Study Notes on Systems of Linear Equations

Systems of Linear Equations in Two Variables

1. Solving Systems Using Substitution or Addition/Elimination Method

  • Objective: Solve the following systems of equations. If a system does not have one unique solution, classify it as inconsistent or dependent.
(a) Solve the following system:
  • Equations:
    • −5(x+y)=9+2y-5(x + y) = 9 + 2y
    • 6y−2=10−7x6y - 2 = 10 - 7x
  • Method: Choose either substitution or elimination.
  • Steps to solve:
    • Rearrange equations if necessary.
    • Use substitution or elimination to find xx and yy.
  • Solution Check: Verify if there is one unique solution or if it is inconsistent.
(b) Solve the following system:
  • Equations:
    • 3x+y=63x + y = 6
    • x+13y=2x + \frac{1}{3}y = 2
  • Method: Choose either substitution or elimination.
  • Steps to solve:
    • Convert x+13y=2x + \frac{1}{3}y = 2 to a simpler form for substitution or elimination.
  • Solution Check: Determine the nature of the solution.
(c) Solve the following system:
  • Equations:
    • 3x−4y=93x - 4y = 9
    • 2x+9y=22x + 9y = 2
  • Method: Choose either substitution or elimination.
  • Steps to solve:
    • Rearrange both equations, if needed, for clear substitution or elimination.
  • Solution Check: Identify if the equations yield a unique solution or classification of the system.
(d) Solve the following system:
  • Equations:
    • −4x−8y=2-4x - 8y = 2
    • 2x=8−4y2x = 8 - 4y
  • Method: Choose either substitution or elimination.
  • Steps to solve:
    • Rearrange the second equation for clear substitution.
  • Solution Check: Confirm solution existence and classify.
(e) Solve the following system:
  • Equations:
    • 0.25x−0.04y=0.240.25x - 0.04y = 0.24
    • 0.15x−0.12y=0.120.15x - 0.12y = 0.12
  • Method: Choose either substitution or elimination.
  • Steps to solve:
    • Rewrite the equations if necessary to facilitate solving.
  • Solution Check: Establish if unique or dependent solutions exist.

2. Setting Up and Solving Linear Equations in Context

  • Task: Create and resolve systems of equations based on contextual scenarios. Clearly define all variables involved.
(a) Mixing Saline Solutions
  • Scenario: Walt wants to mix:
    • A 30% saline solution
    • A 10% saline solution
  • Goal: Create 200 mL of a 12% saline solution.
  • **Variables: **
    • Let xx = volume (in mL) of the 30% saline solution
    • Let yy = volume (in mL) of the 10% saline solution
  • Equations Setup:
    • x+y=200x + y = 200
    • 0.30x+0.10y=0.12(200)0.30x + 0.10y = 0.12(200)
  • Method: Solve the system using substitution or elimination to find values of xx and yy.
(b) Fuel Consumption for a Sedan
  • Scenario: Chris drives:
    • 12 miles per gallon (mpg) in the city
    • 18 mpg on the highway
  • Total Distance: 420 miles
  • Total Fuel Used: 26 gallons
  • Variables:
    • Let cc = miles driven in the city
    • Let hh = miles driven on the highway
  • Equations Setup:
    • c+h=420c + h = 420
    • $ rac{c}{12} + rac{h}{18} = 26$
  • Method: Solve the system to determine the miles driven in both city and highway.
(c) Speed of a Fishing Boat
  • Scenario: A boat travels:
    • 44 mi north with the current in 2 hours
    • 56 mi south against the current in 4 hours
  • Variables:
    • Let bb = speed of the boat in still water (in mph)
    • Let cc = speed of the current (in mph)
  • Equations Setup:
    • Speed with current: b+c=442=22b + c = \frac{44}{2} = 22
    • Speed against current: b−c=564=14b - c = \frac{56}{4} = 14
  • Method: Solve the system of equations to determine both the speed of the boat and the speed of the current.

3. Challenge Problem

  • Task: Solve for xx and yy given the following system:
  • Equations:
    • 1x+2y=1\frac{1}{x} + 2y = 1
    • −1x+4y=−7-\frac{1}{x} + 4y = -7
  • Hint: Use substitutions:
    • Let u=1xu = \frac{1}{x} and v=1yv = \frac{1}{y} to rewrite the equations.
  • Solution Steps:
    • Substitute uu and vv into the equations and solve for uu and vv first, then revert back to xx and yy.