Module 4-2
Module Information
Prepared by: Analytical Chemistry Academic Group, Institute of Chemistry, College of Science, UP Diliman
Module Leads:
C Grace Gregorio, PhD
Lilibeth Coo, PhD
Rheo Lamorena-Lim, PhD
Florenda Valera, PhD
Topic: Acid-Base Equilibria
Learning Outcomes
Recall the concept of acids and bases
Understand Bronsted-Lowry theory (conjugate acid/base pairs)
Distinguish between strong and weak acids and bases
Recall equilibrium expressions for acid/base dissociation reactions
Derive pH and pOH from the autoprotolysis of water, Kw
Calculate the pH and pOH of strong and weak acids/bases
Determine α values for polyprotic acids
Explain the preparation of buffer solutions
Apply the Henderson-Hasselbalch equation for buffer pH calculations
Explain buffer action and buffer capacity
The Nature of Acids and Bases
Definitions
Acid: Contains hydrogen and dissociates in water to yield hydronium ions (H3O+)
Base: Contains hydroxyl group and dissociates in water to yield hydroxide ions (OH–)
Neutralization Reaction: Reaction between H+ (H3O+) from acid and OH– from base, releasing energy (exothermic, ~56 kJ per mole)
Acid-Base Strength
Proton Acceptor/Donor:
Acids: Proton donors; e.g., HNO3, H2PO4. All Arrhenius acids are Bronsted-Lowry acids.
Bases: Proton acceptors; e.g., NH3, CO3 2-, F–, OH–. Not all Bronsted-Lowry bases are Arrhenius bases, but all Arrhenius bases contain OH–.
Bronsted-Lowry Theory
Highlights solvent role in acid-base behavior
Amphiprotic solvent (water) can act as both acid and base
Conjugate acid-base pairs (e.g., acid1-base1 and acid2-base2):
stronger acids have weaker conjugate bases and vice versa
Acid Strength Comparisons
Strong Acids: Completely dissociate in water
Equation Example: HA + H2O ↔ H3O+ + A-
Weak Acids: Slightly dissociate in water
Equation Example: HA + H2O ⇌ H3O+ + A-
Equilibrium Constant Expressions
Strong vs. Weak Acids
Strong Acids:
Qc = [H3O+][A-]/[HA] at equilibrium, Ka >> 1
Weak Acids:
Qc = [H3O+][A-]/[HA] at equilibrium, Ka << 1
Autoprotolysis of Water
Reaction: H2O + H2O ⇌ H3O+ + OH-
Ion-product constant (Kw = [H3O+][OH-] = 1.0 x 10^-14 at 25°C)
Calculation of pH
Strong Acids and Bases
When strong acid/base is the major supplier of H3O+:
pH = -log[H3O+]
When both acid/base and water contribute to H3O+:
Solve using Kw
For weak acids/bases, equilibrium expressions are necessary to calculate [H3O+].
Weak Monoprotic Acids
Strong concentrations can be derived if Ka × [HA] is significant compared to Kw.
Quadratic formula might be necessary for calculating low concentrations.
Buffers and Henderson-Hasselbalch Equation
Back-ground: Weak acids and conjugate bases resist drastic pH changes.
Henderson-Hasselbalch Equation:
pH = pKa + log [A-]/[HA]
Rearrangement of the Ka equilibrium expression.
Buffer Solutions
Resulting solutions from weak acid and conjugate base combinations resist pH changes.
Limited strong acid/base additions are selectively neutralized.
Summary
Understanding acid-base equilibria is based on quantitative aspects influencing H3O+ concentration.
Ka and Kb values: Offer insight into acid/base strength.
Auto-protolysis of water is crucial in equilibria contexts.
The strength of conjugate bases is inversely related to their weak acid counterparts.
Buffers mixture resist abrupt pH changes, highlighting the importance of equilibrium principles.