Coordinate Geometry – Quick Revision Notes

Cartesian System of Rectangular Coordinates

  • Two mutually perpendicular axes XOXXOX' (x–axis) & YOYYOY' (y–axis) meet at the origin O(0,0)O(0,0).

  • Coordinates of a point P(x,y)P(x,y):
    • Abscissa = xx (distance from yy–axis)
    • Ordinate = yy (distance from xx–axis)

  • Quadrant sign convention:
    • I (x>0,y>0) • II (x<0,y>0) • III (x<0,y<0) • IV (x>0,y<0)

Distance & Its Applications

  • Distance between P(x<em>1,y</em>1)P(x<em>1,y</em>1) & Q(x<em>2,y</em>2)Q(x<em>2,y</em>2)
    PQ=(x<em>2x</em>1)2+(y<em>2y</em>1)2PQ = \sqrt{(x<em>2-x</em>1)^2+(y<em>2-y</em>1)^2}

  • Distance from origin: OP=x2+y2OP = \sqrt{x^2+y^2}.

  • Pythagorean tests:
    • Right–triangle: PQ2+QR2=PR2PQ^2+QR^2=PR^2
    • Collinear points: Sum of two smaller distances equals the third.

Section Formulae

  • Internal division of PQPQ in ratio m<em>1:m</em>2m<em>1:m</em>2 by R(x,y)R(x,y):
    x=m<em>1x</em>2+m<em>2x</em>1m<em>1+m</em>2,  y=m<em>1y</em>2+m<em>2y</em>1m<em>1+m</em>2x = \dfrac{m<em>1x</em>2+m<em>2x</em>1}{m<em>1+m</em>2},\; y = \dfrac{m<em>1y</em>2+m<em>2y</em>1}{m<em>1+m</em>2}

  • Mid-point (m<em>1=m</em>2)(m<em>1=m</em>2): (x<em>1+x</em>22,y<em>1+y</em>22)\bigl(\dfrac{x<em>1+x</em>2}{2},\dfrac{y<em>1+y</em>2}{2}\bigr)

  • External division (same ratio):
    x=m<em>1x</em>2m<em>2x</em>1m<em>1m</em>2,  y=m<em>1y</em>2m<em>2y</em>1m<em>1m</em>2x = \dfrac{m<em>1x</em>2-m<em>2x</em>1}{m<em>1-m</em>2},\; y = \dfrac{m<em>1y</em>2-m<em>2y</em>1}{m<em>1-m</em>2}

Area & Collinearity

  • Area of ABC\triangle ABC with vertices A(x<em>1,y</em>1),B(x<em>2,y</em>2),C(x<em>3,y</em>3)A(x<em>1,y</em>1),B(x<em>2,y</em>2),C(x<em>3,y</em>3):
    Area=12x<em>1(y</em>2y<em>3)+x</em>2(y<em>3y</em>1)+x<em>3(y</em>1y2)\text{Area}=\dfrac12\left|x<em>1(y</em>2-y<em>3)+x</em>2(y<em>3-y</em>1)+x<em>3(y</em>1-y_2)\right|

  • Points collinear \Leftrightarrow area $=0$ \Rightarrow determinant condition
    \begin{vmatrix}x1&y1&1\x2&y2&1\x3&y3&1\end{vmatrix}=0

Inclination & Slope of a Line

  • Inclination θ\theta: angle w.r.t. positive x-axis (anticlockwise).

  • Slope m=tanθm=\tan\theta (undefined for vertical lines).

  • Slope of line through P<em>1(x</em>1,y<em>1),P</em>2(x<em>2,y</em>2)P<em>1(x</em>1,y<em>1),P</em>2(x<em>2,y</em>2):
    m=y<em>2y</em>1x<em>2x</em>1m=\dfrac{y<em>2-y</em>1}{x<em>2-x</em>1} (vertical x<em>1=x</em>2\Rightarrow x<em>1=x</em>2).

  • Special results:
    • Parallel lines m<em>1=m</em>2m<em>1=m</em>2
    • Perpendicular lines m<em>1m</em>2=1m<em>1m</em>2=-1
    • Angle between two lines tanϕ=m<em>1m</em>21+m<em>1m</em>2\tan\phi = \dfrac{|m<em>1-m</em>2|}{1+m<em>1m</em>2}

Straight–Line Equations

1. Slope–Intercept

y=mx+cy=mx+c (slope mm, y-intercept cc).

2. Point–Slope

Through P(x<em>1,y</em>1)P(x<em>1,y</em>1): yy<em>1=m(xx</em>1)y-y<em>1=m(x-x</em>1).

