Cartesian System of Rectangular Coordinates Two mutually perpendicular axes X O X ′ XOX' X O X ′ (x–axis) & Y O Y ′ YOY' Y O Y ′ (y–axis) meet at the origin O ( 0 , 0 ) O(0,0) O ( 0 , 0 ) .
Coordinates of a point P ( x , y ) P(x,y) P ( x , y ) : • Abscissa = x x x (distance from y y y –axis) • Ordinate = y y y (distance from x x x –axis)
Quadrant sign convention: • I (x>0,y>0) • II (x<0,y>0) • III (x<0,y<0) • IV (x>0,y<0)
Distance & Its Applications Distance between P ( x < e m > 1 , y < / e m > 1 ) P(x<em>1,y</em>1) P ( x < e m > 1 , y < / e m > 1 ) & Q ( x < e m > 2 , y < / e m > 2 ) Q(x<em>2,y</em>2) Q ( x < e m > 2 , y < / e m > 2 ) P Q = ( x < e m > 2 − x < / e m > 1 ) 2 + ( y < e m > 2 − y < / e m > 1 ) 2 PQ = \sqrt{(x<em>2-x</em>1)^2+(y<em>2-y</em>1)^2} P Q = ( x < e m > 2 − x < / e m > 1 ) 2 + ( y < e m > 2 − y < / e m > 1 ) 2
Distance from origin: O P = x 2 + y 2 OP = \sqrt{x^2+y^2} O P = x 2 + y 2 .
Pythagorean tests: • Right–triangle: P Q 2 + Q R 2 = P R 2 PQ^2+QR^2=PR^2 P Q 2 + Q R 2 = P R 2 • Collinear points: Sum of two smaller distances equals the third.
Section Formulae Internal division of P Q PQ P Q in ratio m < e m > 1 : m < / e m > 2 m<em>1:m</em>2 m < e m > 1 : m < / e m > 2 by R ( x , y ) R(x,y) R ( x , y ) : x = m < e m > 1 x < / e m > 2 + m < e m > 2 x < / e m > 1 m < e m > 1 + m < / e m > 2 , y = m < e m > 1 y < / e m > 2 + m < e m > 2 y < / e m > 1 m < e m > 1 + m < / e m > 2 x = \dfrac{m<em>1x</em>2+m<em>2x</em>1}{m<em>1+m</em>2},\; y = \dfrac{m<em>1y</em>2+m<em>2y</em>1}{m<em>1+m</em>2} x = m < e m > 1 + m < / e m > 2 m < e m > 1 x < / e m > 2 + m < e m > 2 x < / e m > 1 , y = m < e m > 1 + m < / e m > 2 m < e m > 1 y < / e m > 2 + m < e m > 2 y < / e m > 1
Mid-point ( m < e m > 1 = m < / e m > 2 ) (m<em>1=m</em>2) ( m < e m > 1 = m < / e m > 2 ) : ( x < e m > 1 + x < / e m > 2 2 , y < e m > 1 + y < / e m > 2 2 ) \bigl(\dfrac{x<em>1+x</em>2}{2},\dfrac{y<em>1+y</em>2}{2}\bigr) ( 2 x < e m > 1 + x < / e m > 2 , 2 y < e m > 1 + y < / e m > 2 )
External division (same ratio): x = m < e m > 1 x < / e m > 2 − m < e m > 2 x < / e m > 1 m < e m > 1 − m < / e m > 2 , y = m < e m > 1 y < / e m > 2 − m < e m > 2 y < / e m > 1 m < e m > 1 − m < / e m > 2 x = \dfrac{m<em>1x</em>2-m<em>2x</em>1}{m<em>1-m</em>2},\; y = \dfrac{m<em>1y</em>2-m<em>2y</em>1}{m<em>1-m</em>2} x = m < e m > 1 − m < / e m > 2 m < e m > 1 x < / e m > 2 − m < e m > 2 x < / e m > 1 , y = m < e m > 1 − m < / e m > 2 m < e m > 1 y < / e m > 2 − m < e m > 2 y < / e m > 1
Area & Collinearity Area of △ A B C \triangle ABC △ A B C with vertices A ( x < e m > 1 , y < / e m > 1 ) , B ( x < e m > 2 , y < / e m > 2 ) , C ( x < e m > 3 , y < / e m > 3 ) A(x<em>1,y</em>1),B(x<em>2,y</em>2),C(x<em>3,y</em>3) A ( x < e m > 1 , y < / e m > 1 ) , B ( x < e m > 2 , y < / e m > 2 ) , C ( x < e m > 3 , y < / e m > 3 ) : Area = 1 2 ∣ x < e m > 1 ( y < / e m > 2 − y < e m > 3 ) + x < / e m > 2 ( y < e m > 3 − y < / e m > 1 ) + x < e m > 3 ( y < / e m > 1 − y 2 ) ∣ \text{Area}=\dfrac12\left|x<em>1(y</em>2-y<em>3)+x</em>2(y<em>3-y</em>1)+x<em>3(y</em>1-y_2)\right| Area = 2 1 ∣ x < e m > 1 ( y < / e m > 2 − y < e m > 3 ) + x < / e m > 2 ( y < e m > 3 − y < / e m > 1 ) + x < e m > 3 ( y < / e m > 1 − y 2 ) ∣
Points collinear ⇔ \Leftrightarrow ⇔ area $=0$ ⇒ \Rightarrow ⇒ determinant condition \begin{vmatrix}x1&y 1&1\x2&y 2&1\x3&y 3&1\end{vmatrix}=0
Inclination & Slope of a Line Inclination θ \theta θ : angle w.r.t. positive x-axis (anticlockwise).
