Unit 1: Matter & Measurement (class notes)

Domain and Methods of Science

  • A way of seeing and understanding.

  • Requires an agreed-upon method.

  • Relies on observation.

  • Quantitative measurements are preferred (numerical).

  • Involves moving from observation to understanding through a two-stage process.

Stage 1: Discovery Cycle

  • Experiment: An action or process carried out to test a hypothesis or theory.

  • Natural Law: A statement of what occurs without exception.

  • Theory: A logical model explaining why things occur.

    • Examples: Gravity, Conservation of Mass, Life begets Life.

    • Not static; testable by experiment.

    • Modified incrementally via the cycle of understanding.

    • Examples include geocentric theory.

Stage 2: Understanding Cycle

  • Prediction: an expected outcome based on a theory. For example:

    • Theory 1: Less massive gases than nitrogen rise in air because their gravitational attraction is less.

      • Prediction: Hydrogen should rise, Helium should not.

    • Theory 2: Gases that form stable compounds with oxygen burn.

      • Prediction: Helium should not burn, Argon should not burn.

  • Experiment: Testing predictions, leading to modification of theories.

Chemistry

  • Definition: The branch of science that deals with the identification of the substances of which matter is composed; the investigation of their properties and the ways in which they interact, combine, and change; and the use of these processes to form new substances.

  • Study of matter, properties, composition, structure, interactions, and changes.

  • Examples: Graphite and Diamond (different structures, same composition).

Branches of Chemistry

  • Physical Chemistry: Studies the physics, matter, and energy of chemicals at an atomic and molecular level.

  • Analytical Chemistry: Utilizes different methods, instruments, and techniques to study and quantify different matter.

  • Biochemistry: Studies chemical reactions and processes in living things.

  • Organic Chemistry: Studies the structure, synthesis, and properties of organic compounds (containing carbon).

  • Inorganic Chemistry: Studies the structure, synthesis, and properties of inorganic compounds (containing metals).

  • Theoretical Chemistry: Studies key chemistry concepts and the theories behind them.

  • Materials Chemistry: Studies and creates different materials for a specific function.

Matter Classification

What is Matter?

  • Anything that has mass and occupies space.

Physical States

  • Solid: Fixed shape, fixed volume.

  • Liquid: No fixed shape, fixed volume.

  • Gas: No fixed shape, no fixed volume.

Fundamental Composition

  • Elements: Composed of atoms; cannot be broken down into smaller pieces.

    • Need to know the first four rows of the periodic table along with Rb, Cs, Sr, Ba, Pd, Ag, Cd, Sn, I, Xe, Pt, Au, Hg, and Pb.

  • Compounds: Composed of more than one atom in fixed proportions.

  • Mixtures: Can be separated into elements, compounds, or both.

    • Homogeneous: Uniform.

    • Heterogeneous: Non-uniform.

Example 1
  • Classify the following:

    1. Sweet Tea: Homogeneous mixture

    2. Copper: Element

    3. Blood: Heterogeneous mixture

    4. Glucose: Compound

    5. Diamond: Element

Calculations

  • Error in measurements must always be considered.

  • Error can be in accuracy (agreement with true value) or in precision (agreement of the values with each other).

Types of Error

  • Determinate (Systematic): Associated with poor accuracy; values are off in one direction.

  • Indeterminate (Random): Associated with poor precision; values are high and low.

Significant Figures

  • All non-zero digits are significant (1, 2, 3, …, 9).

  • All captive zeros are significant (105, 3507, 14025).

  • Leading zeros are not significant (0.0035, 0.0589, 0.0701).

  • Trailing zeros before a decimal point are significant if specified in the problem (350.24, 3500., 3500).

  • Trailing zeros after a decimal point are significant (35.0, 37.230, 97.000).

  • Conversion factors have infinite significant figures and are ignored.

Example 2

  • How many significant figures?

    • A. 2730.78 m: 6

    • B. 0.0076 mL: 2

    • C. 3400 kg: 2

    • D. 3400.0 m2^2: 5

Math with Significant Digits

Multiplication/Division

  • Limited by the number of significant digits.

