Chem Test

Chemistry Eighth Edition Chapter 16 Study Notes

Overview

  • Authors: Jill K. Robinson, John E. McMurry, Robert C. Fay

  • License: Copyright © 2020, 2016, 2012 Pearson Education, Inc., All Rights Reserved.

  • Course: Chem 1212, Principles of Chemistry II

  • Topics Covered:

    • Acid/Base Chemistry

    • Thermodynamics

    • Reaction Rates

Acid–Base Concepts: The Brønsted–Lowry Theory (1 of 4)

  • Arrhenius Acid:

    • Definition: A substance that dissociates in water to produce hydrogen ions, H⁺.

  • Arrhenius Base:

    • Definition: A substance that dissociates in water to produce hydroxide ions, OH⁻.

Acid–Base Concepts: The Brønsted–Lowry Theory (2 of 4)

  • Brønsted-Lowry Acid:

    • Definition: A substance that can transfer hydrogen ions, H⁺. In other words, a proton donor.

  • Brønsted-Lowry Base:

    • Definition: A substance that can accept hydrogen ions, H⁺. In other words, a proton acceptor.

  • Conjugate Acid-Base Pairs:

    • Definition: Chemical species whose formulas differ only by one hydrogen ion, H⁺.

Acid–Base Concepts: The Brønsted–Lowry Theory (3 of 4)

  • Acid-Dissociation Equilibrium:

    • Reaction:
      HA(aq)+H2O(l)⇌H3O+(aq)+A−(aq)HA(aq) + H₂O(l) ⇌ H₃O^+(aq) + A^−(aq)

    • Where HA is the acid, H₂O is the base, H₃O⁺ is the conjugate acid, and A⁻ is the conjugate base.

Acid–Base Concepts: The Brønsted–Lowry Theory (4 of 4)

  • Base-Dissociation Equilibrium:

    • Reaction:
      B(aq)+H2O(l)⇌HB+(aq)+OH−(aq)B(aq) + H₂O(l) ⇌ HB^+(aq) + OH⁻(aq)

    • Where B is the base, H₂O is the acid, HB⁺ is the conjugate acid, and OH⁻ is the conjugate base.

Hydrated Protons and Hydronium Ions

  • Due to the high reactivity of the hydrogen ion, it is actually hydrated by one or more water molecules.

  • For practical purposes, H⁺ is considered equivalent to H₃O⁺.

Acid Strength and Base Strength (1 of 3)

  • With equal concentrations of reactants and products, the direction of reaction favored is:
    extStrongerAcid+extStrongerBase<br>ightarrowextWeakerAcid+extWeakerBaseext{Stronger Acid} + ext{Stronger Base} <br>ightarrow ext{Weaker Acid} + ext{Weaker Base}

Acid Strength and Base Strength (2 of 3)

  • Weak Acid:

    • Definition: An acid that is only partially dissociated in water; it acts as a weak electrolyte.

Acid Strength and Base Strength (3 of 3)




  • Table 16.1: Relative Strengths of Conjugate Acid-Base Pairs


    Acid (HA)

    Base (A⁻)

    Strength



    HClO₄

    Cl⁻

    Strong Acid



    H₂SO₄

    HSO₄⁻

    Strong Acid



    HNO₃

    NO₃⁻

    Strong Acid



    H₃O⁺

    H₂O

    Weak Acid



    H₂S

    HS⁻

    Weak Acid



    NH₄⁺

    NH₃

    Weak Base






    Factors That Affect Acid Strength (1 of 4)




    • Bond Polarity:

      • The strength of an acid is affected by the polarity of the H-A bond, which in turn is influenced by the electronegativity of element A.

    • Electronegativity Values:

      • CH₄: 2.5

      • NH₃: 3.0

      • H₂O: 3.5

      • HF: 4.0

    Factors That Affect Acid Strength (2 of 4)

    • Bond Strength:

      • The strength of the H-A bond determines the acidity such that:
        extAcidStrength:HF<HCl<HBr<HIext{Acid Strength: HF < HCl < HBr < HI}

    • Relative bond strengths in kcal/mol:

      • HF: 570

      • HCl: 432

      • HBr: 366

      • HI: 298

    Factors That Affect Acid Strength (3 of 4)

    • Oxoacids:

      • Acid strength is influenced by the electronegativity of Y in H-O-Y.

