MATH HL 1

SIXTH FORM ENTRANCE TEST - MATHEMATICS Higher Level

Test Information

  • Test Type: Six Form Entrance Test for entry into Lower Sixth (Year 12) in September 2025.

  • Name and School: Fields provided for candidates to input their name (in capitals) and school.

Additional Courses Studied
  • Candidates are required to circle if they have studied or are currently studying any of the following courses:

    • Additional Mathematics OCR

    • Additional Mathematics CIE

    • Further Mathematics AQA

    • Further Pure Mathematics Edexcel

    • MYP Extended

Exam Details
  • Reading Time: 5 minutes

  • Exam Time: 40 minutes

  • Equipment Needed: Pen, pencil, eraser

  • Calculator Policy: Calculators are NOT allowed.

  • Structure: The exam consists of four questions, each covering different topics.

  • Marks Distribution: 15 marks awarded per question.

  • Scoring Policy: Correct answers with no or poor workings will receive zero marks. Final mark based on the two highest-scored questions.

  • Advice: Candidates are not expected to finish all questions, thus, advised to complete only two full questions.

QUESTION 1: FACTORISATION AND EQUATIONS

a. Factorisation of Expressions
  1. Factorise the expression:
    6x211x+36x^2 - 11x + 3

    • Marks: [2 marks]

  2. Factorise the expression:
    10x221xy+9y210x^2 - 21xy + 9y^2

    • Marks: [3 marks]

b. Solving an Equation
  • Solve the following equation by squaring both sides: extx+22=2+xext{√}x + 22 = 2 + x

    • Marks: [4 marks]

c. Solving Simultaneous Equations
  • Solve the simultaneous equations:

    1. 4x+3y=494x + 3y = 49

    2. ext5x+ext5y=ext17x+7yext{√}5x + ext{√}5y = ext{√}17x + 7y

    • Hint: Consider methods used in parts a. and b.

    • Marks: [6 marks]

QUESTION 2: SIMILARITY

a. Triangle Similarity Explanation
  • Explain why triangles ABC and DEC are similar, given that AB and DE are parallel.

    • Marks: [1 mark]

b. Calculating Length in Similar Triangles
  • Find the length of xx in similar triangles where one side measures 6 cm, another is xx cm, and a third side measures 5 cm.

    • Marks: [2 marks]

c. Expression for Height
  • Write an expression for height hh in terms of xx and yy for similar triangles.

    • Given triangle dimensions: 6 cm, xx cm, and yy cm.

    • Marks: [2 marks]

d. Finding Height in Right-Angled Triangles
  • Using similar triangles, find the height hh in a diagram where the triangles are right-angled with a base of 60 cm and height 20 cm.

    • Marks: [5 marks]

e. Value Calculation in a Right Triangle
  • In the right triangle below, find the value of x+y+zx + y + z. ![Diagram not provided in transcript]

    • Marks: [5 marks]

QUESTION 3: SURDS AND GEOMETRY

a. Expansion and Simplification
  • Expand and simplify: (3+5ext2)2(3 + 5 ext{√}2)^2

    • Marks: [2 marks]

b. Finding Square Root of an Expression
  • By letting: 43+24ext3=(a+bext3)243 + 24 ext{√}3 = (a + b ext{√}3)^2

    • Find ext(43+24ext3)ext{√}(43 + 24 ext{√}3) where aa and bZ+b ∈ ℤ^+.

    • Marks: [5 marks]

c. Side Length of Triangle in Circle
  • The circles below have a radius of 1 cm contained within equilateral triangles.

    • Find the exact length of one side of the triangle in pattern 1.

    • Note: You may use the fact that an(30°)=rac1ext3an(30°) = rac{1}{ ext{√}3}.

    • Marks: [2 marks]

d. Area of Triangle
  • Find the area of the triangle in pattern 3.

    • Marks: [6 marks]

QUESTION 4: SEQUENCES

Note on Arithmetic Sequence
  • Formula for the sum of an arithmetic sequence:
    S<em>n=racn2[2u</em>1+(n1)d]S<em>n = rac{n}{2} [2u</em>1 + (n - 1)d]

Sequence Terms
  1. Given that:

    • T1=1T_1 = 1

    • T2=1+2=3T_2 = 1 + 2 = 3

    • T3=1+2+3=6T_3 = 1 + 2 + 3 = 6

    • Write down the next two terms T<em>4T<em>4 and T</em>5T</em>5.

    • Marks: [2 marks]

b. General Expression for Sequence
  • By considering the sum to nn terms of an arithmetic sequence, find a general expression for TnT_n.

    • Marks: [2 marks]

c. Finding Value of S17
  • Find the value of S17S_{17} given that:

    • S1=1S_1 = 1

    • S2=2+3S_2 = 2 + 3

    • S3=4+5+6S_3 = 4 + 5 + 6

    • Marks: [5 marks]

d. General Expression for Sn
  • Find a general expression for S<em>nS<em>n given that it is of the form: a</em>n3+b<em>n2+c</em>n+da</em>n^3 + b<em>n^2 + c</em>n + d

    • Hint:

    • For n=1n = 1, we get: a+b+c+d=1a + b + c + d = 1.

    • For n=2n = 2, we get: 8a+4b+2c+d=58a + 4b + 2c + d = 5.

    • Marks: [6 marks]