Polar Integrals

Understanding the Region for Integration

  • Given: If x2=2x^2 = 2

    • Therefore, x=extroot2x = ext{root } 2

  • Consider the interval:

    • Left endpoint: 00

    • Right endpoint: extroot2ext{root } 2

  • Pick a favorite xx value between 00 and extroot2ext{root } 2 for integration.

Defining the Integration Limits

  • Integration starts at the curve defined by:

    • Lower curve: y=x2y = x^2

    • Upper curve: y=2y = 2

  • The differential dxdx accumulates vertical slices between these curves.

Double Integral Interpretation

  • The expression integrated is xy2x y^2

  • One interpretation: This double integral represents the volume beneath the graph above the indicated region in the domain.

Integrating Functions

  • A review of integrating vertical slices:

    • Integrate with respect to yy while treating xx as constant.

    • The anti-derivative of yy is computed:

    • Integral of yy: racy33rac{y^3}{3}

    • Evaluate from y=2y = 2 to y=x2y = x^2:

    • Results in: rac(2)33rac(x2)33=rac83racx63rac{(2)^3}{3} - rac{(x^2)^3}{3} = rac{8}{3} - rac{x^6}{3}

Function Volume Interpretation

  • Recall the graph of the flat plane z=1z = 1

    • This plane is 1 unit directly above the 2D region.

    • The integral represents the volume of the solid that has a height of 1 above the given 2D region.

Connection to Past Calculus Concepts

  • Importance of recognizing calculations learned in prior calculus courses:

    • The notation remains consistent with the area calculations from Calculus II.

    • Process involves:

    • Integration from lower to upper limit: Top curve minus bottom curve.

Review of Trigonometric Integrals (Calc II Revisit)

  • Three common integrals involving trig functions:

    1. First Integral:

    • Recommended method: Substitution.

    • Substitute u=heta2u = heta^2

    • Resulting integral:

    • rac12extcos(u)rac{1}{2} ext{cos}(u)

    • Result: rac12extsin(heta2)+Crac{1}{2} ext{sin}( heta^2) + C

    1. Second Integral:

    • Use of trigonometric identity: rac1+extcos(2heta)2rac{1 + ext{cos}(2 heta)}{2}

    • Split into two integrals.

    1. Third Integral:

    • Use substitution with u=extcos(heta)u = ext{cos}( heta)

    • Resulting integral: rac13u3+C- rac{1}{3}u^3 + C

The Importance of Polar Coordinates

  • Need for polar coordinates arises when integrating over circular or symmetric regions.

    • Relation between rectangular coordinates and polar:

    • r2=x2+y2r^2 = x^2 + y^2

    • x=rextcos(heta)x = r ext{cos}( heta)

    • y=rextsin(heta)y = r ext{sin}( heta)

    • an(heta)=racyxan( heta) = rac{y}{x}

Basics of Graphing in Polar Coordinates

  • Knowledge of simple polar equations:

    • Example: r=extconstantr = ext{constant} forms a circle.

  • More complex shapes have equations like r=extsin(2heta)r = ext{sin}(2 heta) which form roses or other patterns.

Double Integrals in Polar Coordinates

  • Additional information on polar coordinates:

    • Area dAdA in polar is measured differently:

    • Area element: dA=rextdrextdhetadA = r ext{dr} ext{d} heta

    • Changes incorporate the radial increase as we extend further outward.

Setting Up Double Integrals in Polar Coordinates

  • Integral format:

    • extIntegral<br>ightarrowextlimitsofhetaextandrext{Integral} <br>ightarrow ext{limits of } heta ext{ and } r

    • Example: Limits can change from constants to functions of hetaheta.

  • Ross laws for radius and angle dictate how to approach integrations in circular domains.

Examples for Double Integrals in Polar

  • Example 1:

    • Create boundaries for theta and radius before proceeding.

    • Confirm integration strategies from previous lessons apply.

  • Example 2:

    • Domain determination is crucial given circular boundaries must be acknowledged based on geometry, such as using equations for circles.

Conclusion and Key Reminders

  • Always remember to use necessary substitutions and identities in order to compute integrals effectively.

  • Approaching integrals in polar coordinates offers advantages when dealing with certain symmetrical shapes, making understanding their applications vital in calculus.