Comprehensive Study Notes on Arithmetic Progressions
Introduction to Patterns and Arithmetic Progressions
Patterns in Nature: Many phenomena in nature follow specific mathematical patterns, including the petals of a sunflower, the holes of a honeycomb, the grains on a maize cob, the spirals on a pineapple, and the spirals on a pine cone.
Examples of Real-Life Patterns:
- Salary Growth: Reena's starting monthly salary is 8000INR with an annual increment of 500INR. Her salary sequence for the first few years is: 8000,8500,9000,...
- Ladder Rungs: A ladder's rungs decrease uniformly by 2cm from bottom to top. If the bottom rung is 45cm, the lengths are: 45,43,41,39,37,35,33,31
- Savings Scheme: An investment of 8000INR grows to 45 times its value every 3years. The maturity amounts after 3,6,9 and 12years are: 10000,12500,15625,19531.25
- Unit Squares: The number of unit squares in larger squares with sides 1,2,3,...units is: 12,22,32,...
- Money Box Savings: Shakila puts 100INR into a money box on her daughter's 1st birthday and increases the amount by 50INR every year: 100,150,200,250,...
- Rabbit Population (Fibonacci pattern): Pairs of rabbits that do not produce in the first month but produce a new pair every month thereafter result in the sequence: 1,1,2,3,5,8
Term: Each number in a list follows a certain rule and is called a term.
Definition of Arithmetic Progression (AP): An arithmetic progression is a list of numbers in which each term is obtained by adding a fixed number to the preceding term, except for the first term.
Common Difference (d): The fixed number added to each term is called the common difference. It can be positive, negative, or zero.
Notation:
- First term: a1 (or simply a)
- Second term: a2
- nth term: an
- Common Difference: d
- Relation: a2−a1=a3−a2=...=an−an−1=d
General Form of an AP: The sequence is represented as:
a,a+d,a+2d,a+3d,...
Types of APs:
- Finite AP: Contains a finite number of terms and always has a last term. Examples include student heights in a queue or temperatures for a single week.
- Infinite AP: Does not have a last term and continues indefinitely. Examples include the set of natural numbers 1,2,3,...
The nth Term of an Arithmetic Progression
Derivation of the Formula:
- Let the first term be a and the common difference be d.
- a1=a
- a2=a+d=a+(2−1)d
- a3=a+2d=a+(3−1)d
- a4=a+3d=a+(4−1)d
General Term Formula: The nth term an of an AP is given by:
an=a+(n−1)d
Last Term (l): If there are m terms in an AP, am represents the last term, sometimes denoted as l.
Identifying an AP: To determine if a list is an AP, calculate d=ak+1−ak for various values of k. If the difference is not constant, it is not an AP.
Worked Examples: nth Term
Example 3: For the AP 2,7,12,..., find the 10th term.
- a=2
- d=7−2=5
- n=10
- a10=2+(10−1)×5=2+45=47
Example 4: Which term of the AP 21,18,15,... is −81? Is any term 0?
- −81=21+(n−1)(−3)→−102=−3(n−1)→34=n−1→n=35
- For an=0: 0=21+(n−1)(−3)→−21=−3(n−1)→7=n−1→n=8
- Answer: The 35th term is −81 and the 8th term is 0.
Example 7: How many two-digit numbers are divisible by 3?
- List: 12,15,18,...,99
- a=12,d=3,an=99
- 99=12+(n−1)3→87=3(n−1)→29=n−1→n=30
Example 8: Find the 11th term from the last term of the AP: 10,7,4,...,−62.
- Method 1: Find total terms (n=25), then calculate the 15th term from the start.
- Method 2: Reverse the AP: −62,−59,−56,...
- a=−62,d=3,n=11
- a11=−62+(11−1)×3=−62+30=−32
Sum of First n Terms of an AP
Gauss's Method: To sum numbers from 1 to 100, Gauss wrote the sum twice (once in reverse) and added them to find constant sums of 101.
S=1+2+...+99+100S=100+99+...+2+12S=100×101→S=5050
General Sum Formulas:
- Standard formula: S=2n[2a+(n−1)d]
- Using last term (an): S=2n(a+an)
- Using terminal term (l): S=2n(a+l)
Relationship between an and Sn:an=Sn−Sn−1
Worked Examples: Summation
Example 11: Sum of first 22 terms of 8,3,−2,...
- a=8,d=−5,n=22
- S22=222[2(8)+(22−1)(−5)]=11[16−105]=11(−89)=−979
Example 13: How many terms of 24,21,18,... must be taken for a sum of 78?
- 78=2n[48+(n−1)(−3)]→156=n(51−3n)→3n2−51n+156=0
- n2−17n+52=0→(n−4)(n−13)=0
- Two answers: n=4 or n=13. This happens because terms from the 5th to the 13th cancel each other out to zero.
Sum of first n positive integers:Sn=2n(n+1)
Applications and Exercise Highlights
- Divisibility: To find the sum of the first 40 positive integers divisible by 6, use a=6,d=6,n=40.
- Compound Interest vs. Simple Interest: Simple interest sequences (80,160,240,...) form an AP, whereas compound interest sequences do not.
- Coordinate/Geometry Applications:
- Spiral Length: A spiral made of 13 semicircles with increasing radii (0.5,1.0,1.5,...). Total length is the sum of circumferences l=π(r1+r2+...+r13).
- Log Stacking: 20 logs in the bottom row, 19 in next, etc. Total logs 200. Solve for n in 200=2n[2(20)+(n−1)(−1)].
- Potato Race: Distance for first potato is 2×5, second is 2×(5+3). The sequence is 10,16,22,... for 10 terms.
Summary of Key Points
- Definition: Each term is obtained by adding d to the previous one.
- General Term: an=a+(n−1)d
- Sum of n Terms: S=2n[2a+(n−1)d] or S=2n(a+l)
- Arithmetic Mean: If a,b,c are in AP, then b=2a+c, where b is the arithmetic mean of a and c.