Factoring Polynomials
Factoring Polynomials
Introduction
- Continuing work with factorization, focusing on polynomials.
- Factorization of polynomials is crucial for Math 107.
- Various methods of factorization will be explored thoroughly.
Objectives
- Easy Factorization:
- Identifying common factors in all terms of the polynomial.
- Finding the greatest common monomial factor.
- Monomial: One term (e.g., 3x2).
- Grouping Terms:
- Special factorization involving a factor (monomial, binomial, trinomial, etc.) common to all terms.
- Special Products:
- Applying special product formulas for factorization.
- Factoring Completely:
- Ensuring the polynomial is factored as much as possible.
Finding the Greatest Common Monomial Factor
- Example Polynomial: 3x5+6x3−9x
- Degree of polynomial: 5
- Terms are in descending order of power (5, 3, 1); powers 4 and 2, and the constant are missing.
- Leading coefficient: 3
- Factor out x because it's common to all terms.
- x5=x4∗x
- x3=x2∗x
- x=x∗1
Identifying Common Coefficients
- Coefficients are 3, 6, and -9.
- Factorize each coefficient:
- 3=3∗1
- 6=3∗2
- −9=3∗−3
- Common factor: 3
Determining the Monomial Factor
- Monomial factor: Product of common coefficient and common variable.
- In this case, 3x.
- General form of a monomial factor: a∗xn, where a is a real number.
- Because it's common, it is termed the greatest common monomial factor.
More Examples of Finding the Greatest Common Monomial Factor
- Example 1: 24x3−32x2
- Coefficients: 24 and -32
- Factorization: 24=8∗3, −32=8∗−4
- Common factor: 8
- Variables: x3 and x2
- Factorization: x3=x2∗x, x2=x2∗1
- Common factor: x2
- Greatest common monomial factor: 8x2
- Resulting factorization: 8x2(3x−4)
- Example 2: 24x5−21x3+6x2
- Coefficients: 24, -21, and 6
- Factorization: 24=3∗8, −21=3∗−7, 6=3∗2
- Common factor: 3
- Variables: x5, x3, and x2
- Factorization: x5=x2∗x3, x3=x2∗x, x2=x2∗1
- Common factor: x2
- Greatest common monomial factor: 3x2
- Resulting factorization: 3x2(8x3−7x+2)
Common Binomial Factors
- Consider expressions like 5x2(6x−5)−2(6x−5).
- (6x−5) is a common binomial factor.
- Factor out the common binomial: (6x−5)(5x2−2).
- This also applies to trinomial or polynomial factors.
- Check if the remaining expression can be factored further.
Example with Common Binomial Factors
- Problem: x2(x−3)+7(x−3)
- Common binomial factor: (x−3)
- Factorization: (x−3)(x2+7)
Factorization by Grouping
- Problem: x3−3x2+7x−21
- Degree of polynomial: 3
- Leading term: x3
- Constant term: -21
- Group terms: (x3−3x2)+(7x−21)
- Factor each group:
- x3−3x2=x2(x−3)
- 7x−21=7(x−3)
- Rewrite the expression: x2(x−3)+7(x−3)
- Factor out the common binomial factor: (x−3)(x2+7)
- Convenient grouping: Choosing terms to facilitate finding a monomial factor.
Special Factors: Difference of Two Squares
- Formula: u2−v2=(u+v)(u−v)
- Both terms must be perfect squares.
- Crucially, there must be a difference (subtraction) between the terms.
- Perfect squares: 1, 4, 9, 16, 25, 36, 49, 81, etc.
- Example: x2−4
- x2 is a perfect square.
- 4 is a perfect square (22).
- u=x, v=2
- Factorization: (x+2)(x−2)
More Complex Example of Difference of Two Squares
- Problem: 25x2−49y2
- 25 is a perfect square (52).
- 49 is a perfect square (72).
- x2 and y2 are perfect squares.
- u=5x, v=7y
- Factorization: (5x+7y)(5x−7y)
Note: a plus sign between the two perfect squares makes this factorization impossible!!
Further Examples
- 4y2−36x2=(2y+6x)(2y−6x)
- 81x2−4=(9x+2)(9x−2)
- Terms must be perfect squares, and there must be a difference.
Special Factors: Sum and Difference of Cubes
- Sum of Cubes: u3+v3=(u+v)(u2−uv+v2)
- Difference of Cubes: u3−v3=(u−v)(u2+uv+v2)
- Remembering perfect cubes is important.
- Perfect Cubes: 1, 8, 27, 64, 125, 216, etc.
Examples of Sum and Difference of Cubes
- Example 1: x3−64
- x3 is a perfect cube.
- 64 is a perfect cube (43).
- u=x, v=4
- Using the difference of cubes formula:
- (x−4)(x2+4x+16)
- Example 2: 8x3+125
- 8 is a perfect cube (23).
- 125 is a perfect cube (53).
- u=2x, v=5
- Using the sum of cubes formula:
- (2x+5)(4x2−10x+25)
Practice Problem
- Problem: y3−27x3
- u=y, v=3x
- Using the difference of cubes formula:
- (y−3x)(y2+3xy+9x2)
- Use alphabetic order for variables (e.g., xy instead of yx).
Summary
- Special Formulas:
- Difference of Squares: u2−v2=(u+v)(u−v)
- Sum of Cubes: u3+v3=(u+v)(u2−uv+v2)
- Difference of Cubes: u3−v3=(u−v)(u2+uv+v2)
- Factorization by grouping (common binomial factors).
- Common monomial factors.
- Tomorrow: Factorization of trinomials.