Laboratory Exercise 4: Vector Analysis and Static Equilibrium

Laboratory Objectives and Apparatus

  • Core Laboratory Objectives:

    • Master the analytical addition of vectors through the resolution of their orthogonal components.
    • Experimentally verify theoretical vector calculations using a physical force table apparatus.
    • Evaluate the conditions necessary to establish static translational equilibrium among concurrent coplanar forces.
  • Required Equipment and Supplies:

    • Force Table: A circular horizontal surface calibrated with angular degree markings from 0∘0^{\circ} to 360∘360^{\circ}.
    • Low-Friction Pulleys: Three specialized clamp-on pulleys designed to minimize resistive frictional forces along the perimeter of the force table.
    • Mass Hangers: Three calibrated hangers, each possessing an inherent mass of exactly 5 g5\,\text{g} (0.005 kg0.005\,\text{kg}).
    • Mass Set: A standardized assortment of slotted weights used to apply gravitational tension to the strings.
    • Central Ring and String Assembly: A small central ring (or knot) attached to strings radiating across the pulleys to represent concurrent force vectors.

Theoretical Principles of Vector Resolution

Resolution of vector A into orthogonal x and y components

  • Planar Vector Representation:

    • A vector A\mathbf{A} situated in a two-dimensional Cartesian plane can be uniquely resolved into the sum of two mutually perpendicular components directed along the coordinate axes.
    • By projecting perpendicular dashed lines from the terminus of vector A\mathbf{A} onto the horizontal xx-axis and vertical yy-axis, the orthogonal components AxA_x and AyA_y are isolated.
  • Component Formulations:

    • For a vector A\mathbf{A} with magnitude AA oriented at an angle θ\theta measured counterclockwise from the positive horizontal axis, the scalar components are given by:
    • Horizontal component:       Ax=Acos⁡(θ)A_x = A \cos(\theta)
    • Vertical component:       Ay=Asin⁡(θ)A_y = A \sin(\theta)

Analytical Vector Addition by Components

Addition of vectors A and B yielding resultant vector C

  • Resultant Vector Definition:

    • The geometric and algebraic sum of two independent coplanar vectors A\mathbf{A} and B\mathbf{B} produces a single resultant vector C\mathbf{C}:     C=A+B\mathbf{C} = \mathbf{A} + \mathbf{B}(Equation 1)
  • Orthogonal Component Relations:

    • The algebraic components of the resultant vector C\mathbf{C} equal the scalar sum of the individual vector components along each respective axis:     Cx=Ax+BxC_x = A_x + B_x(Equation 2)Cy=Ay+ByC_y = A_y + B_y(Equation 3)
  • Expanded Component Equations:

    • Given vector A\mathbf{A} oriented at angle θa\theta_a and vector B\mathbf{B} oriented at angle θb\theta_b:     Ax=Acos⁡(θa)A_x = A \cos(\theta_a)(Equation 4)Ay=Asin⁡(θa)A_y = A \sin(\theta_a)(Equation 5)Bx=Bcos⁡(θb)B_x = B \cos(\theta_b)(Equation 6)By=Bsin⁡(θb)B_y = B \sin(\theta_b)(Equation 7)
  • Resultant Magnitude and Direction:

    • The total magnitude of resultant vector C\mathbf{C} is calculated using the Pythagorean theorem:     C=(Cx2+Cy2)1/2C = \left(C_x^2 + C_y^2\right)^{1/2}(Equation 8)
    • The directional angle θc\theta_c of the resultant vector relative to the positive horizontal axis is determined by the inverse tangent function:     θc=tan⁡−1(CyCx)\theta_c = \tan^{-1}\left(\frac{C_y}{C_x}\right)(Equation 9)

Static Equilibrium on a Force Table

Three coplanar forces in equilibrium acting on a central knot

  • Translational Equilibrium Condition:

    • When multiple coplanar forces act concurrently on a central point, translational static equilibrium requires the vector sum of all forces to equal zero.
    • When equilibrium is achieved, the central knot (or ring) remains stationary and perfectly centered around the center pin at the origin:     A+B+C=0\mathbf{A} + \mathbf{B} + \mathbf{C} = \mathbf{0}(Equation 10)
  • Equilibrant Determination:

    • When forces A\mathbf{A} and B\mathbf{B} are applied by known hung masses, force C\mathbf{C} acts as the balancing force (the equilibrant).
    • The equilibrant vector C\mathbf{C} is exactly equal in magnitude and opposite in direction to the resultant of A\mathbf{A} and B\mathbf{B}:     C=−(A+B)=(−A)+(−B)\mathbf{C} = -(\mathbf{A} + \mathbf{B}) = (-\mathbf{A}) + (-\mathbf{B})(Equation 11)
    • The orthogonal components for the balancing force C\mathbf{C} satisfy:     Cx=−(Ax+Bx)C_x = -(A_x + B_x)Cy=−(Ay+By)C_y = -(A_y + B_y)
  • Gravitational Force Conversion:

    • The downward gravitational force (tension along the string in Newtons) is generated by suspended masses.
    • Every applied force must include both the added mass and the mass of the hanger:     Total Mass (m)=madded+mhanger\text{Total Mass } (m) = m_{\text{added}} + m_{\text{hanger}}mhanger=5 g=0.005 kgm_{\text{hanger}} = 5\,\text{g} = 0.005\,\text{kg}
    • Force calculation equation:     F=m×gF = m \times g     where g=9.8 m/s2g = 9.8\,\text{m/s}^2.
    • Definition of unit force:     1 N=1 kg×9.8 m/s21\,\text{N} = 1\,\text{kg} \times 9.8\,\text{m/s}^2

Experimental Procedures

  • Procedure A: Initial Setup of Apparatus

    • Position the force table on an entirely level, horizontal plane to eliminate gravitational bias.
    • Clamp three low-friction pulleys securely to the circular outer rim of the force table.
    • Thread strings from the central ring over each pulley and attach mass hangers to the loose ends.
  • Procedure B: Fixed Angle Balancing

    • Step 1 — Configure Force A:
    • Suspend an added mass of 20 g20\,\text{g} onto the hanger (total mass =25 g=0.025 kg= 25\,\text{g} = 0.025\,\text{kg}).
    • Secure the pulley clamp at an angular position of 0∘0^{\circ}.
    • Step 2 — Configure Force B:
    • Suspend an added mass of 10 g10\,\text{g} onto the hanger (total mass =15 g=0.015 kg= 15\,\text{g} = 0.015\,\text{kg}).
    • Secure the pulley clamp at an angular position of 270∘270^{\circ}.
    • Step 3 — Balance with Force C:
    • Clamp the third pulley at an angular position of 150∘150^{\circ}.
    • Place an initial added mass of 20 g20\,\text{g} on the hanger (initial total mass =25 g= 25\,\text{g}).
    • Incrementally add or subtract small masses on this third hanger until the central knot is centered at the origin pin.
    • Step 4 — Friction Compensation:
    • Due to residual friction within the pulley bearings, gently tap the strings to overcome static friction and initiate equilibrium motion.
    • Step 5 — Recording Data:
    • Record the experimental mass required to achieve center equilibrium and the experimental angle of 150∘150^{\circ}.
  • Procedure C: Trial and Error Balancing

    • Step 1 — Configure Two Initial Forces:
    • Clamp the first pulley at an angle of 0∘0^{\circ} with an added mass of 200 g200\,\text{g} on the hanger (total mass =205 g=0.205 kg= 205\,\text{g} = 0.205\,\text{kg}).
    • Clamp the second pulley at an angle of 210∘210^{\circ} with an added mass of 250 g250\,\text{g} on the hanger (total mass =255 g=0.255 kg= 255\,\text{g} = 0.255\,\text{kg}).
    • Step 2 — Determine Force C by Trial and Error:
    • Move the third pulley along the circumference and adjust the suspended mass simultaneously through iterative trial and error.
    • Adjust both the angular position and suspended mass until the central knot centers at the origin.
    • Tap the strings lightly between mass and angle adjustments to overcome pulley friction.
    • Step 3 — Recording Data:
    • Record the final balancing angle and the total suspended mass (including the 5 g5\,\text{g} hanger).

Calculations, Analysis, and Data Organization

  • Analytical Calculation Steps:

    • Convert all masses from grams to kilograms (kg=g1000\text{kg} = \frac{\text{g}}{1000}).
    • Compute the tension force in Newtons for each vector by multiplying total mass in kilograms by 9.8 m/s29.8\,\text{m/s}^2.
    • Resolve known vectors A\mathbf{A} and B\mathbf{B} into horizontal (Ax,BxA_x, B_x) and vertical (Ay,ByA_y, B_y) components.
    • Sum components algebraically to find resultant components Rx=Ax+BxR_x = A_x + B_x and Ry=Ay+ByR_y = A_y + B_y.
    • Calculate theoretical equilibrant components Cx=−RxC_x = -R_x and Cy=−RyC_y = -R_y.
    • Compute theoretical equilibrant magnitude C=Cx2+Cy2C = \sqrt{C_x^2 + C_y^2} and direction θc=tan⁡−1(CyCx)\theta_c = \tan^{-1}\left(\frac{C_y}{C_x}\right), adjusting the angle for the correct quadrant.
    • Convert theoretical force CC back into equivalent mass in kilograms (m=C9.8 m/s2m = \frac{C}{9.8\,\text{m/s}^2}).
  • Data Sheet Format:

ParameterForce AForce BForce C (Experimental)Force C (Calculated)
Mass (kg\text{kg})Total mass including 0.005 kg0.005\,\text{kg} hangerTotal mass including 0.005 kg0.005\,\text{kg} hangerMeasured balancing mass including hangerTheoretically calculated balancing mass
Force (N\text{N})mA×9.8 m/s2m_A \times 9.8\,\text{m/s}^2mB×9.8 m/s2m_B \times 9.8\,\text{m/s}^2mC,exp×9.8 m/s2m_{C,\text{exp}} \times 9.8\,\text{m/s}^2Theoretical magnitude CC
Angle (θ\theta)θa\theta_aθb\theta_bMeasured balancing angle θc\theta_cTheoretical balancing angle θc\theta_c
  • Tabulation Requirements:
    • Present experimental values alongside theoretically calculated values for both Procedure B and Procedure C.
    • Explicitly show full component breakdown calculations and trigonometric formulations in the designated reporting space.