      • General trend in oxoacid strength:
        extH−O−I<H−O−Br<H−O−Clext{H-O-I < H-O-Br < H-O-Cl}

    Factors That Affect Acid Strength (4 of 4)

    • Oxoacids:

      • Number of O atoms also impacts acid strength:
        extH−O−Cl<H−O−αl<H−O−αo<H−O−αext{H-O-Cl < H-O-αl < H-O-αo < H-O-α}

    • Oxidation numbers for Cl:

      • Hypochlorous: +1

      • Chlorous: +3

      • Chloric: +5

      • Perchloric: +7

    Dissociation of Water (1 of 4)

    • General reaction for water dissociation:
      2H2O(l)⇌H3O+(aq)+OH−(aq)2 H₂O(l) ⇌ H₃O⁺(aq) + OH⁻(aq)

    • Ion-Product Constant for Water:

      • At 25 °C:
        Kw=[H3O+][OH−]=1.0imes10−14K_w = [H₃O^+][OH^-] = 1.0 imes 10^{-14}

      • Both [H₃O⁺] and [OH⁻] are equal to 1.0imes10−7M1.0 imes 10^{-7} M.

    Dissociation of Water (2 of 4)

    • Equilibrium expression:
      Kw=[H2O+][OH−]K_w = [H₂O⁺][OH^-]

    Dissociation of Water (3 of 4)

    • Concentration scenarios:

      • Acidic solution:
        [H3O+]>[OH−][H₃O^+] > [OH^-]

      • Neutral solution:
        [H2O+]=[OH−][H₂O⁺] = [OH^-]

      • Basic solution:
        [H3O+]<[OH−][H₃O^+] < [OH^-]

    Dissociation of Water (4 of 4)

    • pH scale:

      • Acidic: pH < 7

      • Neutral: pH = 7

      • Basic: pH > 7

    The pH Scale (1 of 4)




    • The pH is calculated using:
      extpH=−extlog([H3O+])ext{pH} = - ext{log}([H₃O^+])



    • Concentration levels of hydronium and corresponding pH:


      Concentration (M)

      pH



      1.0

      0



      1.0×10^-1

      1



      1.0×10^-2

      2



      1.0×10^-3

      3



      …

      …



      1.0×10^-7

      7





      The pH Scale (2 of 4)



      • Example problem:

        • Given [H₃O⁺] = 0.0025 M, calculate pH:
          extpH=−extlog(0.0025)extgivespHextvalue.ext{pH} = - ext{log}(0.0025) ext{ gives } pH ext{ value.}

      The pH Scale (3 of 4)

      • Example problem:

        • Calculate pH for an aqueous ammonia solution with [OH⁻] = 0.0019 M:
          extpH=14−extpOHext(usepOHtofindpH).ext{pH} = 14 - ext{pOH} ext{ (use pOH to find pH).}

      The pH Scale (4 of 4)

      • Acid rain is a significant environmental concern as most aquatic life dies in waters with pH lower than 4.5-5.0.

      • Example problem: Calculate [H₃O⁺] for a lake with pH 4.5:
        [H3O+]=10−4.5M[H₃O^+] = 10^{-4.5} M

      The pH in Solutions of Strong Acids and Strong Bases (1 of 2)

      • Example: Calculate pH of a 0.025 M HNO₃ solution:

        • Since HNO₃ is a strong acid,
          [H3O+]=[HNO3]=0.025M[H₃O^+] = [HNO₃] = 0.025 M

      • Resulting pH can be obtained using the pH formula.

      The pH in Solutions of Strong Acids and Strong Bases (2 of 2)

      • Example: Calculate pH of a solution made from 500 mg NaOH in 500 mL of water:
        ext[OH−]=rac0.5g39.99g/molimes0.5L=0.025Mext{[OH⁻]} = rac{0.5g}{39.99 g/mol imes 0.5 L} = 0.025 M

      Equilibria in Solutions of Weak Acids

      • General reaction for weak acids:
        HA(aq)+H2O(l)⇌H3O+(aq)+A−(aq)HA(aq) + H₂O(l) ⇌ H₃O⁺(aq) + A⁻(aq)

      • Acid-Dissociation Constant (Kₐ):
        Ka=rac[H3O+][A−][HA]Kₐ = rac{[H₃O^+][A^-]}{[HA]}

      Acid-Dissociation Constants at 25 °C (Table 16.2)

      • The proton transferred to water during acid dissociation is shown in red.

      • For weak acids, pKₐ is calculated by:
        pKa=−extlogKapKₐ = - ext{log}Kₐ

      Calculating Equilibrium Concentrations of Weak Acids (1 of 2)

      • For example, to find pH of a 0.10 M HCN solution at 25 °C:

        • Use ICE table method to determine equilibrium concentrations.

        • Use the formula to calculate [H₃O⁺] and pH.

      Calculating Equilibrium Concentrations of Weak Acids (2 of 2)

      • Example Calculation: HCN dissociated as follows:
        HCN(aq)+H2O(l)⇌H3O+(aq)+CN−(aq)HCN(aq) + H₂O(l) ⇌ H₃O⁺(aq) + CN⁻(aq)

      • Given:

        • Ka=4.9imes10−10Kₐ = 4.9 imes 10^{-10}

        • Solving for x gives the concentrations leading to a pH calculation.