  • Example: 278mm11.70g=23.8mm/g\frac{278 \, mm}{11.70 \, g} = 23.8 \, mm/g

Addition/Subtraction

  • Limited by the number of decimal places.

  • Example: 3.18L+0.01315L=3.19L3.18 \, L + 0.01315 \, L = 3.19 \, L

3 significant figures / 3 significant figures --> 3 significant figures
2 decimal places / 5 decimal places --> 2 decimal places

  • Example:
    (57.890cc+73.2cc)/0.37cc=131.09cc/0.37cc=354.297cc=350cc(57.890 \, cc + 73.2 \, cc) / 0.37 \, cc = 131.09 \, cc / 0.37 \, cc = 354.297 \, cc = 350 \, cc
    3 decimal places + 1 decimal place --> Keep 1 decimal place
    4 significant digits / 2 significant digits -->Round to 2 significant digits

Example 3

  • Solve and round to the correct number of significant digits:
    3.4781.1642.00+0.35415.41514.515+3.465+0.0402597\frac{3.478 * 1.164}{2.00} + \frac{0.354}{15.415 - 14.515} + 3.465 + 0.0402597

Units of Measurement

International System of Units (SI)

SI Base Units

Base Quantity

Name

Symbol

Length

meter

m

Mass

kilogram

kg

Time

second

s

Electric current

ampere

A

Thermodynamic temperature

kelvin

K

Amount of substance

mole

mol

Luminous intensity

candela

cd

SI Prefixes

Factor

Name

Symbol

Numerical Value

101210^{12}

tera

T

1,000,000,000,000

10910^9

giga

G

1,000,000,000

10610^6

mega

M

1,000,000

10310^3

kilo

k

1,000

10210^2

hecto

h

100

10110^1

deka

da

10

10110^{-1}

deci

d

0.1

10210^{-2}

centi

c

0.01

10310^{-3}

milli

m

0.001

10610^{-6}

micro

μ

0.000001

10910^{-9}

nano

n

0.000000001

101210^{-12}

pico

p

0.000000000001

SI Derived Units

Derived Quantity

Name

Symbol

SI Units

Frequency

hertz

Hz

s1s^{-1}

Force

newton

N

mkgs2m \cdot kg \cdot s^{-2}

Pressure

pascal

Pa

N/m2m^2

Energy

joule

J

NmN \cdot m

Power

watt

W

J/s

Electric charge

coulomb

C

sAs \cdot A

Electric potential

volt

V

W/A

Electric resistance

ohm

Ω

V/A

Celsius temperature

degree Celsius

°C

K

Example 1

  • 1 micrometer (µm) = 0.000001 (1×1061 \times 10^{-6}) meters (m) OR 1,000,000 (1×1061 \times 10^6) micrometers = 1 meter (m)

  • The average width of human hair is 53 µm. What is this measurement in meters?
    53µm1×106m1µm=5.3×105m53 \, µm * \frac{1 \times 10^{-6} m}{1 \, µm} = 5.3 \times 10^{-5} m
    53µm1m1×106µm=5.3×105m53 \, µm * \frac{1 \, m}{1 \times 10^{6} µm} = 5.3 \times 10^{-5} m

Unit Cancellation

  • Unit Cancellation helps to direct the calculation toward the correct answer with the correct units.

  • What is the speed of light in mi/hr and how many times does light circle the globe at the equator every second?

  • Given Information: Equator = 24901 miles | Speed of light = 2.998×1082.998 \times 10^8 m/s | 1.609 km = 1 mile

2.998×108ms1km1×103m1mile1.609km3600s1hr=6.708×107mi/hr2.998 \times 10^8 \frac{m}{s} * \frac{1 \, km}{1 \times 10^3 \, m} * \frac{1 \, mile}{1.609 \, km} * \frac{3600 \, s}{1 \, hr} = 6.708 \times 10^7 \, mi/hr
2.998×108ms1km1×103m1mile1.609km1s24901mile=7.483loops2.998 \times 10^8 \frac{m}{s} * \frac{1 \, km}{1 \times 10^3 \, m} * \frac{1 \, mile}{1.609 \, km} * \frac{1 \, s}{24901 \, mile} = 7.483 \, loops

Temperature

  • Measure of average kinetic energy and therefore available energy.

