Intermolecular Forces

Intermolecular Forces

  • Intermolecular forces arise from the charged nature of subatomic particles (electrons and protons).

  • They decrease with increasing average particle separation.

  • Intermolecular forces are responsible for the cohesiveness of materials.

  • They determine the physical properties of pure substances such as melting point, boiling point, and vapor pressure.

Intermolecular Forces vs. Phase

  • Substances that are gases at room temperature have weak intermolecular forces.

  • Substances that are condensed (liquids or solids) at room temperature have much stronger intermolecular forces.

  • If intermolecular forces did not exist, all substances would be gases, even at extremely low temperatures.

Intermolecular Forces Determine Physical State

  • The fundamental difference between states of matter is the distance between particles.

Condensed Phases

  • The solid and liquid states are referred to as condensed phases because the particles are closer together.

Intermolecular Forces and Kinetic Energy

  • The physical state of a substance at a particular temperature and pressure depends on two opposing entities:

    • The kinetic energy of the particles.

    • The strength of the intermolecular forces (potential energy) between the particles.

  • These forces are generally the attractive ones between particles in a solid, liquid, or gas.

  • Converting from one physical state to another requires the molecules to gain enough energy to overcome the intermolecular forces.

Types of Intermolecular Forces

  • Ion-dipole (strongest)

    • Applies to solutions, not pure substances.

    • The solvent must be polar.

  • Hydrogen bonding

    • Substance must be polar.

  • Dipole-dipole

    • Substance must be polar.

  • Dispersion (weakest)

    • Substance must contain both protons and electrons.

The Effect of Intermolecular Forces on Boiling Point and Melting Point

  • As the strength of intermolecular forces increases:

    • Boiling point (BP) increases.

    • Heat of vaporization (ar{ ext{vaph}}) increases.

    • Vapor pressure decreases.

    • Vapor pressure (VP) is the pressure exerted by a gas in equilibrium with its liquid phase.

    • VP and BP are inversely related.

    • Melting point (MP) increases.

    • Heat of fusion (ar{ ext{fus}}) increases.

Dipole-Dipole Force

  • Dipole-dipole interactions (forces) are found between polar molecules.

  • These forces result from the attraction (or repulsion) of the positive and negative ends of the dipole moments of polar molecules.

  • The most stable arrangement of polar molecules has the positive end of one molecule oriented toward the negative end of another molecule.

Example of Dipole-Dipole Force

  • The largest intermolecular force between molecules of CH₃Cl comes from the dipole-dipole interaction.

Heat of Vaporization and Boiling Point

  • In order for vaporization to occur, intermolecular forces must be overcome.

  • As polarity increases, the strength of dipole-dipole interactions increases, thus requiring more energy for vaporization.

  • Larger heat of vaporization (ar{ ext{vaph}}) results in higher boiling point (BP).

London Dispersion Forces

  • London dispersion forces are present between all molecules.

  • Temporary dipole moments last for fractions of a second, induced in one molecule by other nearby molecules, leading to displacement of electrons from a symmetrical arrangement.

Strength of the London Dispersion Force Increases with Surface Area

  • London dispersion forces require close surface contact between two (or more) molecules.

  • The strength of dispersion forces is roughly proportional to the surface area in contact between the molecules.

  • As surface area increases, London dispersion forces increase, leading to higher boiling points.

Dispersion Force and Boiling Point

  • For molecules with similar molecular formulas:

    • Long, skinny (unbranched) molecules have greater surface area, resulting in higher boiling points.

    • Shorter, branched molecules are more spherical and have less surface area, resulting in lower boiling points.

Strength of the London Dispersion Force Tends to Increase with Increasing Molecular Weight

  • Larger atoms have larger electron clouds, which are easier to polarize.

  • In general, as molecular weight (MW) increases, boiling point (BP) increases.

The Boiling Point of Water

  • Although boiling point tends to increase with increasing molecular weight, there are exceptions.

