Trigonometric Identities: Double and Half Angle Formulas

Trigonometric Identities

  • Identities are formulas used for calculating different trigonometric values.
  • The lecture focuses on double angle and half angle identities.

Double Angle Formulas

  • These formulas are derived from the sum identities when both angles are the same (a=ba = b).
Sine of Double Angle
  • Starting with the sum identity: sin(a+b)=sin(a)cos(b)+cos(a)sin(b)\sin(a + b) = \sin(a)\cos(b) + \cos(a)\sin(b)
  • If a=ba = b, then: sin(2a)=sin(a)cos(a)+sin(a)cos(a)=2sin(a)cos(a)\sin(2a) = \sin(a)\cos(a) + \sin(a)\cos(a) = 2\sin(a)\cos(a)
Cosine of Double Angle
  • Starting with the sum identity: cos(a+b)=cos(a)cos(b)sin(a)sin(b)\cos(a + b) = \cos(a)\cos(b) - \sin(a)\sin(b)
  • If a=ba = b, then: cos(2a)=cos2(a)sin2(a)\cos(2a) = \cos^2(a) - \sin^2(a)
  • This form is similar to the Pythagorean identity.
Tangent of Double Angle
  • Starting with the sum identity: tan(a+b)=tan(a)+tan(b)1tan(a)tan(b)\tan(a + b) = \frac{\tan(a) + \tan(b)}{1 - \tan(a)\tan(b)}
  • If a=ba = b, then: tan(2a)=2tan(a)1tan2(a)\tan(2a) = \frac{2\tan(a)}{1 - \tan^2(a)}

Alternative Forms of the Cosine Double Angle Formula

  • Using the Pythagorean identity: sin2(a)+cos2(a)=1\sin^2(a) + \cos^2(a) = 1
Version 1
  • Solve for cos2(a)\cos^2(a): cos2(a)=1sin2(a)\cos^2(a) = 1 - \sin^2(a)
  • Substitute into cos(2a)=cos2(a)sin2(a)\cos(2a) = \cos^2(a) - \sin^2(a):
    cos(2a)=(1sin2(a))sin2(a)=12sin2(a)\cos(2a) = (1 - \sin^2(a)) - \sin^2(a) = 1 - 2\sin^2(a)
Version 2
  • Solve for sin2(a)\sin^2(a): sin2(a)=1cos2(a)\sin^2(a) = 1 - \cos^2(a)
  • Substitute into cos(2a)=cos2(a)sin2(a)\cos(2a) = \cos^2(a) - \sin^2(a):
    cos(2a)=cos2(a)(1cos2(a))=2cos2(a)1\cos(2a) = \cos^2(a) - (1 - \cos^2(a)) = 2\cos^2(a) - 1

Half Angle Formulas

  • Derived by manipulating the alternative forms of the cosine double angle formula.
Cosine of Half Angle
  • Starting with cos(2a)=2cos2(a)1\cos(2a) = 2\cos^2(a) - 1
  • Solve for cos(a)\cos(a):
    • Add 1: cos(2a)+1=2cos2(a)\cos(2a) + 1 = 2\cos^2(a)
    • Divide by 2: 1+cos(2a)2=cos2(a)\frac{1 + \cos(2a)}{2} = \cos^2(a)
    • Take the square root: cos(a)=±1+cos(2a)2\cos(a) = \pm\sqrt{\frac{1 + \cos(2a)}{2}}
  • Replace aa with θ2\frac{\theta}{2}: cos(θ2)=±1+cos(θ)2\cos(\frac{\theta}{2}) = \pm\sqrt{\frac{1 + \cos(\theta)}{2}}
Sine of Half Angle
  • Starting with cos(2a)=12sin2(a)\cos(2a) = 1 - 2\sin^2(a)
  • Solve for sin(a)\sin(a):
    • Subtract 1: cos(2a)1=2sin2(a)\cos(2a) - 1 = -2\sin^2(a)
    • Divide by -2: 1cos(2a)2=sin2(a)\frac{1 - \cos(2a)}{2} = \sin^2(a)
    • Take the square root: sin(a)=±1cos(2a)2\sin(a) = \pm\sqrt{\frac{1 - \cos(2a)}{2}}
  • Replace aa with θ2\frac{\theta}{2}: sin(θ2)=±1cos(θ)2\sin(\frac{\theta}{2}) = \pm\sqrt{\frac{1 - \cos(\theta)}{2}}

Example: Finding cos(22.5)\cos(22.5^{\circ})

  • Recognize that 22.5=45222.5^{\circ} = \frac{45^{\circ}}{2}
  • Use the half-angle formula for cosine: cos(22.5)=cos(452)=±1+cos(45)2\cos(22.5^{\circ}) = \cos(\frac{45^{\circ}}{2}) = \pm\sqrt{\frac{1 + \cos(45^{\circ})}{2}}
  • Since 22.522.5^{\circ} is in the first quadrant, cosine is positive.
  • cos(45)=22\cos(45^{\circ}) = \frac{\sqrt{2}}{2}
  • Substitute: cos(22.5)=1+222\cos(22.5^{\circ}) = \sqrt{\frac{1 + \frac{\sqrt{2}}{2}}{2}}
  • Simplify:
    • cos(22.5)=2+222=2+24=2+22\cos(22.5^{\circ}) = \sqrt{\frac{\frac{2 + \sqrt{2}}{2}}{2}} = \sqrt{\frac{2 + \sqrt{2}}{4}} = \frac{\sqrt{2 + \sqrt{2}}}{2}

Verification with Calculator

  • The example demonstrates how to use the half-angle formulas and verifies the result using a calculator.

Summary

  • The lecture covered double angle and half angle formulas for sine, cosine, and tangent.
  • These formulas are useful for finding trigonometric values of angles that are multiples or fractions of known angles.