±16802x = \frac{-4 \pm \sqrt{16 - 80}}{-2}x=4±642x = \frac{-4 \pm \sqrt{-64}}{-2}x=2±642x = 2 \pm \frac{\sqrt{-64}}{-2}x=2±(64)(1)2x = 2 \pm \frac{\sqrt{(64)(-1)}}{-2}x=2±8i2x = 2 \pm \frac{8i}{-2}x=2±4ix = 2 \pm -4i