  • Formulas:

    • °F=1.8(°C)+32°F = 1.8 * (°C) + 32

    • °C=0.55(°F32)°C = 0.55 * (°F – 32)

    • K=°C+273.15K = °C + 273.15

Example 4

  • The melting point of mercury is 235 K. What is this in degrees Celsius?

  • The surface temperature of the sun is 1×1041 \times 10^4 °F (compared to the core temperature of 2.7×1072.7 \times 10^7 °F). What is the surface temperature in Kelvin?

Unit 1 Review – What to Know

  • Natural Law versus Theory

  • How to classify matter based on its physical state or composition

  • Memorize the first four rows of the periodic table (name and symbol) along with Rb, Cs, Sr, Ba, Pd, Ag, Cd, Sn, I, Xe, Pt, Au, Hg, and Pb

  • Systematic versus Random error

  • Determination of significant digits

  • SI prefixes (base 10 conversions) listed on Memorization Sheet

  • How to solve problems using unit cancellation

  • Temperature units and their conversions

Domain and Methods of Science

  • A way of seeing and understanding.

    • Science provides a framework for observing, experimenting, and interpreting the world around us.

  • Requires an agreed-upon method.

    • The scientific method ensures consistency and reliability in scientific investigations.

  • Relies on observation.

    • Empirical evidence is crucial for supporting scientific claims.

  • Quantitative measurements are preferred (numerical).

    • Numerical data allows for precise analysis and comparison.

  • Involves moving from observation to understanding through a two-stage process.

    • This process includes forming hypotheses, testing them, and refining theories based on evidence.

Stage 1: Discovery Cycle
  • Experiment: An action or process carried out to test a hypothesis or theory.

    • Experiments involve manipulating variables and observing outcomes to draw conclusions.

  • Natural Law: A statement of what occurs without exception.

    • Natural laws describe consistent patterns observed in nature.

  • Theory: A logical model explaining why things occur.

    • Theories provide comprehensive explanations for observed phenomena.

    • Examples: Gravity, Conservation of Mass, Life begets Life.

    • Not static; testable by experiment.

      • Scientific theories are continuously tested and refined through experimentation.

    • Modified incrementally via the cycle of understanding.

      • Theories evolve as new evidence emerges and understanding deepens.

    • Examples include geocentric theory.

      • The geocentric theory was an early model of the universe that was later replaced by the heliocentric theory.

Stage 2: Understanding Cycle
  • Prediction: an expected outcome based on a theory. For example:

    • Predictions are derived from theories and tested through experimentation.

    • Theory 1: Less massive gases than nitrogen rise in air because their gravitational attraction is less.

      • This theory suggests that buoyancy is related to the gravitational attraction of gases.

      • Prediction: Hydrogen should rise, Helium should not.

      • Testing this prediction helps validate or refine the theory.

    • Theory 2: Gases that form stable compounds with oxygen burn.

      • This theory connects the reactivity of gases with their ability to form stable compounds.

      • Prediction: Helium should not burn, Argon should not burn.

      • Observing whether these gases burn provides evidence for or against the theory.

  • Experiment: Testing predictions, leading to modification of theories.

    • Experiments provide empirical data that either supports or contradicts theoretical predictions.

Chemistry

  • Definition: The branch of science that deals with the identification of the substances of which matter is composed; the investigation of their properties and the ways in which they interact, combine, and change; and the use of these processes to form new substances.

    • Chemistry is concerned with understanding the composition, structure, properties, and reactions of matter.

  • Study of matter, properties, composition, structure, interactions, and changes.

    • These aspects are fundamental to understanding chemical systems and processes.

  • Examples: Graphite and Diamond (different structures, same composition).

    • These allotropes illustrate how different arrangements of atoms can result in distinct properties.

Branches of Chemistry
  • Physical Chemistry: Studies the physics, matter, and energy of chemicals at an atomic and molecular level.

    • This branch applies principles of physics to understand chemical phenomena.

  • Analytical Chemistry: Utilizes different methods, instruments, and techniques to study and quantify different matter.