3. Two-Point

Through P<em>1,P</em>2P<em>1,P</em>2: yy<em>1y</em>2y<em>1=xx</em>1x<em>2x</em>1\dfrac{y-y<em>1}{y</em>2-y<em>1}=\dfrac{x-x</em>1}{x<em>2-x</em>1}.

4. Intercept Form

xa+yb=1\frac{x}{a}+\frac{y}{b}=1 (cuts axes at a,ba, b).

5. Normal (Perpendicular) Form

xcosα+ysinα=px\cos\alpha + y\sin\alpha = p
$p$ = perpendicular from origin, $\alpha$ its inclination.

6. General First-Degree

Ax+By+C=0Ax+By+C=0 represents a line if A,BA,B not both zero.
• Slope =AB= -\dfrac AB, x-intercept =CA= -\dfrac CA, y-intercept =CB= -\dfrac CB.

Distance of Point from Line

For point P(x<em>1,y</em>1)P(x<em>1,y</em>1) & line Ax+By+C=0Ax+By+C=0:
d=Ax<em>1+By</em>1+CA2+B2d = \dfrac{|Ax<em>1+By</em>1+C|}{\sqrt{A^2+B^2}}

Shift of Origin (Translation of Axes)

  • New origin O(h,k)O'(h,k): x=x+h,  y=y+kx=x'+h,\; y=y'+k.

  • Any curve F(x,y)=0F(x,y)=0 transforms to F(x+h,y+k)=0F(x'+h,y'+k)=0.

Families of Lines

  • Lines through intersection of l<em>1=0l<em>1=0 & l</em>2=0l</em>2=0: l<em>1+λl</em>2=0l<em>1+\lambda l</em>2=0.

  • Parallel to given line Ax+By+C=0Ax+By+C=0: Ax+By+K=0Ax+By+K=0.

  • Perpendicular to it: BxAy+K=0Bx-Ay+K=0.

Circles

  • Standard form (centre h,kh,k radius rr): (xh)2+(yk)2=r2(x-h)^2+(y-k)^2 = r^2.

  • General second-degree with equal x2,y2x^2,y^2 coefficients & no xyxy term:
    x2+y2+2gx+2fy+c=0x^2+y^2+2gx+2fy+c=0
    • Centre (g,f)(-g,-f), radius g2+f2c\sqrt{g^2+f^2-c}.

  • Special positions:
    • Touches x-axis k=r\Rightarrow k=r • Touches y-axis h=r\Rightarrow h=r • Touches both h=k=r\Rightarrow h=k=r.

Conic Sections (Eccentricity Definition)

Given focus SS, directrix ll, eccentricity ee.

  • Circle e=0e=0 (special ellipse).

  • Ellipse 0<e<1.

  • Parabola e=1e=1.

  • Hyperbola e>1.


Ellipse (Standard)

\frac{x^2}{a^2}+\frac{y^2}{b^2}=1\;(a>b>0)

  • c2=a2b2,  e=cac^2=a^2-b^2,\; e=\dfrac ca.

  • Foci (±c,0)=(±ae,0)(\pm c,0)=(\pm ae,0).

  • Directrices x=±aex=\pm\dfrac a e.

  • Major axis 2a2a, minor axis 2b2b.

  • Length of latus rectum =2b2a=\dfrac{2b^2}{a}.
    (Interchange a,ba,b for vertical major axis.)

Parabola (Standard)

y2=4axy^2=4ax

  • Vertex (0,0)(0,0), focus (a,0)(a,0), directrix x=ax=-a.

  • Axis along x-axis; latus rectum 4a4a.
    Other orientations: replace y2y^2 by x2x^2 and/or change signs.

Hyperbola (Standard)

\frac{x^2}{a^2}-\frac{y^2}{b^2}=1\;(a,b>0)

  • c^2=a^2+b^2,\; e=\dfrac ca>1.

  • Foci (±c,0)=(±ae,0)(\pm c,0)=(\pm ae,0).

  • Directrices x=±aex=\pm\dfrac a e.

  • Transverse axis 2a2a, conjugate axis 2b2b.

  • Latus rectum =2b2a=\dfrac{2b^2}{a}.
    Conjugate hyperbola: y2b2x2a2=1\dfrac{y^2}{b^2}-\dfrac{x^2}{a^2}=1.
    Rectangular hyperbola: a=be=2a=b\Rightarrow e=\sqrt2.

Key Problem-Solving Steps

  1. Identify type via ee or general equation criteria.

  2. Normalize coefficients to match standard forms.

  3. Extract parameters a,b,c,ea,b,c,e, then derive foci, axes lengths, directrices, latus rectum.

  4. For locus problems use definition (distance to focus)(distance to directrix)=e\dfrac{\text{(distance to focus)}}{\text{(distance to directrix)}}=e.


End of Module IV Revision Notes – Coordinate Geometry (Straight Lines & Conics)