3.6 The Chain Rule - Calculus Volume 1

Learning Objectives

  • 3.6.1 State the chain rule for the composition of two functions.
  • 3.6.2 Apply the chain rule together with the power rule.
  • 3.6.3 Apply the chain rule and the product/quotient rules correctly in combination when both are necessary.
  • 3.6.4 Recognize the chain rule for a composition of three or more functions.
  • 3.6.5 Describe the proof of the chain rule.

Introduction to the Chain Rule

  • Techniques already learned include differentiating basic functions, sums, differences, products, quotients, and constant multiples.
  • These techniques do not cover differentiating compositions of functions such as:
    • h(x)=f(g(x))h(x) = f(g(x))

Deriving the Chain Rule

  • Concept: For a function that is a composition, the derivative is not simply the sum of derivatives.
  • Chain Rule: The derivative of a composite function is given by:
    (f(g(x)))=f(g(x))imesg(x)(f(g(x)))' = f'(g(x)) imes g'(x)
  • Contextual Example: If we consider how one variable's change affects another in the chain:
    • If xx changes, g(x)g(x) changes, leading to a subsequent change in f(g(x))f(g(x)).
    • Recognize that the derivative of g(x)g(x) contributes to the final derivative as well.

Formal Derivative Expression

  • Set up limit for derivative:
    h(x)=h(x+exth)h(x)exthh'(x) = \frac{h(x + ext{h}) - h(x)}{ ext{h}}
  • Enhance by multiplying and dividing by gg to derive:
    • Take limit as xx approaches a specific point, leading to:
      extExamplelimitsetup:extasxoa:h(x)=ext[evaluatedexpression]extaext{Example limit setup: } ext{as } x o a: h'(x) = \frac{ ext{[evaluated expression]}}{ ext{a}}
    • This concept illustrates that the first term in the product is the derivative of the outside function:
  • Acknowledgment of using trigonometric derivatives as examples (e.g., extsin(x)ext{sin}(x))

General Case of the Chain Rule

  • The Chain Rule: Let ff and gg be functions where:
    • For all xx in the domain of gg for which both ff and gg are differentiable:
      (f(g(x)))=f(g(x))imesg(x)(f(g(x)))' = f'(g(x)) imes g'(x)

Applying the Chain Rule

Steps for Differentiating Using the Chain Rule:

  1. Identify the outer function, ff, and the inner function, gg.
  2. Differentiate the outer function ff, then evaluate it at the inner function g(x)g(x).
  3. Differentiate the inner function, gg.
  4. Multiply the derivatives obtained:
    (f(g(x)))=f(g(x))imesg(x)(f(g(x)))' = f'(g(x)) imes g'(x)

Chain Rule and Power Rule Combined

  • Application where functions take form: f(g(x))=(g(x))nf(g(x)) = (g(x))^n
    • Utilizing Power Rule results in:
      $$ h