Aqueous Solutions Notes
Module 13: Aqueous Solutions Overview
- Solution: A homogeneous mixture of 2 or more substances.
- Solute: Part of a solution present in lower concentration.
- Solvent: Part of the solution present in higher concentration.
- Aqueous solution: A solution where water is the solvent.
Concentration
- Definition: Relative amount of a given solution component.
- Dilute vs. Concentrated: Terms describing low vs. high concentration.
Preparing a Solution
- Example: Preparing a solution of Cobalt(II) chloride dihydrate (CoCl2.2H₂O).
- Weigh out the required mass of solute (10.0 g).
- Add a portion of the solvent to a volumetric flask.
- Swirl to dissolve the solute.
- Add additional solvent to reach the desired volume (500 mL).
Dissociation
- Dissociation: The process where ionic compounds break into ions when dissolved in water.
- Example with NaCl:
- NaCl(s) → Na⁺(aq) + Cl⁻(aq)
- Resulting solutions contain ions and are classified as strong electrolytes.
Concentration Units
- Molarity (M): Molarity is the number of moles of solute per liter of solution.
- Formula: M = moles of solute / liters of solution.
Practice Problems
Example 1: Calculate the molarity of a solution when 0.122 mol of KI is dissolved in 115 mL of water.
Molarity = 0.122 mol / 0.115 L = 1.06 M KI
Example 2: Calculate the molarity of a solution prepared by dissolving 5.7 g NaF (molar mass = 42 g/mol) in 2.0 L of water.
Steps:
- Calculate moles: 5.7 g / 42 g/mol = 0.136 mol.
- Molarity = 0.136 mol / 2.0 L = 0.068 M.
Example 3: Determine the mass required for 155.0 mL of a 1.30 M Cu(NO3)2 solution.
Steps:
- Calculate moles: 0.1550 L × 1.30 mol/L = 0.2015 mol.
- Convert to grams: 0.2015 mol × 187.56 g/mol = 37.8 g.
Dilution of Solutions
- Dilution: Process that reduces the concentration of a solution by adding solvent.
- Stock solution: A concentrated solution prepared for dilution.
- Dilution Equation: C1V1 = C2V2 (where C is concentration and V is volume).
Concentration Units Variations
- Mass Percent: Ratio of solute mass to solution mass expressed as a percentage.
- Parts per Million (ppm) and Parts per Billion (ppb): Used for very low concentrations.
- ppm = (mass of solute / mass of solution) × 10^6
- ppb = (mass of solute / mass of solution) × 10^9
Additional Practice Problems
- Mass Percent Calculation: Calculate how much water must be added to prepare an 8.15% by mass solution from 5.00 g of urea.
- Finding Molarity: If a hazardous chemical bottle is labeled 20.2% by mass of HCl with a density of 1.096 g/mL, calculate its molarity.
Summary of Key Formulas
- Molarity (M) = moles of solute / volume of solution (L)
- Mass Percent (%) = (mass of solute / mass of solution) × 100%
- Volume Percent (%) = (volume of solute / volume of solution) × 100%
- ppm = (mass of solute / mass of solution) × 10^6
- ppb = (mass of solute / mass of solution) × 10^9
Tips for Exam Preparation
- Focus on understanding concepts of solute, solvent, and solution.
- Practice calculating molarity and understanding dilution.
- Familiarize yourself with various units of concentration and how to convert between them.