Polynomial Functions and Zeros
Polynomial Functions and Their Zeros
Fundamental Theorem of Algebra
- A polynomial function of degree $n$ has exactly $n$ complex zeros, counting multiplicities.
- Key Terms:
- Degree: The highest power of the variable in the polynomial.
- Complex Zeros: Includes both real and imaginary numbers.
- Multiplicity: The number of times a particular zero occurs (e.g., if $x-a$ is a factor repeated $k$ times, $a$ is a zero with multiplicity $k$).
Updated Theorem
- A polynomial function always has $n$ complex zeros. This means that both real zeros and imaginary zeros are counted towards the total zeros.
- Example: A degree five polynomial can have various combinations of real or imaginary zeros, including repeated zeros.
- E.g., For a polynomial $P(x)$ of degree 5:
- Possible zeros: $1, 1, -rac{1}{2}, i ext{sqrt}{3}, -i ext{sqrt}{3}$ (with $1$ being counted twice).
Real vs. Complex Numbers
- Complex Number Definition: Any number in the form $a + bi$, where:
- $a$ is the real part,
- $b$ is the imaginary part.
- Real numbers can be seen as complex numbers with the imaginary part set to zero (e.g., $6 + 0i$).
- Imaginary Numbers: Numbers in the form $bi$, where $b$ is a real number. Examples include:
- Purely Imaginary: $3i$, $-8i$, and $ ext{sqrt}{3}i$.
- Complex Imaginary: Numbers like $6 + 3i$, $7 - 2i$.
- Complex numbers include both real and imaginary numbers.
How to Find Complex Zeros
- If asked to find complex zeros, you must identify both real and imaginary solutions.
- If given a polynomial that is degree $n$, it will have exactly $n$ complex zeros, regardless of their nature (real or imaginary).
Conjugate Pairs Theorem
- Imaginary zeros come in conjugate pairs. This means if $a + bi$ is a zero of a polynomial, then $a - bi$ must also be a zero.
- Example: If $3 + 7i$ is a zero, then $3 - 7i$ is also a zero.
- Imaginary zeros must come from solving situations where square roots yield imaginary solutions, hence they appear in pairs due to the symmetry in their formation through square roots.
Example of Finding Zeros
- For a polynomial stated as follows:
P(x) = (x - 1)(x - 1)(x - (-rac{1}{2}))(x - (i ext{sqrt}{3}))(x - (-i ext{sqrt}{3}))
- Here, you see that $(x - 1)$ appears twice, indicating multiplicity of 2.
- Total: 5 zeros counted as $1, 1, -rac{1}{2}, i ext{sqrt}{3}, -i ext{sqrt}{3}$ indicating both real and imaginary roots are accounted for.
Polynomial Factoring
- All polynomials that can be factored meet specific criteria, such as:
- Always factoring into $n$ linear factors for a degree $n$ polynomial.
- This includes all chapter two polynomials within certain bounds as long as they are solvable within real or complex domains.
Finding Zeros with Multiplicities
- To find the multiplicity of a root, perform synthetic division to see if the root produces a remainder of zero consecutively.
- Use this to determine further roots until none can be found, indicating either single or multiple zeros.
- Example of finding multiplicity $2$ by checking if synthetic division yields $0$ again after already finding it zero once.
Solving Polynomial Inequalities
- These can either be graphical or analytical and often require sketching or testing intervals based on zeros.
- Inequalities like $P(x) < 0$ or $P(x) > 0$ prompt examining intervals between the zeros to determine where the polynomial is on the correct side (above or below the x-axis).
- Example Logically: If $f(x)$ is a sketch of polynomial, determine where the sketch lies inside bounds of x-axis:
- Where $P(x) < 0$ (below x-axis) or $P(x) > 0$ (above x-axis).
Analytical Approach for Inequalities
- Critical Points: Found from zeros of the polynomial; use them to split the number line.
- Choose sample points from each interval to test the inequality:
- If $f(x)=P(x)$ yields positive, the polynomial is above the x-axis in that interval, else it’s negative.
Summary of Quadratic Polynomials
- The polynomial $ ext{x}^2 - 13x + 42 = 0$ factors to $(x - 6)(x - 7)$.
- Analyzing graphical positions allows to conclude where $f(x) < 0$ provides the solutions directly from the zeroes.
- The interval notation for these solutions is denoted as $(- ext{infinity}, -6) igcup (-6, -7)$ for appropriate signs from $<0$.
Final Notes
- Always ensure to clarify use of brackets ([ ]) for inclusive treatment of equalities in inequalities versus parentheses (or ) for strictly greater or lesser functions.
- Graphical representation and sign analysis provides the easiest way to derive meaningful solutions while still adhering to polynomial rules and structures.