According to Source 1: Laboratory Exercise 4: Vector Analysis and Static Equilibrium, here is the step-by-step procedure to perform the experiment:

Step 1: Apparatus Setup (Procedure A)
  1. Place the circular force table on a completely flat, level horizontal surface to avoid gravitational tilt.
  2. Clamp three low-friction pulleys along the outer rim of the force table.
  3. Attach three strings to the central ring (or knot), drape each string over a pulley, and tie a calibrated mass hanger (5 g5\,\text{g} or 0.005 kg0.005\,\text{kg}) to the loose end of each string.
Step 2: Fixed Angle Balancing (Procedure B)
  1. Set up Force A:
    • Place 20 g20\,\text{g} of added slotted mass onto the hanger (giving a total mass of 25 g=0.025 kg25\,\text{g} = 0.025\,\text{kg} including the 5 g5\,\text{g} hanger).
    • Clamp this pulley at an angle of 0∘0^{\circ}.
  2. Set up Force B:
    • Place 10 g10\,\text{g} of added mass onto the hanger (total mass =15 g=0.015 kg= 15\,\text{g} = 0.015\,\text{kg}).
    • Clamp this pulley at an angle of 270∘270^{\circ}.
  3. Balance with Force C:
    • Clamp the third pulley at an angle of 150∘150^{\circ}.
    • Start with an initial added mass of 20 g20\,\text{g} on the hanger (initial total mass =25 g= 25\,\text{g}).
    • Incrementally add or remove small masses until the central knot is centered directly over the origin pin.
  4. Compensate for Pulley Friction:
    • Gently tap the strings to overcome static friction in the pulley bearings and verify that the knot remains centered.
  5. Record Experimental Values:
    • Record the final balancing mass (including the 5 g5\,\text{g} hanger) and the angle (150∘150^{\circ}) in the Procedure B table.
Step 3: Trial and Error Balancing (Procedure C)
  1. Set up the Two Known Forces:
    • Clamp the first pulley at 0∘0^{\circ} with 200 g200\,\text{g} added to the hanger (total mass =205 g=0.205 kg= 205\,\text{g} = 0.205\,\text{kg}).
    • Clamp the second pulley at 210∘210^{\circ} with 250 g250\,\text{g} added to the hanger (total mass =255 g=0.255 kg= 255\,\text{g} = 0.255\,\text{kg}).
  2. Find Force C by Trial and Error:
    • Adjust both the angular position of the third pulley and the mass suspended from its hanger simultaneously by trial and error.
    • Tap the strings lightly after adjustments until the central ring remains centered at the origin.
  3. Record Experimental Values:
    • Record the final balancing angle and the total suspended mass (including the hanger).
Step 4: Analytical Calculations and Comparison
  1. Convert Masses to Tension Forces:
    • Ensure all masses are converted to kilograms (kg=g1000\text{kg} = \frac{\text{g}}{1000}), including the 0.005 kg0.005\,\text{kg} hanger mass.
    • Calculate force in Newtons: F=m×9.8 m/s2F = m \times 9.8\,\text{m/s}^2.
  2. Resolve Vectors into Components:
    • A<em>x=Acos⁡(θ</em>a)A<em>x = A\cos(\theta</em>a), A<em>y=Asin⁡(θ</em>a)A<em>y = A\sin(\theta</em>a)
    • B<em>x=Bcos⁡(θ</em>b)B<em>x = B\cos(\theta</em>b), B<em>y=Bsin⁡(θ</em>b)B<em>y = B\sin(\theta</em>b)
  3. Calculate Theoretical Equilibrant (Force C):
    • Sum the components and reverse the sign for static equilibrium (A+B+C=0\mathbf{A} + \mathbf{B} + \mathbf{C} = 0):
      • C<em>x=−(A</em>x+Bx)C<em>x = -(A</em>x + B_x)
      • C<em>y=−(A</em>y+By)C<em>y = -(A</em>y + B_y)
    • Find theoretical magnitude: C=C<em>x2+C</em>y2C = \sqrt{C<em>x^2 + C</em>y^2}
    • Find theoretical angle: θ<em>c=tan⁡−1(C</em>yC<em>x)\theta<em>c = \tan^{-1}\left(\frac{C</em>y}{C<em>x}\right) (adjust for the correct quadrant based on signs of C</em>xC</em>x and CyC_y).
    • Calculate theoretical mass: m=C9.8 m/s2m = \frac{C}{9.8\,\text{m/s}^2}.
  4. Complete the Report:
    • Enter both the experimentally measured and theoretically calculated values in the data tables for Procedure B and Procedure C and show your component calculations.