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Factoring Polynomials
Factoring Polynomials
Factoring Polynomials
Introduction
Continuing work with factorization, focusing on polynomials.
Factorization of polynomials is crucial for Math 107.
Various methods of factorization will be explored thoroughly.
Objectives
Easy Factorization:
Identifying common factors in all terms of the polynomial.
Finding the
greatest common monomial factor
.
Monomial: One term (e.g., 3x^2).
Grouping Terms:
Special factorization involving a factor (monomial, binomial, trinomial, etc.) common to all terms.
Special Products:
Applying special product formulas for factorization.
Factoring Completely:
Ensuring the polynomial is factored as much as possible.
Finding the Greatest Common Monomial Factor
Example Polynomial: 3x^5 + 6x^3 - 9x
Degree of polynomial: 5
Terms are in descending order of power (5, 3, 1); powers 4 and 2, and the constant are missing.
Leading coefficient: 3
Factor out x because it's common to all terms.
x^5 = x^4 * x
x^3 = x^2 * x
x = x * 1
Identifying Common Coefficients
Coefficients are 3, 6, and -9.
Factorize each coefficient:
3 = 3 * 1
6 = 3 * 2
-9 = 3 * -3
Common factor: 3
Determining the Monomial Factor
Monomial factor: Product of common coefficient and common variable.
In this case, 3x.
General form of a monomial factor: a * x^n, where a is a real number.
Because it's common, it is termed the
greatest common monomial factor
.
More Examples of Finding the Greatest Common Monomial Factor
Example 1: 24x^3 - 32x^2
Coefficients: 24 and -32
Factorization: 24 = 8 * 3, -32 = 8 * -4
Common factor: 8
Variables: x^3 and x^2
Factorization: x^3 = x^2 * x, x^2 = x^2 * 1
Common factor: x^2
Greatest common monomial factor: 8x^2
Resulting factorization: 8x^2(3x - 4)
Example 2: 24x^5 - 21x^3 + 6x^2
Coefficients: 24, -21, and 6
Factorization: 24 = 3 * 8, -21 = 3 * -7, 6 = 3 * 2
Common factor: 3
Variables: x^5, x^3, and x^2
Factorization: x^5 = x^2 * x^3, x^3 = x^2 * x, x^2 = x^2 * 1
Common factor: x^2
Greatest common monomial factor: 3x^2
Resulting factorization: 3x^2(8x^3 - 7x + 2)
Common Binomial Factors
Consider expressions like 5x^2(6x - 5) - 2(6x - 5).
(6x - 5) is a
common binomial factor
.
Factor out the common binomial: (6x - 5)(5x^2 - 2).
This also applies to trinomial or polynomial factors.
Check if the remaining expression can be factored further.
Example with Common Binomial Factors
Problem: x^2(x - 3) + 7(x - 3)
Common binomial factor: (x - 3)
Factorization: (x - 3)(x^2 + 7)
Factorization by Grouping
Problem: x^3 - 3x^2 + 7x - 21
Degree of polynomial: 3
Leading term: x^3
Constant term: -21
Group terms: (x^3 - 3x^2) + (7x - 21)
Factor each group:
x^3 - 3x^2 = x^2(x - 3)
7x - 21 = 7(x - 3)
Rewrite the expression: x^2(x - 3) + 7(x - 3)
Factor out the common binomial factor: (x - 3)(x^2 + 7)
Convenient grouping
: Choosing terms to facilitate finding a monomial factor.
Special Factors: Difference of Two Squares
Formula: u^2 - v^2 = (u + v)(u - v)
Both terms must be perfect squares.
Crucially, there must be a difference (subtraction) between the terms.
Perfect squares: 1, 4, 9, 16, 25, 36, 49, 81, etc.
Example: x^2 - 4
x^2 is a perfect square.
4 is a perfect square (2^2).
u = x, v = 2
Factorization: (x + 2)(x - 2)
More Complex Example of Difference of Two Squares
Problem: 25x^2 - 49y^2
25 is a perfect square (5^2).
49 is a perfect square (7^2).
x^2 and y^2 are perfect squares.
u = 5x, v = 7y
Factorization: (5x + 7y)(5x - 7y)
Note: a plus sign between the two perfect squares makes this factorization impossible!!
Further Examples
4y^2 - 36x^2 = (2y + 6x)(2y - 6x)
81x^2 - 4 = (9x + 2)(9x - 2)
Terms must be perfect squares, and there must be a difference.
Special Factors: Sum and Difference of Cubes
Sum of Cubes: u^3 + v^3 = (u + v)(u^2 - uv + v^2)
Difference of Cubes: u^3 - v^3 = (u - v)(u^2 + uv + v^2)
Remembering perfect cubes is important.
Perfect Cubes: 1, 8, 27, 64, 125, 216, etc.
Examples of Sum and Difference of Cubes
Example 1: x^3 - 64
x^3 is a perfect cube.
64 is a perfect cube (4^3).
u = x, v = 4
Using the difference of cubes formula:
(x - 4)(x^2 + 4x + 16)
Example 2: 8x^3 + 125
8 is a perfect cube (2^3).
125 is a perfect cube (5^3).
u = 2x, v = 5
Using the sum of cubes formula:
(2x + 5)(4x^2 - 10x + 25)
Practice Problem
Problem: y^3 - 27x^3
u = y, v = 3x
Using the difference of cubes formula:
(y - 3x)(y^2 + 3xy + 9x^2)
Use alphabetic order for variables (e.g., xy instead of yx).
Summary
Special Formulas:
Difference of Squares: u^2 - v^2 = (u + v)(u - v)
Sum of Cubes: u^3 + v^3 = (u + v)(u^2 - uv + v^2)
Difference of Cubes: u^3 - v^3 = (u - v)(u^2 + uv + v^2)
Factorization by grouping (common binomial factors).
Common monomial factors.
Tomorrow: Factorization of trinomials.
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Explore Top Notes
1: Pharmacology Overview
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Chapter 3 - Describing, Exploring, and Comparing Data
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Studied by 12 people
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Studied by 31 people
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Math 1: General Strategies and Basic Equations
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Studied by 1624 people
5.0
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