      Equilibria in Solutions of Weak Acids

      • Example: Hypothetical 0.250 M HF solution has a pH of 2.036:

        • Use pH to find [H₃O⁺] and backtrack to find Kₐ and pKₐ.

      Percent Dissociation in Solutions of Weak Acids

      • Definition:
        ext{Percent Dissociation} = rac{[ ext{HA}]}{[ ext{HA}]_{initial}} imes 100 ext{%}

      • Example calculation illustrates how the percent dissociation increases as concentration decreases.

      Equilibria in Solutions of Weak Bases (1 of 4)

      • Example reaction for weak bases:
        B(aq)+H2O(l)⇌BH+(aq)+OH−(aq)B(aq) + H₂O(l) ⇌ BH⁺(aq) + OH⁻(aq)

      • Base-Dissociation Constant (Kb):
        K</em>b=rac[BH+][OH−][B]K</em>b = rac{[BH^+][OH^-]}{[B]}

      Equilibria in Solutions of Weak Bases (2 of 4)




      • Table 16.4: Kb Values for Some Weak Bases


        Base

        Formula

        Kb

        Conjugate Acid

        Ka



        Ammonia

        NH₃

        1.8×10⁻⁵

        NH₄⁺

        5.6×10⁻¹⁰








        Equilibria in Solutions of Weak Bases (3 of 4)






        • Example: Calculate pH of a 0.40 M NH₃ solution at 25 °C.

        • Using ICE approach and equilibrium expression helps find pH.

        Equilibria in Solutions of Weak Bases (4 of 4)

        • Using approximation method for Kb allows finding of hydroxide concentration:
          [OH−]=x,extthenpH=−extlog([H3O+])[OH^-] = x, ext{ then } pH = - ext{log}([H₃O^+])

        Relation Between Ka and Kb (1 of 2)

        • Example involving NH₄⁺ dissociation provides a relationship between Kₐ and Kb: K</em>w=K<em>aimesK</em>bK</em>w = K<em>a imes K</em>b

        Relation Between Ka and Kb (2 of 2)

        • The relationship holds true for conjugate acid-base pairs, allowing interconversion between pKₐ and pKb values: pKa+pK</em>b=14.00pKₐ + pK</em>b = 14.00

        Polyprotic Acids (1 of 4)

        • Example of polyprotic acid dissociation with carbonic acid: H2CO3(aq)+H2O(l)⇌H3O+(aq)+HCO3−(aq)H₂CO₃(aq) + H₂O(l) ⇌ H₃O⁺(aq) + HCO₃⁻(aq)

          • Ka1 = 4.3×10⁻⁷

        Polyprotic Acids (2 of 4)




        • Table 16.3: Stepwise Dissociation Constants for Polyprotic Acids at 25 °C


          Acid

          Formula

          Ka1

          Ka2

          Ka3









          Acid–Base Properties of Salts (1 of 9)






          • Salts Yielding Neutral Solutions:

            • Cations from strong bases (e.g., Li⁺, Na⁺).

            • Anions from strong monoprotic acids (e.g., Cl⁻, NO₃⁻).

          Acid–Base Properties of Salts (2 of 9)

          • Salts Yielding Acidic Solutions:

            • Derived from weak bases and strong acids (e.g., NH₄Cl).

          Acid–Base Properties of Salts (3 of 9)

          • Small, highly charged metal cations can produce acidity.

          Acid–Base Properties of Salts (4 of 9)

          • Reaction with water can produce H₃O⁺, leading to an acidic solution.

          Acid–Base Properties of Salts (5 of 9)

          • Salts Yielding Basic Solutions:

            • Derived from strong bases and weak acids (e.g., NaCN).

          Acid–Base Properties of Salts (6 of 9)

          • Solutions depend on relative acid and base strength (e.g., ammonium carbonate).

          Acid–Base Properties of Salts (7 of 9)

          • Distinguishing acidic and basic properties based on strength ratios (Ka and Kb).

          Acid–Base Properties of Salts (8 of 9)

          • Theoretical calculations for salts can result in various pH outcomes.

          Acid–Base Properties of Salts (9 of 9)




  • Table 16.5: Acid-Base Properties of Salts


    Type of Salt

    Examples

    Ions That React with Water

    pH of Solution








    Lewis Acids and Bases (1 of 3)





    • Lewis Acid: An electron-pair acceptor.

    • Lewis Base: An electron-pair donor.

    Lewis Acids and Bases (2 of 3)

    • Example reactions involving copper ions and ammonia show formation of complexes.

    Lewis Acids and Bases (3 of 3)

    • Sulfuric acid as a Lewis acid accepts electron pairs from bases.