    • Analytical chemistry focuses on measuring and characterizing chemical substances.

  • Biochemistry: Studies chemical reactions and processes in living things.

    • Biochemistry explores the chemical basis of life processes.

  • Organic Chemistry: Studies the structure, synthesis, and properties of organic compounds (containing carbon).

    • Organic chemistry is concerned with compounds containing carbon, which are essential to life.

  • Inorganic Chemistry: Studies the structure, synthesis, and properties of inorganic compounds (containing metals).

    • Inorganic chemistry focuses on compounds that do not primarily contain carbon.

  • Theoretical Chemistry: Studies key chemistry concepts and the theories behind them.

    • Theoretical chemistry uses mathematical models to understand and predict chemical behavior.

  • Materials Chemistry: Studies and creates different materials for a specific function.

    • Materials chemistry designs and synthesizes new materials with specific properties.

Matter Classification

What is Matter?
  • Anything that has mass and occupies space.

    • Matter is the substance that makes up the physical universe.

Physical States
  • Solid: Fixed shape, fixed volume.

    • Solids maintain their shape and volume.

  • Liquid: No fixed shape, fixed volume.

    • Liquids take the shape of their container but maintain a constant volume.

  • Gas: No fixed shape, no fixed volume.

    • Gases expand to fill the available space.

Fundamental Composition
  • Elements: Composed of atoms; cannot be broken down into smaller pieces.

    • Elements are the simplest form of matter and cannot be decomposed by chemical means.

    • Need to know the first four rows of the periodic table along with Rb, Cs, Sr, Ba, Pd, Ag, Cd, Sn, I, Xe, Pt, Au, Hg, and Pb.

    • Familiarity with these elements is essential for understanding chemical reactions and compounds.

  • Compounds: Composed of more than one atom in fixed proportions.

    • Compounds are formed when atoms of different elements combine chemically.

  • Mixtures: Can be separated into elements, compounds, or both.

    • Mixtures are combinations of substances that are not chemically bonded.

    • Homogeneous: Uniform.

    • Homogeneous mixtures have a consistent composition throughout.

    • Heterogeneous: Non-uniform.

    • Heterogeneous mixtures have varying composition in different regions.

Example 1
  • Classify the following:

    1. Sweet Tea: Homogeneous mixture

    • Sweet tea has a uniform composition throughout.

    1. Copper: Element

    • Copper is a pure substance that cannot be broken down further.

    1. Blood: Heterogeneous mixture

    • Blood contains various components, such as cells and plasma, that are not uniformly distributed.

    1. Glucose: Compound

    • Glucose is a molecule composed of carbon, hydrogen, and oxygen atoms in a fixed ratio.

    1. Diamond: Element

    • Diamond is a pure form of carbon.

Calculations

  • Error in measurements must always be considered.

    • No measurement is perfect, and errors can affect the accuracy and precision of results.

  • Error can be in accuracy (agreement with true value) or in precision (agreement of the values with each other).

    • Accurate measurements are close to the true value, while precise measurements are reproducible.

Types of Error
  • Determinate (Systematic): Associated with poor accuracy; values are off in one direction.

    • Systematic errors can be identified and corrected.

  • Indeterminate (Random): Associated with poor precision; values are high and low.

    • Random errors are unpredictable and can be minimized by taking multiple measurements.

Significant Figures

  • All non-zero digits are significant (1, 2, 3, …, 9).

    • Non-zero digits always contribute to the precision of a measurement.

  • All captive zeros are significant (105, 3507, 14025).

    • Captive zeros are between non-zero digits.

  • Leading zeros are not significant (0.0035, 0.0589, 0.0701).

    • Leading zeros only indicate the position of the decimal point.

  • Trailing zeros before a decimal point are significant if specified in the problem (350.24, 3500., 3500).

    • Trailing zeros can indicate the precision of the measurement if explicitly stated.

  • Trailing zeros after a decimal point are significant (35.0, 37.230, 97.000).

    • Trailing zeros after the decimal point indicate the precision of the measurement.

  • Conversion factors have infinite significant figures and are ignored.