Slope m = tan θ m=\tan\theta m = tan θ (undefined for vertical lines).
Slope of line through P < e m > 1 ( x < / e m > 1 , y < e m > 1 ) , P < / e m > 2 ( x < e m > 2 , y < / e m > 2 ) P<em>1(x</em>1,y<em>1),P</em>2(x<em>2,y</em>2) P < e m > 1 ( x < / e m > 1 , y < e m > 1 ) , P < / e m > 2 ( x < e m > 2 , y < / e m > 2 ) : m = y < e m > 2 − y < / e m > 1 x < e m > 2 − x < / e m > 1 m=\dfrac{y<em>2-y</em>1}{x<em>2-x</em>1} m = x < e m > 2 − x < / e m > 1 y < e m > 2 − y < / e m > 1 (vertical ⇒ x < e m > 1 = x < / e m > 2 \Rightarrow x<em>1=x</em>2 ⇒ x < e m > 1 = x < / e m > 2 ).
Special results: • Parallel lines m < e m > 1 = m < / e m > 2 m<em>1=m</em>2 m < e m > 1 = m < / e m > 2 • Perpendicular lines m < e m > 1 m < / e m > 2 = − 1 m<em>1m</em>2=-1 m < e m > 1 m < / e m > 2 = − 1 • Angle between two lines tan ϕ = ∣ m < e m > 1 − m < / e m > 2 ∣ 1 + m < e m > 1 m < / e m > 2 \tan\phi = \dfrac{|m<em>1-m</em>2|}{1+m<em>1m</em>2} tan ϕ = 1 + m < e m > 1 m < / e m > 2 ∣ m < e m > 1 − m < / e m > 2∣
Straight–Line Equations 1. Slope–Intercept y = m x + c y=mx+c y = m x + c (slope m m m , y-intercept c c c ).
2. Point–Slope Through P ( x < e m > 1 , y < / e m > 1 ) P(x<em>1,y</em>1) P ( x < e m > 1 , y < / e m > 1 ) : y − y < e m > 1 = m ( x − x < / e m > 1 ) y-y<em>1=m(x-x</em>1) y − y < e m > 1 = m ( x − x < / e m > 1 ) .
3. Two-Point Through P < e m > 1 , P < / e m > 2 P<em>1,P</em>2 P < e m > 1 , P < / e m > 2 : y − y < e m > 1 y < / e m > 2 − y < e m > 1 = x − x < / e m > 1 x < e m > 2 − x < / e m > 1 \dfrac{y-y<em>1}{y</em>2-y<em>1}=\dfrac{x-x</em>1}{x<em>2-x</em>1} y < / e m > 2 − y < e m > 1 y − y < e m > 1 = x < e m > 2 − x < / e m > 1 x − x < / e m > 1 .
4. Intercept Form x a + y b = 1 \frac{x}{a}+\frac{y}{b}=1 a x + b y = 1 (cuts axes at a , b a, b a , b ).
5. Normal (Perpendicular) Form x cos α + y sin α = p x\cos\alpha + y\sin\alpha = p x cos α + y sin α = p $p$ = perpendicular from origin, $\alpha$ its inclination.
6. General First-Degree A x + B y + C = 0 Ax+By+C=0 A x + B y + C = 0 represents a line if A , B A,B A , B not both zero. • Slope = − A B = -\dfrac AB = − B A , x-intercept = − C A = -\dfrac CA = − A C , y-intercept = − C B = -\dfrac CB = − B C .
Distance of Point from Line For point P ( x < e m > 1 , y < / e m > 1 ) P(x<em>1,y</em>1) P ( x < e m > 1 , y < / e m > 1 ) & line A x + B y + C = 0 Ax+By+C=0 A x + B y + C = 0 : d = ∣ A x < e m > 1 + B y < / e m > 1 + C ∣ A 2 + B 2 d = \dfrac{|Ax<em>1+By</em>1+C|}{\sqrt{A^2+B^2}} d = A 2 + B 2 ∣ A x < e m > 1 + B y < / e m > 1 + C ∣
Shift of Origin (Translation of Axes) New origin O ′ ( h , k ) O'(h,k) O ′ ( h , k ) : x = x ′ + h , y = y ′ + k x=x'+h,\; y=y'+k x = x ′ + h , y = y ′ + k .
