Essential Mathematics: Geometry, Scientific Notation, Equations, and Inequalities

Geometric Area Calculations

  • Triangle Area Formula:
    • Area=12×base×height\text{Area} = \frac{1}{2} \times \text{base} \times \text{height}
  • Calculation Procedure:
    • Identify the base and corresponding perpendicular height (e.g., base = 22 cm22\,\text{cm}, height = 6 cm6\,\text{cm}, ignoring extraneous side lengths such as 14 cm14\,\text{cm}).
    • Substitute into the formula: Area=12×22 cm×6 cm=11 cm×6 cm=66 cm2\text{Area} = \frac{1}{2} \times 22\,\text{cm} \times 6\,\text{cm} = 11\,\text{cm} \times 6\,\text{cm} = 66\,\text{cm}^2.

Scientific and Standard Notation

  • Scientific Notation Structure:
    • Expressed in the form a×10na \times 10^n, where 1≤∣a∣<101 \le |a| < 10 and nn is an integer.
  • Converting Standard Form to Scientific Notation:
    • Shift the decimal point to create a coefficient aa such that 1≤∣a∣<101 \le |a| < 10.
    • Moving the decimal point to the right yields a negative exponent (n<0n < 0):
    • 0.00856=8.56×10−30.00856 = 8.56 \times 10^{-3} (shifted 33 places right)
    • 0.000896 moles per L=8.96×10−4 moles per L0.000896\,\text{moles per L} = 8.96 \times 10^{-4}\,\text{moles per L} (shifted 44 places right)
    • Moving the decimal point to the left yields a positive exponent (n>0n > 0):
    • 17,200,000 square miles=1.72×107 square miles17,200,000\,\text{square miles} = 1.72 \times 10^7\,\text{square miles} (shifted 77 places left)
  • Converting Scientific Notation to Standard Form:
    • Positive exponent: Shift decimal point right by nn places, filling empty positions with zeros:
    • 9.9×103 pounds=9900 pounds9.9 \times 10^3\,\text{pounds} = 9900\,\text{pounds}
    • Negative exponent: Shift decimal point left by ∣n∣|n| places, filling empty positions with leading zeros:
    • 4.1×10−2 seconds=0.041 seconds4.1 \times 10^{-2}\,\text{seconds} = 0.041\,\text{seconds}

Solving Literal and Multi-Step Linear Equations

  • Literal Equations:
    • Treat non-target variables as constants and isolate the target variable using inverse operations in reverse order of operations (PEMDAS/BODMAS).
    • Solving K=5r−sK = 5r - s for rr:
    • Add ss to both sides: K+s=5rK + s = 5r
    • Divide both sides by 55: r=K+s5r = \frac{K + s}{5}
  • Multi-Step Equations with Distribution:
    • Distribute coefficients into parentheses and combine like terms on each side before isolating the variable.
    • Infinite Solutions (Identity):
    • 4(y+1)−7=3(y−1)+y4(y + 1) - 7 = 3(y - 1) + y
    • Distribute: 4y+4−7=3y−3+y4y + 4 - 7 = 3y - 3 + y
    • Combine like terms: 4y−3=4y−34y - 3 = 4y - 3
    • Subtract 4y4y: −3=−3-3 = -3
    • A true numerical statement indicates all real numbers are solutions.
    • Unique Solution:
    • 3(u−2)−4u=2(u−9)3(u - 2) - 4u = 2(u - 9)
    • Distribute: 3u−6−4u=2u−183u - 6 - 4u = 2u - 18
    • Combine like terms: −u−6=2u−18-u - 6 = 2u - 18
    • Isolate variable and constants: −6=3u−18  ⟹  12=3u-6 = 3u - 18 \implies 12 = 3u
    • Divide by 33: u=4u = 4

Graphing Linear and Compound Inequalities on a Number Line

  • Boundary Circle Rules:
    • Open Circle: Used for strict inequalities (<< or >>) to show the boundary value is excluded.
    • Closed Circle: Used for non-strict inequalities (≤\le or ≥\ge) to show the boundary value is included.
  • Single Inequalities:
    • a≤−7a \le -7: Closed circle at −7-7, shaded ray extending to the left.
    • y<−8y < -8: Open circle at −8-8, shaded ray extending to the left.
  • Compound "And" Inequalities (Intersection):
    • Requires values to satisfy both conditions simultaneously; represented as a continuous segment between two endpoints.
    • x>−3 and x≤7x > -3 \text{ and } x \le 7: Open circle at −3-3, closed circle at 77, connected by a line segment.
    • x<7 and x≥5x < 7 \text{ and } x \ge 5 (expressed as 5≤x<75 \le x < 7): Interval [5,7)[5, 7), graphed with a closed circle at 55, an open circle at 77, and a connecting line segment.
  • Compound "Or" Inequalities (Union):
    • Requires values to satisfy at least one condition; represented as two disjoint rays pointing in opposite directions.
    • x>8 or x<1x > 8 \text{ or } x < 1: Open circle at 11 with a ray to the left; open circle at 88 with a ray to the right.
    • x≤−4 or x>8x \le -4 \text{ or } x > 8: Closed circle at −4-4 with a ray to the left; open circle at 88 with a ray to the right.