    • Conversion factors are exact and do not limit the number of significant figures in a calculation.

Example 2
  • How many significant figures?

    • A. 2730.78 m: 6

    • All digits are significant.

    • B. 0.0076 mL: 2

    • Only the 7 and 6 are significant.

    • C. 3400 kg: 2

    • Only the 3 and 4 are significant.

    • D. 3400.0 m2^2: 5

    • All digits, including the trailing zeros after the decimal point, are significant.

Math with Significant Digits

Multiplication/Division
  • Limited by the number of significant digits.

    • The result should have the same number of significant digits as the factor with the fewest significant digits.

  • Example: 278mm11.70g=23.8mm/g\frac{278 \, mm}{11.70 \, g} = 23.8 \, mm/g

    • 278 has 3 significant digits, and 11.70 has 4 significant digits, so the answer is rounded to 3 significant digits.

Addition/Subtraction
  • Limited by the number of decimal places.

    • The result should have the same number of decimal places as the number with the fewest decimal places.

  • Example: 3.18L+0.01315L=3.19L3.18 \, L + 0.01315 \, L = 3.19 \, L

    • 3.18 has 2 decimal places, and 0.01315 has 5 decimal places, so the answer is rounded to 2 decimal places.

3 significant figures / 3 significant figures --> 3 significant figures

2 decimal places / 5 decimal places --> 2 decimal places

  • Example:
    (57.890cc+73.2cc)/0.37cc=131.09cc/0.37cc=354.297cc=350cc(57.890 \, cc + 73.2 \, cc) / 0.37 \, cc = 131.09 \, cc / 0.37 \, cc = 354.297 \, cc = 350 \, cc

    • First, add 57.890 and 73.2, which gives 131.09. Since 73.2 has only one decimal place, round 131.09 to 131.1.

    • Then, divide 131.1 by 0.37, which gives 354.324. Since 0.37 has two significant figures, round 354.324 to 350.

3 decimal places + 1 decimal place --> Keep 1 decimal place

4 significant digits / 2 significant digits -->Round to 2 significant digits

Example 3
  • Solve and round to the correct number of significant digits:

    3.4781.1642.00+0.35415.41514.515+3.465+0.0402597\frac{3.478 * 1.164}{2.00} + \frac{0.354}{15.415 - 14.515} + 3.465 + 0.0402597

Units of Measurement

International System of Units (SI)
SI Base Units

Base Quantity

Name

Symbol

Length

meter

m

Mass

kilogram

kg

Time

second

s

Electric current

ampere

A

Thermodynamic temperature

kelvin

K

Amount of substance

mole

mol

Luminous intensity

candela

cd

SI Prefixes

Factor

Name

Symbol

Numerical Value

101210^{12}

tera

T

1,000,000,000,000

10910^9

giga

G

1,000,000,000

10610^6

mega

M

1,000,000

10310^3

kilo

k

1,000

10210^2

hecto

h

100

10110^1

deka

da

10

10110^{-1}

deci

d

0.1

10210^{-2}

centi

c

0.01

10310^{-3}

milli

m

0.001

10610^{-6}

micro

μ

0.000001

10910^{-9}

nano

n

0.000000001

101210^{-12}

pico

p

0.000000000001

SI Derived Units

Derived Quantity

Name

Symbol

SI Units

Frequency

hertz

Hz

s1s^{-1}

Force

newton

N

mkgs2m \cdot kg \cdot s^{-2}

Pressure

pascal

Pa

N/m2m^2

Energy

joule

J

NmN \cdot m

Power

watt

W

J/s

Electric charge

coulomb

C

sAs \cdot A

Electric potential

volt

V

W/A

Electric resistance

ohm

Ω

V/A

Celsius temperature

degree Celsius

°C

K

Example 1
  • 1 micrometer (µm) = 0.000001 (1×1061 \times 10^{-6}) meters (m) OR 1,000,000 (1×1061 \times 10^6) micrometers = 1 meter (m)

  • The average width of human hair is 53 µm. What is this measurement in meters?