  • The boiling point of water is higher than expected due to strong hydrogen bonding.

Hydrogen Bonding

  • Compounds containing H-F, O-H, and/or N-H bonds exhibit hydrogen bonding:

    • Strong dipole-dipole interaction between a hydrogen atom covalently bonded to O, N, or F and a lone pair of electrons on a different O, N, or F atom.

Hydrogen Bonding is a Strong Intermolecular Force

  • Due to the large differences in electronegativity, O-H, N-H, and F-H bonds are highly polar.

  • The hydrogen atom has a strong partial positive charge, leading to a strong attraction to the nonbonding electrons on other N, O, or F atoms.

Identifying Molecules That Can Hydrogen Bond

  • The ability to form hydrogen bonds depends on the presence of the appropriate bonds in the structure of a molecule.

H-Bonding and Boiling Point

  • Impact of hydrogen bonding on boiling point (BP):

    • Hydrogen bonding leads to higher boiling points.

    • Water (H₂O) forms hydrogen bonds; H₂S cannot form H-bonds.

    • As the number of hydrogens capable of forming hydrogen bonds increases, the boiling point increases.

H-Bonding is Stronger with OH than with NH

  • Due to greater differences in electronegativity, OH forms stronger hydrogen bonds than NH.

  • Compounds with OH have higher boiling points than similar compounds with NH or NH₂. (e.g., BP of CH₃CH₂CH₂CH₂NH₂ = 77-78 °C vs. BP of CH₃CH₂CH₂CH₂OH = 117-118 °C)

Predict and Explain Relative BPs - I

  • Comparison of pairs of compounds for boiling point:

    • Identify which compound has a higher BP and explain the reasoning.

    • Evaluate relative vapor pressures.

Predict and Explain Relative BPs - II

  • Similar analysis of boiling points for different compound pairs, considering influence of molecular structure on boiling points.

Solubility and Polarity

  • Polar liquids tend to dissolve readily in polar solvents due to dipole-dipole interactions.

    • Example: Acetone and water are both polar and miscible.

  • Nonpolar liquids tend to be insoluble in polar liquids.

    • Example: Gasoline and water are immiscible.

Solubility – Like Dissolves Like

  • Nonpolar liquids tend to dissolve readily in nonpolar solvents due to dispersion forces.

    • Example: Gasoline and hexane are both nonpolar and miscible.

  • The general rule is “like dissolves like.”

Intermolecular Forces and Solubility

  • Polar compounds dissolve in polar solvents due to:

    • Dipole-dipole interactions.

    • Hydrogen bonding (sometimes).

    • Example of hydrogen bonding: between methyl amine and water.

Why Nonpolar Compounds Do Not Dissolve Appreciably in Water

  • Nonpolar compounds do not dissolve appreciably in water because they cannot break the hydrogen-bonding network that exists in water.

Solubility and the Ion-Dipole Force

  • Ionic compounds tend to dissolve in polar solvents like water due to ion-dipole forces.

  • Ion-dipole attractions cannot occur in a pure substance; they are the attractive force between an ion and the partially charged end of a polar molecule.

Solvation of Ions in Water

  • An aqueous solution of an ionic compound such as NaCl contains solvated cations (C Na⁺) and anions (C Cl⁻).

  • This solvation process highlights examples of ion-dipole forces.

Predicting Solubility in Water

  • Evaluate solubility of various solutes in water:

    • CH₃CH₂CH₃ vs. CH₃CH₂OH

    • HOCH₂CH₂CH₂CH₂OH vs. CH₃CH₂CH₂CH₂CH₂OH

    • Vitamin A vs. Vitamin C

Solubility of Large Molecules

  • When both solute and solvent contain polar and nonpolar components:

    • Estimate solubility by assessing the polar and nonpolar portions.

  • As the length of the carbon chain in alcohols (R-OH) increases, solubility in water decreases, while solubility in hexane (C₆H₁₄) increases.