Any curve F ( x , y ) = 0 F(x,y)=0 F ( x , y ) = 0 transforms to F ( x ′ + h , y ′ + k ) = 0 F(x'+h,y'+k)=0 F ( x ′ + h , y ′ + k ) = 0 .
Families of Lines Lines through intersection of l < e m > 1 = 0 l<em>1=0 l < e m > 1 = 0 & l < / e m > 2 = 0 l</em>2=0 l < / e m > 2 = 0 : l < e m > 1 + λ l < / e m > 2 = 0 l<em>1+\lambda l</em>2=0 l < e m > 1 + λ l < / e m > 2 = 0 .
Parallel to given line A x + B y + C = 0 Ax+By+C=0 A x + B y + C = 0 : A x + B y + K = 0 Ax+By+K=0 A x + B y + K = 0 .
Perpendicular to it: B x − A y + K = 0 Bx-Ay+K=0 B x − A y + K = 0 .
Circles Standard form (centre h , k h,k h , k radius r r r ): ( x − h ) 2 + ( y − k ) 2 = r 2 (x-h)^2+(y-k)^2 = r^2 ( x − h ) 2 + ( y − k ) 2 = r 2 .
General second-degree with equal x 2 , y 2 x^2,y^2 x 2 , y 2 coefficients & no x y xy x y term: x 2 + y 2 + 2 g x + 2 f y + c = 0 x^2+y^2+2gx+2fy+c=0 x 2 + y 2 + 2 g x + 2 f y + c = 0 • Centre ( − g , − f ) (-g,-f) ( − g , − f ) , radius g 2 + f 2 − c \sqrt{g^2+f^2-c} g 2 + f 2 − c .
Special positions: • Touches x-axis ⇒ k = r \Rightarrow k=r ⇒ k = r • Touches y-axis ⇒ h = r \Rightarrow h=r ⇒ h = r • Touches both ⇒ h = k = r \Rightarrow h=k=r ⇒ h = k = r .
Conic Sections (Eccentricity Definition) Given focus S S S , directrix l l l , eccentricity e e e .
Ellipse (Standard) \frac{x^2}{a^2}+\frac{y^2}{b^2}=1\;(a>b>0)
c 2 = a 2 − b 2 , e = c a c^2=a^2-b^2,\; e=\dfrac ca c 2 = a 2 − b 2 , e = a c .
Foci ( ± c , 0 ) = ( ± a e , 0 ) (\pm c,0)=(\pm ae,0) ( ± c , 0 ) = ( ± a e , 0 ) .
Directrices x = ± a e x=\pm\dfrac a e x = ± e a .
Major axis 2 a 2a 2 a , minor axis 2 b 2b 2 b .
Length of latus rectum = 2 b 2 a =\dfrac{2b^2}{a} = a 2 b 2 . (Interchange a , b a,b a , b for vertical major axis.)
Parabola (Standard) y 2 = 4 a x y^2=4ax y 2 = 4 a x
Vertex ( 0 , 0 ) (0,0) ( 0 , 0 ) , focus ( a , 0 ) (a,0) ( a , 0 ) , directrix x = − a x=-a x = − a .
Axis along x-axis; latus rectum 4 a 4a 4 a . Other orientations: replace y 2 y^2 y 2 by x 2 x^2 x 2 and/or change signs.
Hyperbola (Standard) \frac{x^2}{a^2}-\frac{y^2}{b^2}=1\;(a,b>0)
c^2=a^2+b^2,\; e=\dfrac ca>1.
Foci ( ± c , 0 ) = ( ± a e , 0 ) (\pm c,0)=(\pm ae,0) ( ± c , 0 ) = ( ± a e , 0 ) .
Directrices x = ± a e x=\pm\dfrac a e x = ± e a .
Transverse axis 2 a 2a 2 a , conjugate axis 2 b 2b 2 b .
Latus rectum = 2 b 2 a =\dfrac{2b^2}{a} = a 2 b 2 . Conjugate hyperbola: y 2 b 2 − x 2 a 2 = 1 \dfrac{y^2}{b^2}-\dfrac{x^2}{a^2}=1 b 2 y 2 − a 2 x 2 = 1 . Rectangular hyperbola: a = b ⇒ e = 2 a=b\Rightarrow e=\sqrt2 a = b ⇒ e = 2 .
Key Problem-Solving Steps Identify type via e e e or general equation criteria.
Normalize coefficients to match standard forms.
Extract parameters a , b , c , e a,b,c,e a , b , c , e , then derive foci, axes lengths, directrices, latus rectum.
For locus problems use definition (distance to focus) (distance to directrix) = e \dfrac{\text{(distance to focus)}}{\text{(distance to directrix)}}=e (distance to directrix) (distance to focus) = e .
End of Module IV Revision Notes – Coordinate Geometry (Straight Lines & Conics)