    53µm1×106m1µm=5.3×105m53 \, µm * \frac{1 \times 10^{-6} m}{1 \, µm} = 5.3 \times 10^{-5} m

    53µm1m1×106µm=5.3×105m53 \, µm * \frac{1 \, m}{1 \times 10^{6} µm} = 5.3 \times 10^{-5} m

Unit Cancellation

  • Unit Cancellation helps to direct the calculation toward the correct answer with the correct units.

    • By tracking units through a calculation, you can ensure that the final answer has the correct units.

  • What is the speed of light in mi/hr and how many times does light circle the globe at the equator every second?

    • These problems illustrate how unit cancellation can be used to convert between different units.

  • Given Information: Equator = 24901 miles | Speed of light = 2.998×1082.998 \times 10^8 m/s | 1.609 km = 1 mile

2.998×108ms1km1×103m1mile1.609km3600s1hr=6.708×107mi/hr2.998 \times 10^8 \frac{m}{s} * \frac{1 \, km}{1 \times 10^3 \, m} * \frac{1 \, mile}{1.609 \, km} * \frac{3600 \, s}{1 \, hr} = 6.708 \times 10^7 \, mi/hr

2.998×108ms1km1×103m1mile1.609km1s24901mile=7.483loops2.998 \times 10^8 \frac{m}{s} * \frac{1 \, km}{1 \times 10^3 \, m} * \frac{1 \, mile}{1.609 \, km} * \frac{1 \, s}{24901 \, mile} = 7.483 \, loops

Temperature

  • Measure of average kinetic energy and therefore available energy.

    • Temperature is directly proportional to the average kinetic energy of the particles in a substance.

  • Formulas:

    • °F=1.8(°C)+32°F = 1.8 * (°C) + 32

    • This formula converts degrees Celsius to degrees Fahrenheit.

    • °C=0.55(°F32)°C = 0.55 * (°F – 32)

    • This formula converts degrees Fahrenheit to degrees Celsius.

    • K=°C+273.15K = °C + 273.15

    • This formula converts degrees Celsius to Kelvin.

Example 4
  • The melting point of mercury is 235 K. What is this in degrees Celsius?

    • Use the formula K=°C+273.15K = °C + 273.15 to find °C. Rearrange the formula to °C=K273.15°C = K - 273.15. Substitute 235 K to the new formula, °C=235273.15°C = 235 - 273.15. Therefore, the melting point is -38.15 °C.

  • The surface temperature of the sun is 1×1041 \times 10^4 °F (compared to the core temperature of 2.7×1072.7 \times 10^7 °F). What is the surface temperature in Kelvin?

    • Use the formula °F=1.8(°C)+32°F = 1.8 * (°C) + 32 to find °C. Rearrange the formula to °C=0.55(°F32)°C = 0.55 * (°F – 32). Substitute 1×1041 \times 10^4 °F to the new formula, °C=0.55(1×10432)°C = 0.55 * (1 \times 10^4 – 32). Therefore, the surface temperature is 5521.6 °C. Then use the formula K=°C+273.15K = °C + 273.15 to find K. Substitute 5521.6 °C to the formula, therefore, the surface temperature of the sun is 5794.8 K.

Unit 1 Review – What to Know

  • Natural Law versus Theory

    • Understand the difference between descriptive natural laws and explanatory theories.

  • How to classify matter based on its physical state or composition

    • Be able to identify matter as solid, liquid, or gas and as element, compound, or mixture.

  • Memorize the first four rows of the periodic table (name and symbol) along with Rb, Cs, Sr, Ba, Pd, Ag, Cd, Sn, I, Xe, Pt, Au, Hg, and Pb

    • Knowing these elements will help in understanding chemical formulas and reactions.

  • Systematic versus Random error

    • Know the causes and effects of each type of error.

  • Determination of significant digits

    • Be able to count significant digits in a measurement and apply the rules for calculations.

  • SI prefixes (base 10 conversions) listed on Memorization Sheet

    • Familiarize yourself with common prefixes like kilo-, centi-, and milli-.

  • How to solve problems using unit cancellation

    • Practice converting between different units using the factor-label method.

  • Temperature units and their conversions

    • Be able to convert between Celsius, Fahrenheit, and Kelvin.