Study Notes on Testing, Triangle Law of Cosines, Area of Triangles and Applied Problems

Test Information

  • Students have a test to take in the testing center this week.

  • Reminder to check the testing center’s hours of operation.

  • Testing center open on Thursday and Friday also.

  • Ensure to arrange any necessary appointments, especially if visiting Eaton's, Dare, or Currituck testing centers, which may not always be open.

  • Students can reach out via email for assistance if there are any questions about scheduling the test.

Class Schedule

  • No class is scheduled for Thursday this week.

  • Students can utilize the regular class time on Thursday to take the exam.

  • The exam duration is two hours.

Material Coverage

  • The session will cover all needed information and notes.

  • In case some content isn’t covered today, there will be an additional class at 12:30 tomorrow.

    • The video of this class will be posted for students to access later to finish the notes.

Law of Cosines (Section 7.3)

Overview

  • Continuing discussion of triangles, specifically the law of cosines.

  • Recap of previous topics on solving right triangles and the law of sines.

Cases in Triangles

  • Case 1 and Case 2 were discussed previously (Law of Sines).

  • Today focuses on:

    • Case 3: Side-Angle-Side (SAS)

    • Given: Two sides and the included angle.

    • Case 4: Side-Side-Side (SSS)

    • Given: Three sides.

Law of Cosines Definition

  • For any triangle with sides labeled a, b, and c, and respective opposite angles A, B, and C:

    • c2=a2+b22abcos(C)c^2=a^2+b^2-2\cdot a\cdot b\cdot{cos}(C)

    • b2=a2+c22accos(B)b^2=a^2+c^2-2\cdot a\cdot c\cdot{cos}(B)

    • a2=b2+c22bccos(A)a^2=b^2+c^2-2\cdot b\cdot c\cdot{cos}(A)

Solving Triangles Using the Law of Cosines

Example 1: Triangle with Given Sides and Angle
  • Given: a = 2, b = 3, angle C = 60 degrees.

  • Setup: Calculate the third side using the formula:

    • c2=a2+b22abcos(C)c^2=a^2+b^2-2\cdot a\cdot b\cdot{cos}(C)

  • Calculation steps:

    1. c2=22+32223cos(60)c^2=2^2+3^2-2\cdot2\cdot3\cdot{cos}(60)

    2. Substitute known values:

    • c2=4+92230.5c^2=4+9-2\cdot2\cdot3\cdot0.5

    • c2=136=7c^2 = 13 - 6 = 7

    1. Thus, c=7c=\sqrt7

Finding Missing Angles
  • To find angle A:

    • Using the law of cosines:

    • a2=b2+c22bccos(A)a^2=b^2+c^2-2\cdot b\cdot c\cdot{cos}(A)

    • Substitute:

    • 22=32+72237cos(A)2^2=3^2+\sqrt7^2-2\cdot3\cdot\sqrt7\cdot{cos}(A)

    • Calculate and simplify to find A.

Example 2: Triangle with All Three Sides
  • Given: a = 4, b = 3, c = 6 (Case 4).

  • Start by finding angle A, using:

    • a2=b2+c22bccos(A)a^2=b^2+c^2-2\cdot b\cdot c\cdot{cos}(A)

    • Substitute and simplify to find angle A:

    • 16=9+36236cos(A)16=9+36-2\cdot3\cdot6\cdot{cos}(A)

    • Continue to isolate and compute A.

Applied Problem

  • Scenario: A sailboat moves from Naples, Florida to Key West.

    • Distance = 150 miles at a speed of 15 miles/hour.

    • After 4 hours, the angle is off by 20 degrees.

Calculating Distances and Angles
  1. Calculate distance traveled:

    • distance=speedtime=154=60miles.{distance}={speed}\cdot{time}=15\cdot4=60_{}{ miles}.

  2. Use law of cosines to find remaining distance from Key West, drawing a triangle with appropriate side lengths and angles.

  3. Distances, remaining angles, and overall calculations yield solutions for navigation and course correction.

Triangle Area (Section 7.4)

Area Formula for Triangles

  • General formula: A=rac12imesextbaseimesextheight.A = rac{1}{2} imes ext{base} imes ext{height}.

  • In the case of SAS triangles,

    • When given sides a, b and included angle c:

    • Use A=rac12abimesextsin(c)A = rac{1}{2}ab imes ext{sin}(c)

Heron’s Formula for SSS Triangles
  • For triangles with sides a, b, c:

    • Calculate semi-perimeter, s=rac12(a+b+c)s = rac{1}{2}(a+b+c)

    • Area given by, A=extsqrt(s(sa)(sb)(sc)).A = ext{sqrt}(s(s-a)(s-b)(s-c)).

Example: Area Calculation
  1. Find area with sides 4, 5, and 7 using Heron's formula.

  2. Calculate total area needed when the painter wants to paint that triangle from a paint can coverage perspective.

Questions and Discussions

  • The instructor opened the floor for student questions and clarifications on both the law of cosines and area formulas for triangles.

  • Reminder to complete assignments, prepare for the exam, and note no lab assignments due this week.